Construction Materials, Methods and Techniques (MindTap Course List)
4th Edition
ISBN: 9781305086272
Author: William P. Spence, Eva Kultermann
Publisher: Cengage Learning
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Chapter 3, Problem 11RQ
To determine
The examples of renewable building materials
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P.3.3
Oil of sp.gr. 0.9 flows through a vertical pipe (upwards). Two points A and B one
above the other 40 cm apart in a pipe are connected by a U-tube carrying mercury. If
the difference of pressure between A and B is 0.2 kg/cm²,
1- Find the reading of the manometer.
2- If the oil flows through a horizontal pipe, find the reading in manometer for the
same difference in pressure between A and B.
Ans. 1- R= 0.12913 m, 2- R = 0.1575 m,
Please solve the question by hand with a detailed explanation of the steps.
Please solve the question by hand with a detailed explanation of the steps.
Chapter 3 Solutions
Construction Materials, Methods and Techniques (MindTap Course List)
Ch. 3 - What are the major material groups?Ch. 3 - Prob. 2RQCh. 3 - What are the mechanical properties that define a...Ch. 3 - How does a tensile stress differ from a...Ch. 3 - Prob. 5RQCh. 3 - Prob. 6RQCh. 3 - Prob. 7RQCh. 3 - What is the most common form of chemical...Ch. 3 - Prob. 9RQCh. 3 - Prob. 10RQ
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- P.3.4 A mercury U-tube manometer is used to measure the pressure drop across an orifice in pipe. If the liquid that flowing through the orifice is brine of sp.gr. 1.26 and upstream pressure is 2 psig and the downstream pressure is (10 in Hg) vacuum, find the reading of manometer. Ans. R=394 mm Hgarrow_forwardProject management questionarrow_forwardQ5/B with Explantion plsarrow_forward
- project management question Q5/Barrow_forwardProblem 1: Given: In a given floor system, a 5-in concrete slab supported by T-beams of 24-ft spans, supporting 354 psf live load. The T-beams are spaced 2x4 ft on center, and bw (width of the beam web) = 15 inches. Total T-beam height is 25 inches. f'c = 4,000psi, fy = 60,000psi. Design the T-beam. Show all steps. Sketch your Design. Problem 2: Given: A 25"x25" column is subject to a factored axial load of Pu=1,200 kips, and factored design moment of Mu-354 kips-ft. f'c 4,000psi, fy = 60,000psi. Determine the required steel ratio (p) and ties. Sketch the design. 2.0 0.08 INTERACTION DIAGRAM R4-60.9 fc-4 ksi 1.8 1,- 60 ksi 0.07 Y=0.9 16 1.6 0.06 Kmax 0.05 1.4 f/f, = 0 0.04 00 K₁ = P₁/f'c Ag 1.2 12 0.03 0.25 1.0 10 0.02 0.01 0.8 0.6 0.4 €,= 0.0035 0.2 €,= 0.0050 0.0 h yh 0.50 0.75 1.0. 0.00 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 0.45 0.50 R₁ = P₁e/f'Agharrow_forwardGiven: In a given floor system, a 5-in concrete slab supported by T-beams of 24-ft spans, supporting 354 psf live load. The T-beams are spaced 2x4 ft on center, and bw (width of the beam web) = 15 inches. Total T-beam height is 25 inches. f'c = 4,000psi, fy = 60,000psi. Design the T-beam. Show all steps. Sketch your Design.arrow_forward
- Problem 2: Given: A 25"x25" column is subject to a factored axial load of Pu=1,200 kips, and factored design moment of Mu-354 kips-ft. f'c 4,000psi, fy = 60,000psi. Determine the required steel ratio (p) and ties. Sketch the design. 2.0 P=0.08 INTERACTION DIAGRAM R4-60.9 fc-4 ksi 1.8 1,- 60 ksi 0.07 7=0.9 1.6 16 0.06 Kmax 0.05 1.4 f/f, = 0 0.04 90 K₁ = P₁/f'Ag 1.2 0.03 0.25 0.02 1.0 0.01 0.8 0.6 0.4 €= 0.0035 0.2 €,= 0.0050 0.0 h yh 0.50 0.75 1.0. 0.00 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 0.45 0.50 R₁ = P₁e/f'Aharrow_forwardGiven: A 25"x25" column is subject to a factored axial load of Pu=1,200 kips, and factored design moment of Mu=354 kips-ft. f'c 4,000psi, fy = 60,000psi. Determine the required steel ratio () and ties. Sketch the design.arrow_forwardSee Figure (1) below. A 14 in. wide and 2 in. thick plate subject to tensile loading has staggered holes as shown. Compute An and Ae. P 2.00 3.00 4.00 3.00 2.00 ΕΙ T A B C F G D S = 2.50 3/4" bolts in 13/16" holes 14x12 PL Parrow_forward
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