The “surface area-to-volume” ratio helps in explaining the relation between a cell’s surface area and its size.

Question

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Answer 1

Question

Chapter 3, Problem 1A

Summary Introduction

Introduction:

The “surface area-to-volume” ratio helps in explaining the relation between a cell’s surface area and its size.

Expert Solution & Answer

Answer to Problem 1A

Correct answer:

As the cell size decreases, the ratio its surface area to volume increases. Therefore, option (a) is correct.

Explanation of Solution

Reasons for the correct statement:

The surface area to volume ratio increases, when there is decrease in the size of the cell. Accordingly, as the cells have smaller size, they tend to possess a surface area that is large, and so, as the size of the cell decreases, the ratio increases.

Option (a) is given as “increases”.

“As the size of a cell decreases, the ratio of its surface area to volume increases”, it is the right answer”.

Hence, option (a) is correct.

Reasons for the incorrect statements:

Option (b) is given as “decreases”.
As the size of a cell will increase, then the ratio of surface area to volume would decrease, not when the cell size will decrease. So, it is a wrong answer.

Option (c) is given as “stays the same”.
As the cell size decreases, the ratio its surface area to volume increases, however it does not remain the same. So, it is a wrong answer.

Hence, options (b) and (c) are incorrect.

Conclusion

:

As the cell size decreases, then the ratio to its surface area to volume increases.

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✓ Details Draw a protein that is embedded in a membrane (a transmembrane protein), label the lipid bilayer and the protein. Identify the areas of the lipid bilayer that are hydrophobic and hydrophilic. Draw a membrane with two transporters: a proton pump transporter that uses ATP to generate a proton gradient, and a second transporter that moves glucose by secondary active transport (cartoon-like is ok). It will be important to show protons moving in the correct direction, and that the transporter that is powered by secondary active transport is logically related to the proton pump.

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Answer 2

Question

Chapter 3, Problem 1A

Summary Introduction

Introduction:

The “surface area-to-volume” ratio helps in explaining the relation between a cell’s surface area and its size.

Expert Solution & Answer

Answer to Problem 1A

Correct answer:

As the cell size decreases, the ratio its surface area to volume increases. Therefore, option (a) is correct.

Explanation of Solution

Reasons for the correct statement:

The surface area to volume ratio increases, when there is decrease in the size of the cell. Accordingly, as the cells have smaller size, they tend to possess a surface area that is large, and so, as the size of the cell decreases, the ratio increases.

Option (a) is given as “increases”.

“As the size of a cell decreases, the ratio of its surface area to volume increases”, it is the right answer”.

Hence, option (a) is correct.

Reasons for the incorrect statements:

Option (b) is given as “decreases”.
As the size of a cell will increase, then the ratio of surface area to volume would decrease, not when the cell size will decrease. So, it is a wrong answer.

Option (c) is given as “stays the same”.
As the cell size decreases, the ratio its surface area to volume increases, however it does not remain the same. So, it is a wrong answer.

Hence, options (b) and (c) are incorrect.

Conclusion

:

As the cell size decreases, then the ratio to its surface area to volume increases.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 3, Problem 1A

Summary Introduction

Introduction:

The “surface area-to-volume” ratio helps in explaining the relation between a cell’s surface area and its size.

Expert Solution & Answer

Answer to Problem 1A

Correct answer:

As the cell size decreases, the ratio its surface area to volume increases. Therefore, option (a) is correct.

Explanation of Solution

Reasons for the correct statement:

The surface area to volume ratio increases, when there is decrease in the size of the cell. Accordingly, as the cells have smaller size, they tend to possess a surface area that is large, and so, as the size of the cell decreases, the ratio increases.

Option (a) is given as “increases”.

“As the size of a cell decreases, the ratio of its surface area to volume increases”, it is the right answer”.

Hence, option (a) is correct.

Reasons for the incorrect statements:

Option (b) is given as “decreases”.
As the size of a cell will increase, then the ratio of surface area to volume would decrease, not when the cell size will decrease. So, it is a wrong answer.

Option (c) is given as “stays the same”.
As the cell size decreases, the ratio its surface area to volume increases, however it does not remain the same. So, it is a wrong answer.

Hence, options (b) and (c) are incorrect.

Conclusion

:

As the cell size decreases, then the ratio to its surface area to volume increases.

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Answer 4

Question

Chapter 3, Problem 1A

Summary Introduction

Introduction:

The “surface area-to-volume” ratio helps in explaining the relation between a cell’s surface area and its size.

Expert Solution & Answer

Answer to Problem 1A

Correct answer:

As the cell size decreases, the ratio its surface area to volume increases. Therefore, option (a) is correct.

Explanation of Solution

Reasons for the correct statement:

The surface area to volume ratio increases, when there is decrease in the size of the cell. Accordingly, as the cells have smaller size, they tend to possess a surface area that is large, and so, as the size of the cell decreases, the ratio increases.

Option (a) is given as “increases”.

“As the size of a cell decreases, the ratio of its surface area to volume increases”, it is the right answer”.

Hence, option (a) is correct.

Reasons for the incorrect statements:

Option (b) is given as “decreases”.
As the size of a cell will increase, then the ratio of surface area to volume would decrease, not when the cell size will decrease. So, it is a wrong answer.

