Physics for Scientists and Engineers with Modern Physics, Technology Update
9th Edition
ISBN: 9781305401969
Author: SERWAY, Raymond A.; Jewett, John W.
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 29, Problem 62AP
(a)
To determine
The radius of curvature of the path the proton follows when it enters the region of the field.
(b)
To determine
To explain: The proton will arrive at the center of cylinder or not.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Within a cylindrical region of space of radius 100 Mm, a magnetic field is uniform with a magnitude 25.0 μT and oriented parallel to the axis of the cylinder. The magnetic field is zero outside this cylinder. A cosmic-ray proton traveling at one-tenth the speed of light is heading directly toward the center of the cylinder, moving perpendicular to the cylinder’s axis. (a) Find the radius of curvature of the path the proton follows when it enters the region of the field. (b) Explain whether the proton will arrive at the center of the cylinder.
Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and then injected into a region of constant magnetic field with a field strength of 0.45 T.
1. What is the potential difference, in volts, required in the first part of the experiment to accelerate electrons to a speed of 6.1 × 107 m/s?
2. Find the radius of curvature, in meters, of the path of a proton accelerated through this same potential after the proton crosses into the region with the magnetic field.
3. What is the ratio of the radii of curvature for a proton and an an electron traveling through this apparatus?
An electron beam is directed horizontally into a region where there is both an electric field and a magnetic field. The electric field points upward with a magnitude EE = 2.9 N/C, as shown in the figure. While moving through the region, the electron beam remains directed in a straight, horizontal line with a speed of 460 m/s.
1.) Express the magnitude of the electric force using the electric field E and the elementary charge e.
2.) Calculate the numerical value of the magnitude of the electric force in newtons.
3.) Express the magnitude of the magnetic force in terms of the elementary charge ee, electron speed vv, and BB, the magnitude of the magnetic field.
4.) If the electron is continuing in a horizontal straight line, express the magnitude of the magnetic field in terms of vv and EE, B = ?
5.) Calculate the magnitude of the magnetic field in tesla, if the electron continues in a horizontal straight line.
5.)
Chapter 29 Solutions
Physics for Scientists and Engineers with Modern Physics, Technology Update
Ch. 29.1 - An electron moves in the plane of this paper...Ch. 29.2 - Prob. 29.2QQCh. 29.4 - A wire carries current in the plane of this paper...Ch. 29.5 - (i) Rank the magnitudes of the torques acting on...Ch. 29 - Prob. 1OQCh. 29 - Prob. 2OQCh. 29 - Prob. 3OQCh. 29 - Prob. 4OQCh. 29 - Prob. 5OQCh. 29 - Prob. 6OQ
Ch. 29 - Prob. 7OQCh. 29 - Prob. 8OQCh. 29 - Prob. 9OQCh. 29 - Prob. 10OQCh. 29 - Prob. 11OQCh. 29 - Prob. 12OQCh. 29 - Prob. 13OQCh. 29 - Prob. 1CQCh. 29 - Prob. 2CQCh. 29 - Prob. 3CQCh. 29 - Prob. 4CQCh. 29 - Prob. 5CQCh. 29 - Prob. 6CQCh. 29 - Prob. 7CQCh. 29 - At the equator, near the surface of the Earth, the...Ch. 29 - Prob. 2PCh. 29 - Prob. 3PCh. 29 - Consider an electron near the Earths equator. In...Ch. 29 - Prob. 5PCh. 29 - A proton moving at 4.00 106 m/s through a...Ch. 29 - Prob. 7PCh. 29 - Prob. 8PCh. 29 - A proton travels with a speed of 5.02 106 m/s in...Ch. 29 - Prob. 10PCh. 29 - Prob. 11PCh. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - An accelerating voltage of 2.50103 V is applied to...Ch. 29 - A proton (charge + e, mass mp), a deuteron (charge...Ch. 29 - Prob. 16PCh. 29 - Review. One electron collides elastically with a...Ch. 29 - Review. One electron collides elastically with a...Ch. 29 - Review. An electron moves in a circular path...Ch. 29 - Prob. 20PCh. 29 - Prob. 21PCh. 29 - Prob. 22PCh. 29 - Prob. 23PCh. 29 - A cyclotron designed to accelerate protons has a...Ch. 29 - Prob. 25PCh. 29 - Prob. 26PCh. 29 - A cyclotron (Fig. 28.16) designed to accelerate...Ch. 29 - Prob. 28PCh. 29 - Prob. 29PCh. 29 - Prob. 30PCh. 29 - Prob. 31PCh. 29 - Prob. 32PCh. 29 - Prob. 33PCh. 29 - Prob. 34PCh. 29 - A wire carries a steady current of 2.40 A. A...Ch. 29 - Prob. 36PCh. 29 - Prob. 37PCh. 29 - Prob. 38PCh. 29 - Prob. 39PCh. 29 - Consider the system pictured in Figure P28.26. A...Ch. 29 - Prob. 41PCh. 29 - Prob. 42PCh. 29 - Prob. 43PCh. 29 - Prob. 44PCh. 29 - Prob. 45PCh. 29 - A 50.0-turn circular coil of radius 5.00 cm can be...Ch. 29 - Prob. 47PCh. 29 - Prob. 48PCh. 29 - Prob. 49PCh. 29 - Prob. 50PCh. 29 - Prob. 51PCh. 29 - Prob. 52PCh. 29 - Prob. 53PCh. 29 - A Hall-effect probe operates with a 120-mA...Ch. 29 - Prob. 55PCh. 29 - Prob. 56APCh. 29 - Prob. 57APCh. 29 - Prob. 58APCh. 29 - Prob. 59APCh. 29 - Prob. 60APCh. 29 - Prob. 61APCh. 29 - Prob. 62APCh. 29 - Prob. 63APCh. 29 - Prob. 64APCh. 29 - Prob. 65APCh. 29 - Prob. 66APCh. 29 - A proton having an initial velocity of 20.0iMm/s...Ch. 29 - Prob. 68APCh. 29 - Prob. 69APCh. 29 - Prob. 70APCh. 29 - Prob. 71APCh. 29 - Prob. 72APCh. 29 - Prob. 73APCh. 29 - Prob. 74APCh. 29 - Prob. 75APCh. 29 - Prob. 76APCh. 29 - Prob. 77CPCh. 29 - Prob. 78CPCh. 29 - Review. A wire having a linear mass density of...Ch. 29 - Prob. 80CP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A