Explanation Given info: The potential difference is 25.0 kV . Write the expression to calculate the work potential energy of electron. E = e V Here, E is the work potential energy of electron. e is the charge on electron. V is the potential difference. Substitute 1.6 × 10 − 19 C for e and 25.0 kV for V in above expression. E = 1.6 × 10 − 19 C × 25 kV × 1000 V 1 kV = 4 × 10 − 15 J Thus, the potential energy of electron is 4 × 10 − 15 J . Write the expression to calculate the Kinetic Energy of Electron with the help of relativistic approach. ( 1 1 − v ′ 2 c 2 − 1 ) m c 2 = E v ′ = c 1 − ( E m c 2 + 1 ) − 2 Substitute 9.1 × 10 − 31 kg for m , 3 × 10 8 m / s for c and 4 × 10 − 15 J for E in above expression

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ISBN: 9780136782490

Author: Walker

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Chapter 29, Problem 89PP

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The speed of an electron considering the relativistic approach when accelerated through a voltage of 25.0 kV .

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Chapter 29, Problem 88PP

Chapter 29, Problem 90PP

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The speed of an electron considering the relativistic approach when accelerated through a voltage of 25.0 kV .

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The speed of an electron considering the relativistic approach when accelerated through a voltage of 25.0 kV .

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