Option (c) is given as “stays the same”.
As the cell size decreases, the ratio its surface area to volume increases, however it does not remain the same. So, it is a wrong answer.

Hence, options (b) and (c) are incorrect.

Conclusion

:

As the cell size decreases, then the ratio to its surface area to volume increases.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 3, Problem 1A

Summary Introduction

Introduction:

The “surface area-to-volume” ratio helps in explaining the relation between a cell’s surface area and its size.

Expert Solution & Answer

Answer to Problem 1A

Correct answer:

As the cell size decreases, the ratio its surface area to volume increases. Therefore, option (a) is correct.

Explanation of Solution

Reasons for the correct statement:

The surface area to volume ratio increases, when there is decrease in the size of the cell. Accordingly, as the cells have smaller size, they tend to possess a surface area that is large, and so, as the size of the cell decreases, the ratio increases.

Option (a) is given as “increases”.

“As the size of a cell decreases, the ratio of its surface area to volume increases”, it is the right answer”.

Hence, option (a) is correct.

Reasons for the incorrect statements:

Option (b) is given as “decreases”.
As the size of a cell will increase, then the ratio of surface area to volume would decrease, not when the cell size will decrease. So, it is a wrong answer.

Option (c) is given as “stays the same”.
As the cell size decreases, the ratio its surface area to volume increases, however it does not remain the same. So, it is a wrong answer.

Hence, options (b) and (c) are incorrect.

Conclusion

:

As the cell size decreases, then the ratio to its surface area to volume increases.

Answer 6

Chapter 3, Problem 1A

Summary Introduction

Introduction:

The “surface area-to-volume” ratio helps in explaining the relation between a cell’s surface area and its size.

Expert Solution & Answer

Answer to Problem 1A

Correct answer:

As the cell size decreases, the ratio its surface area to volume increases. Therefore, option (a) is correct.

Explanation of Solution

Reasons for the correct statement:

The surface area to volume ratio increases, when there is decrease in the size of the cell. Accordingly, as the cells have smaller size, they tend to possess a surface area that is large, and so, as the size of the cell decreases, the ratio increases.

Option (a) is given as “increases”.

“As the size of a cell decreases, the ratio of its surface area to volume increases”, it is the right answer”.

Hence, option (a) is correct.

Reasons for the incorrect statements:

Option (b) is given as “decreases”.
As the size of a cell will increase, then the ratio of surface area to volume would decrease, not when the cell size will decrease. So, it is a wrong answer.

Option (c) is given as “stays the same”.
As the cell size decreases, the ratio its surface area to volume increases, however it does not remain the same. So, it is a wrong answer.

Hence, options (b) and (c) are incorrect.

Conclusion

:

As the cell size decreases, then the ratio to its surface area to volume increases.

Answer 7

Chapter 3, Problem 1A

Summary Introduction

Introduction:

The “surface area-to-volume” ratio helps in explaining the relation between a cell’s surface area and its size.

Answer 8

Expert Solution & Answer

Answer to Problem 1A

Correct answer:

As the cell size decreases, the ratio its surface area to volume increases. Therefore, option (a) is correct.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Reasons for the correct statement:

The surface area to volume ratio increases, when there is decrease in the size of the cell. Accordingly, as the cells have smaller size, they tend to possess a surface area that is large, and so, as the size of the cell decreases, the ratio increases.

Option (a) is given as “increases”.

“As the size of a cell decreases, the ratio of its surface area to volume increases”, it is the right answer”.

Hence, option (a) is correct.

Reasons for the incorrect statements:

Option (b) is given as “decreases”.
As the size of a cell will increase, then the ratio of surface area to volume would decrease, not when the cell size will decrease. So, it is a wrong answer.

Option (c) is given as “stays the same”.
As the cell size decreases, the ratio its surface area to volume increases, however it does not remain the same. So, it is a wrong answer.

Hence, options (b) and (c) are incorrect.

Answer 12

Conclusion

:

As the cell size decreases, then the ratio to its surface area to volume increases.

Answer 13

Ch. 3.1 - State the basic principles of the cell theory.Ch. 3.1 - Prob. 2LO Ch. 3.1 - Prob. 3LO Ch. 3.1 - Discuss how a researcher might use a GFP-labeled...Ch. 3.1 - How might a meal of a cheeseburger and fries be...Ch. 3.2 - Distinguish between the structure of a prokaryotic...Ch. 3.2 - Identify the role of the plasma membrane and...Ch. 3.2 - Summarize how eukaryotic cells evolved from...Ch. 3.3 - Prob. 1LO Ch. 3.3 - Prob. 2LO

The “surface area-to-volume” ratio helps in explaining the relation between a cell’s surface area and its size.

Concept explainers

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Introduction:

The “surface area-to-volume” ratio helps in explaining the relation between a cell’s surface area and its size.

Answer to Problem 1A

Explanation of Solution

Want to see more full solutions like this?

Chapter 3 Solutions

The “surface area-to-volume” ratio helps in explaining the relation between a cell’s surface area and its size.

Concept explainers

Videos

Introduction: The “surface area-to-volume” ratio helps in explaining the relation between a cell’s surface area and its size.

Answer to Problem 1A

Explanation of Solution

Want to see more full solutions like this?

Chapter 3 Solutions

Introduction:

The “surface area-to-volume” ratio helps in explaining the relation between a cell’s surface area and its size.