COLLEGE PHYSICS,V.2
COLLEGE PHYSICS,V.2
11th Edition
ISBN: 9781305965522
Author: SERWAY
Publisher: CENGAGE L
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Chapter 29, Problem 49P

(a)

To determine

The number of electrons emitted in a 10.0 day period.

(b)

To determine

The total energy deposited.

(c)

To determine

The absorbed dose.

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A patient swallows a radiopharmaceutical tagged with phosphorus-32 (P), a ߯ emitter with a half-life of 14.3 days. The average kinetic energy of the emitted electrons is 7.00 x 10² keV. If the initial activity of the sample is 1.31 MBq, determine (a) the number of electrons emitted in a 10.0-day period, (b) the total energy deposited in the body during the 10.0 days, and (c) the absorbed dose if the electrons are com- pletely absorbed in 1 × 10² g of tissue.
Iodine-131 is a beta-emitter, which decay by the first-order rate law with a half-life of 8.0 days. What is the activity in cps (counts per second) of 25.0 ng (2.5 x 10–8 g) sample of 131I (atomic mass = 131 g/mol)? (Avogadro’s #, NA = 6.02 x 1023/mol) (A) 1.2 x 108 cps           (B) 1.5 x 1010 cps           (C) 1.0 x 1011 cps           (D) 4.1 x 1011 cps
Cobalt-60 and iodine-131 are used in treatments for some types of cancer. Cobalt-60 decays with a half-life of 5.27 years, emitting beta particles with a maximum energy of 0.32 MeV. Iodine-131 decays with a half-life of8.04 days, emitting beta particles with a maximumenergy of 0.60 MeV.(a) Suppose a fixed small number of moles of each of these isotopes were to be ingested and remain in the body indefinitely. What is the ratio of the number of millisieverts of total lifetime radiation exposure that would be caused by the two radioisotopes?(b) Now suppose that the contact with each of these isotopes is for a fixed short period, such as 1 hour. What is the ratio of millisieverts of radiation exposure for the two in this case?

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COLLEGE PHYSICS,V.2

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