The formula of the binary compound formed from the given pairs of elements in each case is to be stated. Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number − 8 . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned. To determine: The formula of diboron trioxide.
The formula of the binary compound formed from the given pairs of elements in each case is to be stated. Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number − 8 . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned. To determine: The formula of diboron trioxide.
Solution Summary: The author explains the formula of the binary compound formed from the given pairs of elements in each case.
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
To determine: The formula of diboron trioxide.
(b)
Interpretation Introduction
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
To determine: The formula of of arsenic pentafluoride.
(c)
Interpretation Introduction
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
To determine: The formula of of dinitrogen monoxide.
(d)
Interpretation Introduction
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
Denote the dipole for the indicated bonds in the following molecules.
H3C
✓
CH3
B
F-CCl 3
Br-Cl
H3C Si(CH3)3
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OH
НО.
HO
HO
OH
vitamin C
CH3
For the SN2 reaction, draw the major organic product and select the correct (R) or (S) designation around the stereocenter
carbon in the organic substrate and organic product. Include wedge-and-dash bonds and draw hydrogen on a stereocenter.
Η
1
D
EN
Select Draw Templates More
C
H
D
N
Erase
Q9: Explain why compound I is protonated on O while compound II is protonated on N.
NH2
NH2
I
II
Chapter 3 Solutions
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