Explanation Given info: E = 1.0 × 10 − 5 eV= 1.0 × 10 − 5 × 1.6 × 10 − 19 = 1.6 × 10 − 24 J h = 6.6 × 10 − 34 Js c =3 × 10 8 m/s Formula used: The energy of a photon is given by, E = h f Here, f is frequency and h is planks constant. The frequency is given by, f = c λ Therefore energy, E = h c λ Calculation: Substituting the given values in formula, E = h c λ , we get 1.6 × 10 − 24 J = 6.6 × 10 − 34 Js × 3 × 10 8 m/s λ ⇒ λ = 6

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Chapter 29 Solutions

College Physics

Ch. 29 - Give an example of a physical entity that is...Ch. 29 - Give an example of a physical entity that is not...Ch. 29 - What aspect of the blackbody spectrum forced...Ch. 29 - If Planck's constant were large, say 1034 times...Ch. 29 - Why don't we notice quantization in everyday...Ch. 29 - Is visible light the only type of EM radiation...Ch. 29 - Which aspects of the photoelectric effect cannot...Ch. 29 - Is the photoelectric effect a direct consequence...Ch. 29 - Insulators (nonmetals) have a higher BE than...Ch. 29 - If you pick up and shake a piece of metal that has...

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Solution Summary: The author calculates the energy of a photon by substituting the given values in formula.

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