The balanced chemical equation for the given reaction. Concept introduction: According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed. Therefore a chemical equation, having lesser number of moles of an element on either side of a reaction, is balanced using appropriate numerical coefficients to satisfy the law of conservation of mass.
The balanced chemical equation for the given reaction. Concept introduction: According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed. Therefore a chemical equation, having lesser number of moles of an element on either side of a reaction, is balanced using appropriate numerical coefficients to satisfy the law of conservation of mass.
Interpretation: The balanced chemical equation for the given reaction.
Concept introduction:
According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed. Therefore a chemical equation, having lesser number of moles of an element on either side of a reaction, is balanced using appropriate numerical coefficients to satisfy the law of conservation of mass.
(b)
Interpretation Introduction
Interpretation: The amount of calcium oxide required to eliminate the sulfur dioxide.
Concept introduction: The amount of calcium oxide is calculated by the product of number of moles and molar mass of calcium oxide. The amount (m) of CaO required to eliminate SO2 per day is calculated as,
m=n×M
(c)
Interpretation Introduction
Interpretation: The amount of calcium sulfite produced daily.
Concept introduction: The amount of calcium sulfite is calculated by the product of number of moles and molar mass of calcium sulfite. The amount (m) of CaSO3 produced daily is calculated as,
B 1 of 2
Additional problems in preparation to Midterm #1:
1.) How can the following compounds be prepared using Diels-Alder reaction:
CH3 O
CN
(a)
(b)
CN
CH3
2.) What is the missing reagent in the shown reaction?
H3C
+ ?
H3C
H3C
CN
H3C
''CN
(၁)
H
3.) Write the products 1,2-addition and 1,4-addition of DBr to 1,3-cyclohexadiene.
Remember, D is deuterium, a heavy isotope of hydrogen. It reacts exactly like hydrogen.
4.) In the shown reaction, which will be the kinetic product and which will be the
thermodynamic product?
H3C
CI
H3C
HCI
H3C
+
5.) Which of the following molecules is aromatic?
(a)
(b)
(c)
H
6.) Which of the following molecules is aromatic?
(a)
(b)
(c)
7.) Write the mechanism for the shown reaction.
+
Ха
AICI 3
CI
8.) Suggest reagents that would convert benzene into the shown compounds.
CI
NO2
-8-6-6-8-a
(a)
(b)
(c)
(d)
(e)
(a)
SO3H
Br
The number of 2sp^2 hybridized atoms in is: A. 8; B. 6; C.4; D.2; E.0;
The highest boiling compound from among the following isA. 2-methylheptane; B. 3-methylheptane; C. 2,2-dimethylhexane;D. octane; E. 2,2,3-trimethylpentane
Chapter 3 Solutions
Chemistry: The Central Science Plus Mastering Chemistry with Pearson eText -- Access Card Package (14th Edition)
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Step by Step Stoichiometry Practice Problems | How to Pass ChemistryMole Conversions Made Easy: How to Convert Between Grams and Moles; Author: Ketzbook;https://www.youtube.com/watch?v=b2raanVWU6c;License: Standard YouTube License, CC-BY