Chapter 3, Problem 23PS

a.

Explanation of Solution

Given: The values of the variables, x = 2, y = 3, and z = 1, are assigned to the expression, x+2 / 6+y.

To find: The result of the expression, x+2 / 6+y, if x = 2, y = 3, and z = 1 .

Solution:

Precedence of the operator defines the grouping of words within an expression and defines how to interpret an expression. Many operators precede over others; for example, the operator of multiplication has a greater precedence than the operator of addition...

b.

Explanation of Solution

Given: The values of the variables, x = 2, y = 3, and z = 1, are assigned to the expression, y-3 * z+2.

To find: The result of the expression, y-3 * z+2, if x = 2, y = 3, and z = 1 .

Solution:

Precedence of the operator defines the grouping of words within an expression and defines how to interpret an expression. Many operators precede over others; for example, the operator of multiplication has a greater precedence than the operator of addition...

c.

Explanation of Solution

Given: The values of the variables, x = 2, y = 3, and z = 1, are assigned to the expression, z – (x+z) % 2 + 4.

To find: The result of the expression, z – (x+z) % 2 + 4, if x = 2, y = 3, and z = 1 .

Solution:

Precedence of the operator defines the grouping of words within an expression and defines how to interpret an expression. Many operators precede over others; for example, the operator of multiplication has a greater precedence than the operator of addition...

d.

Explanation of Solution

Given: The values of the variables, x = 2, y = 3, and z = 1, are assigned to the expression, x-2*(3+z)+y.

To find: The result of the expression, x-2*(3+z)+y, if x = 2, y = 3, and z = 1 .

Solution:

Precedence of the operator defines the grouping of words within an expression and defines how to interpret an expression. Many operators precede over others; for example, the operator of multiplication has a greater precedence than the operator of addition...

e.

Explanation of Solution

Given: The values of the variables, x = 2, y = 3, and z = 1, are assigned to the expression, y++ + z-- + x++.

To find: The result of the expression, y++ + z-- + x++, if x = 2, y = 3, and z = 1 .

Solution:

Prefix operation like ‘++var’ or ‘--var', having property that the value is first incremented or decremented by 1, then it returns the value...