
Concept explainers
(a)
Interpretation:
The equivalency and both conversion factor a) hours and days is to be stated.
Concept introduction:
Equivalency is defined as the two quantities that are equivalent in value. For example: 0.025 furlong is equal to 1 rod. In this case, furlong and rod represent the same physical length but expressed in various units. When an equivalency is denoted as a fractional value it is called ‘conversion factor’. Moreover, two conversion factors result from each equivalency.

Answer to Problem 20E
The equivalency of a) hours and days is
Conversion factor of a) hours and days is given by;
Explanation of Solution
The two quantities that are equivalent in value is denoted as equivalence. For example: 0.025 furlong is equal to 1 rod. In this case, furlong and rod represent the same physical length but expressed in various units. When an equivalency is denoted as a fractional value it is called ‘conversion factor’. Moreover, two conversion factors result from each equivalency.
In the expression (1), the conversion factor 1 rod / 0.025 furlong is used to convert a length expressed in furlongs to a length expressed in rods. Two variable, x and y are directly proportional if there is a non-zero constant k which connect them in the form of
A proportionality constant, m is inserted to convert a proportionality into an equality. Such as,
Given expression;
a) hours and days
Based on the above discussion the equivalency and conversion factors are states as follows;
The equivalency of a) hours and days is
Conversion factor of a) minutes and seconds is given by;
Thus, the equivalency and both conversion factor a) hours and days is stated.
(b)
Interpretation:
The equivalency and both conversion factor b) gallons and quarts is to be stated.
Concept introduction:
Equivalency is defined as the two quantities that are equivalent in value. For example: 0.025 furlong is equal to 1 rod. In this case, furlong and rod represent the same physical length but expressed in various units. When an equivalency is denoted as a fractional value it is called ‘conversion factor’. Moreover, two conversion factors result from each equivalency.

Answer to Problem 20E
The equivalency of b) gallons and quarts is
Conversion factor of b) gallons and quarts is given by;
Explanation of Solution
The two quantities that are equivalent in value is denoted as equivalence. For example: 0.025 furlong is equal to 1 rod. In this case, furlong and rod represent the same physical length but expressed in various units. When an equivalency is denoted as a fractional value it is called ‘conversion factor’. Moreover, two conversion factors result from each equivalency.
In the expression (1), the conversion factor 1 rod / 0.025 furlong is used to convert a length expressed in furlongs to a length expressed in rods. Two variable, x and y are directly proportional if there is a non-zero constant k which connect them in the form of y = kx. Besides, the relationship is expressed as y α x. In the expression the symbol α is called as ‘is proportional to’.
A proportionality constant, m is inserted to convert a proportionality into an equality. Such as,
Given expression;
b) Gallons and quarts
Based on the above discussion the equivalency and conversion factors are states as follows;
The equivalency of b) gallons and quarts is
Conversion factor of b) gallons and quarts is given by;
Thus, the equivalency and both conversion factor b) gallons and quarts is stated.
Interpretation:
(c)
The equivalency and both conversion factor c) quarters and dollars is to be stated.
Concept introduction:
Equivalency is defined as the two quantities that are equivalent in value. For example: 0.025 furlong is equal to 1 rod. In this case, furlong and rod represent the same physical length but expressed in various units. When an equivalency is denoted as a fractional value it is called ‘conversion factor’. Moreover, two conversion factors result from each equivalency.

