a.
To find out which gym is less expensive if one plan to take 4 aerobics classes each month.
a.
![Check Mark](/static/check-mark.png)
Answer to Problem 23PTTS
Gym A is more expensive.
Explanation of Solution
Given:
The annual fee of Gym A is given = $540.
The annual fee of Gym B is given = $360.
The Class fee of Aerobics Each time of Gym A = $3.
The Class fee of Aerobics Each time of Gym B = $5.
Concept Used:
The concept of forming and solving inequality is used.
Calculation:
Number of Classes of Aerobics one takes each month at = 4
Number of Classes in a year = 4 x 12 =48
Cost of Each Aerobics at Gym A = $3 x 48 = $144
Total Cost of a year at Gym A = $144 + $540 = $684.
Cost of Each Aerobics at Gym B = $5 x 48 = $240
Total Cost of a year at Gym B = $360 + $240 = $600
Hence, cost of a year at Gym A is more than cost of a year at Gym B.
Conclusion:
Thus, Gym A is more expensive.
b.
To write and solve an inequality to determine the number of aerobics class 1 year at Gym A is less than that at Gym B.
b.
![Check Mark](/static/check-mark.png)
Answer to Problem 23PTTS
The inequality is x<90. So, 91 Aerobics Classes at Gym A is less than that at Gym B.
Explanation of Solution
Given:
The annual fee of Gym A is given = $540.
The annual fee of Gym B is given = $360.
The Class fee of Aerobics Each time of Gym A = $3.
The Class fee of Aerobics Each time of Gym B = $5.
The cost of 1 year at Gym A is less than Gym B.
Concept Used:
The concept of forming and solving inequality is used.
Calculation:
Let the number of Aerobics Classes in a year =
Cost of Each Aerobics at Gym A = $3
Total Cost of a year at Gym A =
Cost of Each Aerobics at Gym B = $5
Total Cost of a year at Gym B =
The cost of 1 year at Gym A is less than Gym B.
Take like Terms on the same side and solve.
Conclusion:
Thus, for 91 aerobics classes, Gym A is cheaper than Gym B.
c.
To find how many aerobics classes one should average each month so that the total cost for 1 year at gym B is less than that at gym A.
c.
![Check Mark](/static/check-mark.png)
Answer to Problem 23PTTS
For 22 aerobics classes each month, Gym B is cheaper than Gym A.
Explanation of Solution
Given:
The annual fee of Gym A is given = $540.
The annual fee of Gym B is given = $360.
The Class fee of Aerobics Each time of Gym A = $3.
The Class fee of Aerobics Each time of Gym B = $5.
The cost of 1 year at Gym B is less than Gym A.
Concept Used:
The concept of forming and solving inequality is used.
Calculation:
Let the number of Aerobics Classes in a year =
Cost of Each Aerobics at Gym A = $3
Total Cost of a year at Gym A =
Cost of Each Aerobics at Gym B = $5
Total Cost of a year at Gym B =
The cost of 1 year at Gym B is less than Gym A.
Take like Terms on the same side and solve.
Average classes each month =
Conclusion:
Thus, for 22 aerobics classes each month, Gym B is cheaper than Gym A.
Chapter 3 Solutions
Holt Mcdougal Larson Pre-algebra: Common Core Practice Workbook
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