particle moving downward at a speed of 6.0106 m/s enters a uniform magnetic field that is horizontal and directed from east to west. (a) If the particle is deflected initially to the north in a circular arc, is its charge positive or negative? (b) If B = 0.25 T and the charge-to-mass ratio (q/m) of the particle is 40107 C/kg. what is ±e radius at the path? (c) What is the speed of the particle after c has moved in the field for 1.0105s ? for 2.0s?arrow_forwardA long, straight, horizontal wire carries a left-to-right current of 20 A. If the wire is placed in a uniform magnetic field of magnitude 4.0105 T that is directed vertically downward, what is tire resultant magnitude of the magnetic field 20 cm above the wire? 20 cm below the wire?arrow_forward(a) A cosmic ray proton moving toward Earth at 5.00107 m/s experiences a magnetic force of 1.70l0l6 N. What is the strength of the magnetic field if there is a 45 angle between it and the proton’s velocity? (b) Is the value obtained in part a. consistent with the known strength of Earth's magnetic field on its surface? Discuss.arrow_forward
- Two long coaxial copper tubes, each of length L, are connected to a battery of voltage V. The inner tube has inner radius o and outer radius b, and the outer tube has inner radius c and outer radius d. The tubes are then disconnected from the battery and rotated in the same direction at angular speed of radians per second about their common axis. Find the magnetic field (a) at a point inside the space enclosed by the inner tube r d. (Hint: Hunk of copper tubes as a capacitor and find the charge density based on the voltage applied, Q=VC, C=20LIn(c/b) .)arrow_forwardIn Figure P22.43, the current in the long, straight wire is I1 = 5.00 A and the wire lies in the plane of the rectangular loop, which carries a current I2 = 10.0 A. The dimensions in the figure are c = 0.100 m, a = 0.150 m, and = 0.450 m. Find the magnitude and direction of the net force exerted on the loop by the magnetic field created by the wire. Figure P22.43 Problems 43 and 44.arrow_forwardThe velocity vector of a singly charged helium ion (mHe = 6.64 1027 kg) is given by v=4.50105m/s. The acceleration of the ion in a region of space with a uniform magnetic field is 8.50 1012 m/s2 in the positive y direction. The velocity is perpendicular to the field direction. What are the magnitude and direction of the magnetic field in this region?arrow_forward
- Calculate the magnitude of the magnetic field at a point 25.0 cm from a long, thin conductor carrying a current of 2.00 A.arrow_forwardA proton travels with a speed of 3.00 106 m/s at an angle of 37.0 with the direction of a magnetic field of 0.300 T in the +y direction. What are (a) the magnitude of the magnetic force on the proton and (b) its acceleration?arrow_forwardA wire, of length L = 3.8 mm, on a circuit board carries a current of I = 2.36 μA in the j direction. A nearby circuit element generates a magnetic field in the vicinity of the wire of B = Bxi + Byj + Bzk, where Bx = 5.2 G, By = 5.8 G, and Bz = 5.6 G. a) Calculate the magnitude of the magnetic field B, in gauss, in the vicinity of the wire due to the circuit element. Part (b) Calculate the i component of the magnetic force Fx, in newtons, exerted on the wire by the magnetic field due to the circuit element. Part (c) Calculate the j component of the magnetic force Fy, in newtons, exerted on the wire by the magnetic field due to the circuit element. Part (d) Calculate the k component of the magnetic force Fz, in newtons, exerted on the wire by the magnetic field due to the circuit element. Part (e) Calculate the magnitude of the magnetic force F, in newtons, exerted on the wire by the magnetic field due to the circuit element Part (f) If you simply multiply the…arrow_forward
- A proton moves through a uniform electric field given by vector E = 50.0 j hat V/m and a uniform magnetic field vector B = (0.200 i hat+ 0.300 j hat+ 0.400 k hat) T. Determine the acceleration of the proton when it has a velocity vector v = 200 i m/sarrow_forwardA straight, vertical wire carries a current of 2.15 A downward in a region between the poles of a large superconducting electromagnet, where the magnetic field has a magnitude of B = 0.554 T and is horizontal. What is the magnitude of the magnetic force on a 1.00 cm section of the wire that is in this uniform magnetic field, if the magnetic field direction is 30.0° south of west? Express your answer with the appropriate units. F = Submit Part F ゆ 6 = μÅ Submit Value What is the direction of this magnetic force? Express your answer in degrees. Request Answer — ΑΣΦ Units Request Answer ? ? O north of westarrow_forwardAn electron moves through a uniform electric field E = (2.00î + 4.60ĵ) V/m and a uniform magnetic field B = 0.400 T. Determine the acceleration of the electron when it has a velocity v = 8.0î m/s. (Give each component in m/s2.) What If? For the electron moving along the x-axis in the fields in part (a), what speed (in m/s) would result in the electron also experiencing an acceleration directed along the x-axis?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
- College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Magnets and Magnetic Fields; Author: Professor Dave explains;https://www.youtube.com/watch?v=IgtIdttfGVw;License: Standard YouTube License, CC-BY