Answer to Problem 20E
The equivalency of c) quarters and dollars is
Conversion factor of c) quarters and dollars is given by;
Explanation of Solution
The two quantities that are equivalent in value is denoted as equivalence. For example: 0.025 furlong is equal to 1 rod. In this case, furlong and rod represent the same physical length but expressed in various units. When an equivalency is denoted as a fractional value it is called ‘conversion factor’. Moreover, two conversion factors result from each equivalency.
In the expression (1), the conversion factor 1 rod / 0.025 furlong is used to convert a length expressed in furlongs to a length expressed in rods. Two variable, x and y are directly proportional if there is a non-zero constant k which connect them in the form of y = kx. Besides, the relationship is expressed as y α x. In the expression the symbol α is called as ‘is proportional to’.
A proportionality constant, m is inserted to convert a proportionality into an equality. Such as
Given expression;
c) quarters and dollars
Based on the above discussion the equivalency and conversion factors are states as follows;
The equivalency of c) quarters and dollars is
Conversion factor of c) quarters and dollars is given by;
Thus, the equivalency and both conversion factor c) quarters and dollars is stated.
Want to see more full solutions like this?
Chapter 3 Solutions
Introduction to Chemistry, Special Edition
- Stuc X ctclix ALE X A ALE אן A ALEX Lab (195 X Nut x M Inb x NU X NUT X Unt x + → C www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-lgNslkr7j8P3jH-IQ1g8NUi-mObKa_ZLx2twjEhK7mVG6PulJI006NcKTV37JxMpZuyrVCdQolLAKqp_7U3r1GUD3... New Chrome available: Naomi Question 26 of 39 (4 points) | Question Attempt: 1 of Unlimited Give the IUPAC name. 2,3-dimethylhexane Part: 1/2 Part 2 of 2 Draw the skeletal structure of a constitutional isomer of the alkane above that contains a different number of carbons in its longest chain. Skip Part Check Click and drag to start drawing a structure. 3 Finance headline Q Search mwa Harvard Intensifi... X Save For Later 00 dlo HB Submit Assignment 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility a 9:11 PM 4/22/2025arrow_forwardPredict the product of this organic reaction: + NH2 HO A P+ H2O Specifically, in the drawing area below draw the skeletal ("line") structure of P. If there is no reasonable possibility for P, check the No answer box under the drawing area. Click and drag to start drawing a structure. ✓arrow_forward个 Stuc X ctclix ALE X A ALE × A ALE X Lab x (195 × Nut x M Inbx EF 目 → C www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-IgNslkr7j8P3jH-IQ1g8NUi-mObKa_ZLx2twjEhK7mVG6PulJI006NcKTV37JxMpz Chapter 12 HW = Question 27 of 39 (5 points) | Question Attempt: 1 of Unlimited Part: 1/2 Part 2 of 2 Give the IUPAC name. Check 3 50°F Clear ©2025 McGraw Hill L Q Search webp a عالياكarrow_forward
- 个 Stuck x ctc xALE X A ALE × A ALE X Lab x (19: x - G www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-lgNslkr7j8P3jH-1Q1g8NUi-mObka ZLx2twjEhK7mVG6PUUIO06 Chapter 12 HW 三 Question 26 of 39 (4 points) 1 Question Attempt: 1 of Unlimited Answer the following questions about the given alkane. Part: 0 / 2 Part 1 of 2 Give the IUPAC name. Skip Part 2 53°F Clear Check × Q Search hp hp 02arrow_forwardCalculate the equilibrium constant at 25.0 oC for the following equation. Cd(s) + Sn+2(aq) ↔Cd+2(aq) + Sn(s) Group of answer choices 3.11x104 1.95x1018 9.66x108 1.40x109arrow_forwardWhat is the pH at the cathode for the following cell written in line notation at 25.0 oC with a Ecell = -0.2749 V? Ni(s)|Ni+2(aq, 1.00 M)||H+1(aq, ?M)|H2(g, 1.00 atm)|Pt(s)arrow_forward
- Calculate Ecell for a hydrogen fuel cell at 95.0 oC using the following half-reactions with PH2 = 25.0 atm and PO2 = 25.0 atm. O2(g) + 4H+1(aq) + 4e-1 → 2H2O(l) Eo = 1.229 V 2H2(g) → 4H+1(aq) + 4e-1 Eo = 0.00 Varrow_forwardCalculate Ecell at 25.0 oC using the following half-reactions with [Ag+1] = 0.0100 M and [Sn+2] = 0.0200 M. Ag+1(aq) + 1e-1 Ag(s) Sn+2(aq) + 2e-1 Sn(s)arrow_forwardDone 18:19 www-awu.aleks.com Chapter 12 HW Question 27 of 39 (5 points) | Question Attempt: 1 of Unlimited .. LTE סוי 9 ✓ 20 ✓ 21 × 22 23 24 25 26 27 28 29 30 Answer the following questions about the given alkane. Part: 0 / 2 Part 1 of 2 Classify each carbon atom as a 1º, 2º, 3º, or 4°. Highlight in red any 1° carbons, highlight in blue any 2° carbons. highlight in green any 3° carbons, and leave any 4° carbons unhighlighted. Skip Part Check Save For Later © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center | Accessibility ☑ คarrow_forward
- < Done 19:22 www-awu.aleks.com Chapter 12 HW Question 4 of 39 (2 points) | Question Attempt: 5 of Unlimited : .. LTE סוי 1 ✓ 2 ✓ 3 = 4 ✓ 5 ✓ 6 ✓ 7 ✓ 8 ✓ 9 = 10 11 ✓ 12 Consider the molecule (CH3)2CHCH2CHCн for the following questions. Part 1 of 2 Which of the following molecules is/are constitutional isomer(s) to (CH3)2CHCH2CH2CH3? Check all that apply. Part 2 of 2 (CH3),C(CH2)2CH3 CH3 H,C-CH-CH-CH, CH 3 None of the above. ☑ Which of the following molecules is/are identical molecules to (CH3)2CHCH2CH2CH₁₂? Check all that apply. CH3 H,C-CH-CH₂-CH2-CH, CH3(CH2)2CH(CH3)2 CH2-CH2-CH3 HỌC-CH=CH, 乂 ☑ а None of the above Check Save For Later Submit Assignment © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibilityarrow_forward18:11 LTE ا... US$50 off hotels is waiting for you Book now, hotels in Nashville are going fast QUTSLIVII 25 61 69 points) | QuestIVIT ALLēm... now Give the IUPAC name for each compound. Part 1 of 3 Part 2 of 3 X ☑ Х Check Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. TOMS CT US ...vacy Center | Accessibilityarrow_forwardDone 19:17 www-awu.aleks.com Chapter 12 HW Question 29 of 39 (6 points) | Question Attempt: 1 of Unlimited .III LTE סוי 27 28 = 29 30 31 32 = 33 34 35 Consider this structure. CH3CH2CH2 Part 1 of 3 3 CH2 CH2CH3 - C-CH2CH 3 H CH₂ Give the IUPAC name of this structure. 3-ethyl-3,4-dimethylheptane Part: 1/3 Part 2 of 3 Draw the skeletal structure. Skip Part < Check Click and drag to start drawing a structure. Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility Хarrow_forward
- Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning



