To determine We need to determine the following: a) Flow rate in the units of mL/hr and mg of sodium chloride per hour. b) Flow rate in units of gtt/hr c) Quantity of sodium chloride delivered in a 4-hour period. Explanation Given: 0.9 mg of sodium chloride per 100 mL of solution A total solution of 500 mL is given over a 4-hour period. Formula used: Flow rate = Total quantity Total time Calculation: a) Flow rate= Total quantity Total time = 5 00 mL 4 hours =125 mL hr 100 mL of solution contains =0 .9 mg of sodium chloride 1 mL of solution contains = 0 .9 mg 100 mL 500 mL of solution contains = 0 .9 mg 100 mL x 500 mL= 4 .5 mg milligrams Therefore: Flow rate= Total quantity Total time = 4 .5 mg 4 hours =1 ...

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ISBN: 9780135239919

Author: BENNETT AND BR

Publisher: PEARSON

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Chapter 2.B, Problem 93E

To determine

We need to determine the following:

a) Flow rate in the units of mL/hr and mg of sodium chloride per hour.

b) Flow rate in units of gtt/hr

c) Quantity of sodium chloride delivered in a 4-hour period.

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Chapter 2.B, Problem 91E

Chapter 2.B, Problem 94E

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