For each group in the following list, find the order of the group and the order of each element in the group. What relation do you see between the orders of the elements of a group and the order of the group? Z 12 , U (10), U (12), U (20), D 4
For each group in the following list, find the order of the group and the order of each element in the group. What relation do you see between the orders of the elements of a group and the order of the group? Z 12 , U (10), U (12), U (20), D 4
For each group in the following list, find the order of the group and the order of each element in the group. What relation do you see between the orders of the elements of a group and the order of the group?
Z
12
, U(10), U(12), U(20),
D
4
Expert Solution & Answer
To determine
To calculate : The relationship between the group's element commands and the group's commands.
U(20)D4U(12)Z12U(10)
Here we have to make it understand and not to verify.
Answer to Problem 1E
Clearly,it can be said that commands of the elements of the group are no larger than the order of the given group.
Explanation of Solution
Given information : List of group Z12,U(10),U(12),U(20) and D4 is given in the question.
I want to learn this topic l dont know anything about it
Solve the linear system of equations attached using Gaussian elimination (not Gauss-Jordan) and back subsitution.
Remember that:
A matrix is in row echelon form if
Any row that consists only of zeros is at the bottom of the matrix.
The first non-zero entry in each other row is 1. This entry is called aleading 1.
The leading 1 of each row, after the first row, lies to the right of the leading 1 of the previous row.
PRIMERA EVALUACIÓN SUMATIVA
10. Determina la medida de los ángulos in-
teriores coloreados en cada poligono.
⚫ Octágono regular
A
11. Calcula es número de lados qu
poligono regular, si la medida
quiera de sus ángulos internos
• a=156°
A= (-2x+80
2
156 180-
360
0 = 24-360
360=24°
• a = 162°
1620-180-360
6=18-360
360=19
2=360=
18
12. Calcula las medida
ternos del cuadrilá
B
X+5
x+10
A
X+X+
Sx+6
5x=3
x=30
0
лаб
• Cuadrilátero
120°
110°
• α = 166° 40'
200=180-360
0 =
26-360
360=20
ひ=360
20
18 J
60°
⚫a=169° 42' 51.43"
169.4143180-340
0 = 10.29 54-360
360 10.2857
2=360
10.2857
@Sa
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