2 SEM CARDLESS ACC W/RAVEN TEXT
12th Edition
ISBN: 9781265810467
Author: Raven
Publisher: MCGRAW-HILL HIGHER EDUCATION
expand_more
expand_more
format_list_bulleted
Question
Chapter 3, Problem 1U
Summary Introduction
Introduction:
The monomer is a smaller subunit of molecules, which bond or join with the identical molecules to form a
Expert Solution & Answer
Answer to Problem 1U
Correct answer:
The polymer is formed by the removal of an –OH group and a hydrogen atom between the two monomers. Therefore, option b is correct.
Explanation of Solution
Reason for the correct statement:
A polymer is a long molecule that is formed by the bonding between the smaller units of monomer molecules. The long chains of polymers are formed by the dehydration reaction. In a dehydration reaction, two monomer molecules form a covalent bond by the removal of a hydroxyl ion (-OH) of one monomer and the removal of hydrogen ion of another monomer.
Option b is given as “by the removal of as –OH group and a hydrogen atom.”
As the polymer molecules are formed by the removal of –OH group of one monomer and the hydrogen atom of another monomer, option b is the right answer.
Reasons for the incorrect statements:
Option a is given as “from the growth of the chain of carbon atom.”
The polymer is formed by the bond formation between the –OH and hydrogen group present in two monomers, not from the chain of carbon atoms. So, it is a wrong answer.
Option c is given as “by the addition of an –OH group and a hydrogen atom.”
The polymers are formed by dehydration reaction in which the removal of –OH and hydrogen atom occurs. So, it is a wrong answer.
Option d is given as “through hydrogen bonding.”
The polymers are formed with the formation of a covalent bond between the two monomer unit and not through hydrogen bonding. So, it is a wrong answer.
Hence, options a, c, and d are incorrect.
Conclusion
The polymers are formed by the dehydration reaction in which the covalent bond is formed between the two monomer subunit by removing the –OH group of one monomer unit and a hydrogen atom of another monomer unit.
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation?
The cell membranes are more resistant than normal.
An isotonic solution had been added instead of water.
A solution of 0.1 M NaCl had been added instead of water.
Not enough water had been added to the red blood cell pellet.
The man had sickle-cell anaemia.
A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation?
The cell membranes are more resistant than normal.
An isotonic solution had been added instead of water.
A solution of 0.1 M NaCl had been added instead of water.
Not enough water had been added to the red blood cell pellet.
The man had sickle-cell anaemia.
With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobin
Chapter 3 Solutions
2 SEM CARDLESS ACC W/RAVEN TEXT
Ch. 3.1 - Describe the relationship between functional...Ch. 3.1 - Recognize the different kinds of isomers.Ch. 3.1 - Prob. 3LOCh. 3.2 - Prob. 1LOCh. 3.2 - Prob. 2LOCh. 3.3 - Prob. 1LOCh. 3.3 - Prob. 2LOCh. 3.3 - Prob. 3LOCh. 3.3 - Prob. 4LOCh. 3.4 - Prob. 1LO
Ch. 3.4 - Prob. 2LOCh. 3.4 - Prob. 3LOCh. 3.5 - Prob. 1LOCh. 3.5 - Prob. 2LOCh. 3.5 - Prob. 3LOCh. 3 - Prob. 1UCh. 3 - Why are carbohydrates important molecules for...Ch. 3 - Plant cells store energy in the form of ______,...Ch. 3 - Prob. 4UCh. 3 - A molecule of DNA or RNA is a polymer of a....Ch. 3 - Prob. 6UCh. 3 - What monomers make up a protein? a....Ch. 3 - A triglyceride is a form of _______ composed of...Ch. 3 - You can use starch or glycogen as an energy...Ch. 3 - Which of the following is NOT a difference between...Ch. 3 - Prob. 3ACh. 3 - A mutation that alters a single amino acid within...Ch. 3 - Two different proteins have the same domain in...Ch. 3 - What aspect of triglyceride structure accounts for...Ch. 3 - The spontaneous formation of a lipid bilayer in an...Ch. 3 - Prob. 1SCh. 3 - Hydrogen bonds and hydrophobic interactions each...Ch. 3 - Prob. 3S
Knowledge Booster
Similar questions
- With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forward
