A compound has a molar mass of 86 g/mol and has the percent composition (by mass) of 55.8% C, 37.2% O, and 7.0% H. a) Determine the empirical formula. C O H b) Determine the molecular formula. C O H
A compound has a molar mass of 86 g/mol and has the percent composition (by mass) of 55.8% C, 37.2% O, and 7.0% H. a) Determine the empirical formula. C O H b) Determine the molecular formula. C O H
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A compound has a molar mass of 86 g/mol and has the percent composition (by mass) of 55.8% C, 37.2% O, and 7.0% H.
a) Determine the empirical formula. C O H
b) Determine the molecular formula. C O H
Expert Solution

Moles of C, H , O
To determine the empirical formula for compound , first we have to consider the given percentage of C , H and O as mass .
55.8% C, 37.2% O, and 7.0% H.
Carbon = = 55.8 g
Oxygen = 37.2 g
Hydrogen = 7.0 g
* Moles of carbon
= Mass of carbon / molar mass of carbon
= 55.8 g / 12 (g/mol)
= 4.65 mol
*Moles of oxygen
= Mass of oxygen / molar mass of oxygen
= 37.2 g / 16 (g/mol)
= 2.32 mol
*Moles of hydrogen
= Mass of hydrogen/molar mass of hydrogen
= 7 g / 1.0 (g/mol)
= 7 mol
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