Explanation It is given that the components of A → satisfy the relation given below. A x = − A y ≠ 0 From the obove equation, it can be concluded that the components of A → are equal in magnitude but unequal in direction. Formula to calculate the possible directions of vector A → is, θ = tan − 1 ( A y A x ) (1) Here, θ is the direction of vector A → . A x is the component of vector A → in x direction. A y is the component of vector A → in y direction. Consider the vector diagram for the given vector components when A x < 0 . Figure (1) When A x < 0 , the value of component of vector A → in x direction is, A x = − a When A x < 0 , the value of component of vector A → in y direction is, A y = a Substitute ( − a ) for A x and a for A y in equation (1). θ = tan − 1 ( ( + a ) ( − a ) ) = tan − 1 ( − 1 ) = − 45 ° Solve the further equation. θ = 180 ° + ( − 45 ° ) = 135 ° Thus, the possible direction of vector A → when A x < 0 is 135 ° counterclockwise from the x-axis

5th Edition

ISBN: 9780134051796

Author: Walker

Publisher: YUZU

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Chapter 3, Problem 11CQ

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The possible directions of vector A→ .

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Chapter 3 Solutions

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The possible directions of vector A → .

Solution Summary: The author calculates the possible directions of vector stackreltoA by using the obove equation.

The possible directions of vector A→ .

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Chapter 3 Solutions