Explanation Given info: The potential difference is 25.0 kV . Write the expression to calculate the work potential energy of electron. E = e V Here, E is the work potential energy of electron. e is the charge on electron. V is the potential difference. Substitute 1.6 × 10 − 19 C for e and 25.0 kV for V in above expression. E = 1.6 × 10 − 19 C × 25 kV × 1000 V 1 kV = 4 × 10 − 15 J Thus, the potential energy of electron is 4 × 10 − 15 J . Write the expression to calculate the Kinetic Energy of Electron. 1 2 m v 2 = E v = 2 E m Here, m is the mass of electron. v is the final speed of electron. E is the work potential energy of electron. Substitute 9.1 × 10 − 31 kg for m and 4 × 10 − 15 J for E in above expression

Modified Mastering Physics with Pearson eText -- Access Card -- for Physics (18-Weeks)

5th Edition

ISBN: 9780136781356

Author: Walker, JAMES

Publisher: PEARSON

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Chapter 29, Problem 87PP

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The speed of an electron accelerated through a voltage of 25.0 kV .

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Chapter 29, Problem 86GP

Chapter 29, Problem 88PP

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Modified Mastering Physics with Pearson eText -- Access Card -- for Physics (18-Weeks)

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The speed of an electron accelerated through a voltage of 25.0 kV .

Solution Summary: The author explains how to determine the speed of an electron accelerated through a voltage of 0.312c.

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The speed of an electron accelerated through a voltage of 25.0 kV .

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Chapter 29 Solutions