(a)
The interest rate for an amount of $2000 borrowed, which has become $2600 at the point of re-payment at the end of two years.
(a)
Answer to Problem 20P
The interest rate for an amount of $2000 borrowed, which has become $2600 at the point of re-payment at the end of two years is 14.01%.
Explanation of Solution
The next step is to calculate the second square root of 1.3 in order to determine the value of ‘r’.
The relevant data has to be substituted to the
Introduction:
Calculating the interest rate for lending and borrowings is essential as the value of money changes with the passage of time. The longer the time period taken for settling a fixed amount of money, the lower the interest rate. This is due to the same amount being spread over a higher number of years.
(b)
The interest rate for an amount of $ 2000 borrowed, which has become $ 2600 at the point of re-payment at the end of three years.
(b)
Answer to Problem 20P
The interest rate for an amount of $ 2000 borrowed, which has become $ 2600 at the point of re-payment at the end of three years is 9.13%.
Explanation of Solution
Next, the third square root of 1.3 is being calculated to determine the ‘r’ value.
The relevant data has to be substituted to the future value equation in finding the applicable interest rate. The future value of the borrowed amount has to be divided by the present value as the first step. Next, the second square root of the aforesaid figure has to be derived, in simplifying the steps to find “r”. Finally, “r” could be found by subtracting one from the solved square root figure.
Introduction:
Calculating the interest rate for lending and borrowings is essential as the value of money changes with the passage of time. The longer the time period taken for settling a fixed amount of money, the lower the interest rate. This is due to the same amount being spread over a higher number of years.
(c)
The interest rate for an amount of $ 2000 borrowed, which has become $ 2600 at the point of re-payment at the end of six years.
(c)
Answer to Problem 20P
The interest rate for an amount of $ 2000 borrowed, which has become $ 2600 at the point of re-payment at the end of six years is 4.46%.
Explanation of Solution
The sixth square root of 1.3 is being calculated next, to determine the value of ‘r’.
The relevant data has to be substituted to the future value equation in finding the applicable interest rate. The future value of the borrowed amount has to be divided by the present value as the first step. Next, the second square root of the aforesaid figure has to be derived, in simplifying the steps to find “r”. Finally, “r” could be found by subtracting one from the solved square root figure.
Introduction:
Calculating the interest rate for lending and borrowings is essential as the value of money changes with the passage of time. The longer the time period taken for settling a fixed amount of money, the lower the interest rate. This is due to the same amount being spread over a higher number of years.
(d)
The interest rate for an amount of $ 2000 borrowed, which has become $ 2600 at the point of re-payment at the end of ten years.
(d)
Answer to Problem 20P
The interest rate for an amount of $ 2000 borrowed, which has become $ 2600 at the point of re-payment at the end of ten years would be 2.65%.
Explanation of Solution
The tenth square root of 1.3 is being calculated next, in determining the value of ‘r’.
The relevant data has to be substituted to the future value equation in finding the applicable interest rate. The future value of the borrowed amount has to be divided by the present value as the first step. Next, the second square root of the aforesaid figure has to be derived, in simplifying the steps to find “r”. Finally, “r” could be found by subtracting one from the solved square root figure.
Introduction:
Calculating the interest rate for lending and borrowings is essential as the value of money changes with the passage of time. The longer the time period taken for settling a fixed amount of money, the lower the interest rate. This is due to the same amount being spread over a higher number of years.
Want to see more full solutions like this?
Chapter 3 Solutions
ENGINEERING ECONOMIC ENHANCED EBOOK
- Does the compounding increases the amount of interest paid over a year atthe same nominal interest rate?arrow_forwardYou borrow $500 from a family member and agree to pay it back in six months. Because you are part of the family, you are only being charged simple interest at the rate of 0.5% per month. How much will you owe after six months? How much is the interest?arrow_forwardMaria takes out a 30-year mortgage for $235,136 at an annual interest rate of 4.2%. How much does she still owe when there is 1 year left on the loan? Round your answer to the nearest dollar.arrow_forward
- Ella Stein paid $187.50 interest on a loan of $12,000 for 3 months. What was the rate of interest she paid?arrow_forwardBobby was desperate. He borrowed $600 from a pawn shop and understood he was to repay the loan starting next month with $100, increasing by $10 per month for a total of 8 months. Actually, he misunderstood. The repayments increased by 10% each month after starting next month at $100. Use a spreadsheet to calculate the monthly interest rate that he thought he was to pay, and what he actually will pay.arrow_forwardInterest earned with an annuity due is higher than that with an ordinary annuity. Do you agree or disagree? Please explainarrow_forward
- Joe just completed his engineering degree and started to work for an engineering firm. Joe wants to retire early after 30 years working. He plans to invest $5,000 at the end of every year for a 30-year career. If Joe needs $3,954,750 in savings at retirement, what interest rate must the investment earn?arrow_forwardPlease answer only handwrittenarrow_forwardYou borrow $800 from a family member and agree to pay it back in nine months. Because you are part of the family, you are only being charged simple interest at the rate of 0.6% per month. How much will you owe after nine months? How much is the interest?arrow_forward
- You can afford a $1500 per month mortgage payment. You've found a 30 year loan at 7% interest compounded monthly.a) How big of a loan can you afford?$b) How much total money will you pay the loan company?$c) How much of that money is interest?$arrow_forwardMary Smith took out a loan of $75,000. The loan runs for five years at a minimum interest rate of 33% with payments due each month. How much is each monthly payment?arrow_forwardYou want to buy a $32,000 car. You can finance the car for 1.5% interest for 6 years. What is your monthly payment? Assume monthly compounding. Do not enter the negative sign from your calculator (if there is one) or the dollar sign. Round to two decimal places.arrow_forward
- Economics Today and Tomorrow, Student EditionEconomicsISBN:9780078747663Author:McGraw-HillPublisher:Glencoe/McGraw-Hill School Pub Co