COLLEGE PHYSICS,V.2
11th Edition
ISBN: 9781305965522
Author: SERWAY
Publisher: CENGAGE L
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Chapter 29.6, Problem 29.4QQ
To determine
The possible reactions.
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Identify the unknown particles X, A and Z in the following nuclear reactions:
(a) X + He → "Mg + ¿n
12
(b) U + n→ Sr + ¿X + 2,n
235
90
Sr + ;X +
38
Select the missing product of this nuclear reaction:
235
U + n
92
1
1
90
→ ? + 2 n +
Rb
37
O A. 144
Cs
55
о в. 146
Cs
55
C. 143.
53
O D. 143
Хе
54
For the following reaction, what is the energy released, in GJ/mol? (1 GJ = 1E9 J)
Use 2.998E8 m/s as the speed of light
1 a m u has a mass of 1.6605E-27 kg
A + B → C + D
A
B
C
D
mass (amu)
3.1706
6.3211
4.1531
5.1703
Chapter 29 Solutions
COLLEGE PHYSICS,V.2
Ch. 29.3 - Prob. 29.1QQCh. 29.3 - What fraction of a radioactive sample has decayed...Ch. 29.3 - Prob. 29.3QQCh. 29.6 - Prob. 29.4QQCh. 29.6 - Prob. 29.5QQCh. 29 - Prob. 1CQCh. 29 - Prob. 2CQCh. 29 - Prob. 3CQCh. 29 - Prob. 4CQCh. 29 - Prob. 5CQ
Ch. 29 - Prob. 6CQCh. 29 - Prob. 7CQCh. 29 - A radioactive sample has an activity R. For each...Ch. 29 - Prob. 9CQCh. 29 - Prob. 10CQCh. 29 - Prob. 11CQCh. 29 - Prob. 12CQCh. 29 - Prob. 13CQCh. 29 - Prob. 1PCh. 29 - Prob. 2PCh. 29 - Prob. 3PCh. 29 - Prob. 4PCh. 29 - Using 2.3 1017 kg/m3 as the density of nuclear...Ch. 29 - Prob. 6PCh. 29 - Prob. 7PCh. 29 - Prob. 8PCh. 29 - Prob. 9PCh. 29 - Prob. 10PCh. 29 - Prob. 11PCh. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - Prob. 14PCh. 29 - Two nuclei having the same mass number are known...Ch. 29 - Prob. 16PCh. 29 - Radon gas has a half-life of 3.83 days. If 3.00 g...Ch. 29 - Prob. 18PCh. 29 - Prob. 19PCh. 29 - Prob. 20PCh. 29 - Prob. 21PCh. 29 - Prob. 22PCh. 29 - Prob. 23PCh. 29 - Prob. 24PCh. 29 - Prob. 25PCh. 29 - Prob. 26PCh. 29 - Prob. 27PCh. 29 - Prob. 28PCh. 29 - The Mass of 56Fe is 55.934 9 u, and the mass of...Ch. 29 - Prob. 30PCh. 29 - Prob. 31PCh. 29 - Prob. 32PCh. 29 - Prob. 33PCh. 29 - Prob. 34PCh. 29 - Prob. 35PCh. 29 - Prob. 36PCh. 29 - Prob. 37PCh. 29 - Prob. 38PCh. 29 - Prob. 39PCh. 29 - Prob. 40PCh. 29 - Prob. 41PCh. 29 - Prob. 42PCh. 29 - Prob. 43PCh. 29 - Prob. 44PCh. 29 - Prob. 45PCh. 29 - Prob. 46PCh. 29 - Prob. 47PCh. 29 - Prob. 48PCh. 29 - Prob. 49PCh. 29 - Prob. 50PCh. 29 - Prob. 51APCh. 29 - Prob. 52APCh. 29 - Prob. 53APCh. 29 - Prob. 54APCh. 29 - Prob. 55APCh. 29 - Prob. 56APCh. 29 - Prob. 57APCh. 29 - Prob. 58APCh. 29 - Prob. 59APCh. 29 - Prob. 60APCh. 29 - Prob. 61APCh. 29 - Prob. 62AP
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- Each of the following reactions is missing a single particle. Identify the missing particle for each reaction. p+pn+? p+pp+0+? ?+p+? K+n0+? +e++ve+? (f)ve+pn+?arrow_forwardThis problem demonstrates that the binding energy of the electron in the ground state of a hydrogen atom is much smaller than the rest mass energies of the proton and electron. Calculate the mass equivalent in u of the 13.6-eV binding energy of an electron in a hydrogen atom, and compare this with the known mass of the hydrogen atom. Subtract the known mass of the proton from the known mass of the hydrogen atom. Take the ratio of the binding energy of the electron (13.6 eV) to the energy equivalent of the electron’s mass (0.511 MeV). Discuss how your answers confirm the stated purpose of this problem.arrow_forwardFor the following reaction, what is the energy released, in GJ/mol? (1 GJ = 1E9 J) Use 2.998E8 m/s as the speed of light 1 a m u has a mass of 1.6605E-27 kg A + 1n → C + D A n C D mass (amu) 6.1450 1.0087 3.0221 4.0834 Express your answer as a positive valuearrow_forward
- The indium isotope 115/49 I n captures an electron and becomes the cadmium isotope 115/48 C d, as shown in the nuclear reaction below. 115/49 I n + ? ⟶ 115/48 C d What kind of particle is emitted in this decay, as denoted by the question mark?arrow_forwardb & carrow_forwardc) The equation below describes the disintegration of a polonium nucleus into a lead nucleus and an alpha-particle. During the reaction energy Q is released. 210Po → He +²02Pb+Q 84 82 Calculate the loss of energy during the reaction. The masses in the atomic mass unit u are as follows: 210 206 Po= 209.98287 u, Pb = 205.97446 u and He = 4.002604 u. 84 82 You may assume that 1u is equivalent to 931 MeV. d) The lead nucleus recoils in the opposite direction to the emitted alpha particle conserving momentum. Hence calculate: i) The ratio of the recoil nucleus and alpha particle velocities ii) The kinetic energy distribution of these products.arrow_forward
- What amount of extra kinetic energy will be released in the reaction n + 235U → 93RB + 9³Rb+ 141 Cs + 2 n? In other words, what is the Q-value of the reaction? The mass of 93Rb is 92.9217 u, the mass of 14 Cs is 140.919 u, the mass of 235U is 235.044 u and the mass of n is 1.00867 u. The 2 value of c² is 931.5 MeV/u. Answer in units of MeV.arrow_forwardHelp.arrow_forwardNuclear Fission: 1. n+ 2U → ? + 3gSr + 2n 2. n+ 235U → 1I 137 + 33Y+ ?narrow_forward
- Complete the following reactions. (a) µ- + p → n + ? (b) n + p → ∑0 + n + ?arrow_forwardC → ?+e¯+ū Fill in the missing isotope for the following decay process. 14N A He D Be 14B Earrow_forwardComplete the following nuclear reactions. (a) ?+ 14 / 7 N → 1 / 1 H + 17 / 8 O (b) 7 / 3 Li + 1 / 1 H → 4 / 2 He + ?arrow_forward
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