Programming with Microsoft Visual Basic 2015 (MindTap Course List)
7th Edition
ISBN: 9781285860268
Author: Diane Zak
Publisher: Cengage Learning
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Expert Solution & Answer
Chapter 2.LB, Problem 5RQ
Explanation of Solution
Keyboard access to a text box:
Access key:
- An access key is a shortcut to select the object by using “ALT” key with any letter or any number combination.
- It can be allocated to each control in the interface that accepts the user input.
- The underlined letter in the interface indicates the access key letter.
- It can be assigned to an object by adding an ampersand (&) in the control’s caption.
- First letter of the caption of an object is assigned as an access key unless other letter provides a more meaning.
- For example:
- If the letter “D” is used as an access key for the “Display” button, then the “Display” button can be accessed by using either ALT + D or ALT + d.
- The access key can be assigned to the “Display” button by adding an ampersand in the text property of the “Display” button control as “&Display”.
- If the letter “D” is used as an access key for the “Display” button, then the “Display” button can be accessed by using either ALT + D or ALT + d.
TabIndex:
- TabIndex is a property of the control used in an interface.
- TabIndex property assigns the number to represent the order in which the control should be moved in the interface...
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Students have asked these similar questions
make corrections of this program based on the errors shown. this is CIS 227 .
Create 6 users: Don, Liz, Shamir, Jose, Kate, and Sal.
Create 2 groups: marketing and research.
Add Shamir, Jose, and Kate to the marketing group.
Add Don, Liz, and Sal to the research group.
Create a shared directory for each group.
Create two files to put into each directory:
spreadsheetJanuary.txt
meetingNotes.txt
Assign access permissions to the directories:
Groups should have Read+Write access
Leave owner permissions as they are
“Everyone else” should not have any access
Submit for grade:
Screenshot of /etc/passwd contents showing your new users
Screenshot of /etc/group contents showing new groups with their members
Screenshot of shared directories you created with files and permissions
⚫ your circuit diagrams for your basic bricks, such as AND, OR, XOR gates and 1 bit multiplexers,
⚫ your circuit diagrams for your extended full adder, designed in Section 1 and
⚫ your circuit diagrams for your 8-bit arithmetical-logical unit, designed in Section 2.
1 An Extended Full Adder
In this Section, we are going to design an extended full adder circuit (EFA). That EFA takes 6 one bit inputs: aj, bj,
Cin, Tin, t₁ and to. Depending on the four possible combinations of values on t₁ and to, the EFA produces 3 one bit
outputs: sj, Cout and rout.
The EFA can be specified in principle by a truth table with 26 = 64 entries and 3 outputs. However, as the EFA
ignores certain inputs in certain cases, it is easier to work with the following overview specification, depending only
on t₁ and to in the first place:
t₁ to Description
00
Output Relationship
Ignored
Inputs
Addition Mode
2 Coutsjaj + bj + Cin, Tout= 0
Tin
0 1
Shift Left Mode
Sj = Cin,
Cout=bj, rout = 0
rin, aj
10
1 1
Shift Right…
Chapter 2 Solutions
Programming with Microsoft Visual Basic 2015 (MindTap Course List)
Ch. 2.LA - Prob. 1RQCh. 2.LA - Prob. 2RQCh. 2.LA - Prob. 3RQCh. 2.LA - Prob. 4RQCh. 2.LA - Prob. 5RQCh. 2.LA - Prob. 1ECh. 2.LA - Prob. 2ECh. 2.LA - Prob. 3ECh. 2.LB - Prob. 1RQCh. 2.LB - Prob. 2RQ
Ch. 2.LB - Prob. 3RQCh. 2.LB - Prob. 4RQCh. 2.LB - Prob. 5RQCh. 2.LB - Prob. 1ECh. 2.LB - Prob. 2ECh. 2.LB - Prob. 3ECh. 2.LB - Prob. 4ECh. 2.LC - Prob. 1RQCh. 2.LC - Prob. 2RQCh. 2.LC - Prob. 3RQCh. 2.LC - Prob. 4RQCh. 2.LC - Prob. 5RQCh. 2.LC - Prob. 1ECh. 2.LC - Prob. 2ECh. 2.LC - Prob. 3ECh. 2.LC - Prob. 4ECh. 2.LC - Prob. 5ECh. 2.LC - Your science teacher has asked you to create an...Ch. 2.LC - Prob. 7ECh. 2.LC - Prob. 8ECh. 2.LC - Prob. 9ECh. 2.LC - The payroll clerk at Photo Workshop has asked you...Ch. 2.LC - Prob. 11E
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