- During a routine medical check up of a healthy man it was found that his haematocrit value was highly unusual – value of 60%. What one of the options below is the most likely reason? He will have a diet high in iron. He is likely to be suffering from anaemia. He lives at high altitude. He has recently recovered from an accident where he lost a lot of blood. He has a very large body size.arrow_forwardExplain what age of culture is most likely to produce an endospore?arrow_forwardExplain why hot temperatures greater than 45 degrees celsius would not initiate the sporulation process in endospores?arrow_forward
- Endospore stain: Consider tube 2 of the 7-day bacillus culture. After is was heated, it was incubated for 24 hours then refrigerated. Do you think the cloudiness in this tube is due mostly to vegetative cells or to endospores? Explain your reasoningarrow_forwardReactunts C6H12O6 (Glucose) + 2NAD+ + 2ADP 2 Pyruvic acid + 2NADH + 2ATP a. Which of the above are the reactants? b. Which of the above are the products? c. Which reactant is the electron donor? GHz 06 (glucose) d. Which reactant is the electron acceptor? NAD e. Which of the products have been reduced? NADH f. Which of the products have been oxidized? g. Which process was used to produce the ATP? h. Where was the energy initially in this chemical reaction and where is it now that it is finished? i. Where was the carbon initially in this chemical reaction and where is it now that it is finished? j. Where were the electrons initially in this chemical reaction and where is it now that it is finished? 3arrow_forwardThere is ________ the concept of global warming. Very strong evidence to support Some strong evidence to support Evidence both supporting and against Evidence againstarrow_forward
- How many types of reactions can an enzyme perform?arrow_forwardYour goal is to produce black seeds resistant to mold. So you make the same cross again (between a homozygous black seeded, mold susceptible parent and a homozygous white seeded and mold resistant parent), and, again, advance progeny by SSD to create 100 F10 generation plants. Based on the information you obtained from your first crossing experiment (Question #4), how many F10 plants would you expect to have black seeds and be resistant to mold? Assume that a toxin produced by the mold fungus has been isolated. Only mold resistant seeds will germinate in the presence of the toxin. Could you use this toxin screening procedure to have segregation distortion work in your favor in the F2 generation? Explain your answer. Info from Question 4 a. P Locus (Seed Color): Hypothesis: The null hypothesis (H₀) is that seed color is controlled by alleles at a single locus. Observed Data: Total white seeds: 45 (resistant plants) + 6 (susceptible plants) = 51 Total black seeds: 7 (resistant…arrow_forward10. Consider the following enzyme and its substrate where the "+" and "-" indicate cations and anions, respectively. Explain which of the following inhibitors could inhibit this enzyme? Which type of inhibitor would it be and why? (Video 5-2) Substrate Enzyme Potential inhibitorsarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Biology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage Learning
Concepts of BiologyBiologyISBN:9781938168116Author:Samantha Fowler, Rebecca Roush, James WisePublisher:OpenStax College
Biology Today and Tomorrow without Physiology (Mi...BiologyISBN:9781305117396Author:Cecie Starr, Christine Evers, Lisa StarrPublisher:Cengage Learning
Human Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage Learning
Biology (MindTap Course List)
Biology
ISBN:9781337392938
Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher:Cengage Learning
Concepts of Biology
Biology
ISBN:9781938168116
Author:Samantha Fowler, Rebecca Roush, James Wise
Publisher:OpenStax College
Biology Today and Tomorrow without Physiology (Mi...
Biology
ISBN:9781305117396
Author:Cecie Starr, Christine Evers, Lisa Starr
Publisher:Cengage Learning
Human Biology (MindTap Course List)
Biology
ISBN:9781305112100
Author:Cecie Starr, Beverly McMillan
Publisher:Cengage Learning