Chemistry (AP Edition)
9th Edition
ISBN: 9781133611103
Author: Steven S. Zumdahl, Susan A. Zumdahl
Publisher: Brooks Cole
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Chapter 3, Problem 179IP
With the advent of techniques such as scanning tunneling microscopy, it is now possible to “write” with individual atoms by manipulating and arranging atoms on an atomic surface.
a. If an image is prepared by manipulating iron atoms and their total mass is 1.05 × 10−20 g, what number of iron atoms were used?
b. If the image is prepared on a platinum surface that is exactly 20 platinum atoms high and 14 platinum atoms wide, what is the mass (grams) of the atomic surface?
c. If the atomic surface were changed to ruthenium atoms and the same surface mass as determined in part b is used, what number of ruthenium atoms is needed to construct the surface?
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Part VII. The H-NMR of a compound with molecular formula C5 H 10 O2 is given below.
Find the following:
(a) The no. of protons corresponding to each signal in the spectra
(6) Give the structure of the compound and assign the signals to each
proton in the compound.
a
70.2
Integration Values
C5H10O2
b
47.7
C
46.5
d
69.5
3.6 3.5
3.4 3.3 3.2 3.1 3.0
2.9 2.8
2.7
2.6 2.5
2.4 2.3 2.2 2.1 2.0
Chemical Shift (ppm)
1.9
1.8
1.7 1.6
1.5
1.4 1.3 1.2
1.1 1.0
0.9 0.8
Part 111. 1 H-NMR spectrum of a compound with integration values in red is given below.
Answer the following:
(a) write the signals in the 'H-NMR spectrum to the corresponding protons on the structure
of the molecule below.
(b) Identify the theoretical multiplicities for each proton in the compound. Also give the possible.
complex splitting patterns assuming J values are not similar.
там
Br
22
2
3
6
4 7.2 7.0 6.8 6.6 6.4 6.2 6.0 5.8 5.6 5.4 5.2 5.0 4.8 4.6 4.4 4.2 4.0 3.8 3.6 3.4 3.2 3.0 2.8 2.6 2.4 2.2 2.0 1.8 1.6 1.4 1.2 1.0 0.8 0
Chemical Shift (ppm)
ra.
Br
2
3
6
6
2.5
2.4
2.3
2.2
2.1
2.0
1.9
1.8
1.7
1.6
1.5
1.4
1.3
1.2
1.1
1.0
0.9
0.8
Chemical Shift (ppm)
2
2
Br
7.3
7.2
7.1
7.0 6.9
6.7 6.6 6.5
6.4
6.3
6.2
6.1
6.0
Chemical Shift (ppm)
5.9
5.8 5.7
5.5 5.4 5.3 5.2
5.0 4.9
1600°
1538°C
1493°C
In the diagram, the letter L indicates
that it is a liquid. Indicate its
components in the upper region
where only L is indicated.
The
iron-iron carbide phase
diagram.
Temperature (°C)
1400
8
1394°C
y+L
1200
2.14
y, Austenite
10000
912°C
800a
0.76
0.022
600
400
(Fe)
a, Ferrite
Composition (at% C)
15
1147°C
a + Fe3C
2
3
Composition (wt% C)
L
2500
4.30
2000
y + Fe3C
727°C
1500
Cementite (Fe3C)
1000
4
5
6
6.70
Temperature (°F)
Chapter 3 Solutions
Chemistry (AP Edition)
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