Mindtap For Herman's Delmar's Standard Textbook Of Electricity, 2 Terms Printed Access Card (mindtap Course List)
7th Edition
ISBN: 9781337900621
Author: Stephen L. Herman
Publisher: Cengage Learning
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Chapter 29, Problem 4RQ
To determine
The type of armature winding to be used for a machine intended for high-voltage, low-current operation.
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Find the overall impedance of the followingP=1000W pf=0.8(leading) Vrms=220VThe overall impedance in complex form R+jX
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Chapter 29 Solutions
Mindtap For Herman's Delmar's Standard Textbook Of Electricity, 2 Terms Printed Access Card (mindtap Course List)
Ch. 29 - What is a generator?Ch. 29 - Prob. 2RQCh. 29 - Prob. 3RQCh. 29 - Prob. 4RQCh. 29 - What are interpoles, and what is their purpose?Ch. 29 - How are interpoles connected in relation to the...Ch. 29 - Prob. 7RQCh. 29 - How is the series field connected in relation to...Ch. 29 - How is the shunt field connected in relation to...Ch. 29 - What is armature reaction?
Ch. 29 - What is armature reaction proportional to?Ch. 29 - What are eddy currents?Ch. 29 - What condition characterizes overcompounding?Ch. 29 - What is the function of the shunt field rheostat?Ch. 29 - Explain the difference between cumulative- and...Ch. 29 - Explain the difference between cumulative- and...Ch. 29 - What three factors determine the amount of output...Ch. 29 - What is the voltage regulation of a DC generator...Ch. 29 - Prob. 19RQCh. 29 - Prob. 20RQCh. 29 - You are working as an electrician in a large steel...
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- DO NOT USE AI NEED HANDWRITTEN SOLUTIONarrow_forwardEach branch of a three-phase star-connected load consists of a coil of resistance 4.2 Ω and reactance 5.6 Ω. The load is supplied at a line voltage of 400 V, 50 Hz. The total active power supplied to the load is measured by the two-wattmeter method. Draw a circuit diagram of the wattmeter connections and calculate their separate readings. Derive any formula used in your calculations. ANS: 13.1 kW, 1.71 kWarrow_forwardThree non-reactive loads are connected in delta across a three-phase, three-wire, 400 V supply in the following way: (i) 10 kW across R and Y lines; (ii) 6 kW across Y and B lines; (iii) 4 kW across B and R lines. Draw a phasor diagram showing the three line voltages and the load currents and determine: (a) the current in the B line and its phase relationship to the line voltage VBR; (b) the reading of a wattmeter whose current coils are connected in the B line and whose voltage circuit is connected across the B and R lines. The phase rotation is R–Y–B. Where would a second wattmeter be connected for the two-wattmeter method and what would be its reading? ANS: 21.8 A, 36°35′ lagging; 7 kW; 13 kWarrow_forward
- NEED HANDWRITTEN SOLUTION DO NOT USE AI OR CHATGPTarrow_forwardA factory has the following load with power factor of 0.85 lagging in each phase. Between the red and yellow phases 40 A, between the yellow and blue phases 50 A, and between the blue and red phases 60 A. If the supply is 415 V, three-phase, calculate the line currents. Draw a phasor diagram for phase and line quantities. Ensure to draw all necessary diagrams ANS: IR = 87.178<-68.380 A; IY = 78.102<-178.120 A; IB = 95.394<61.210 A.arrow_forwardAnswer question D only using by hand first darw cylinder then calculate show me starrow_forward
- The phase currents in a delta-connected three-phase load are as follows: between the red and yellow lines, 30 A at p.f. 0.707 leading; between the yellow and blue lines, 20 A at unity p.f.; between the blue and red lines, 25 A at p.f. 0.866 lagging. Calculate the line currents and draw the complete phasor diagram. ANS: 21.6 A in R, 49.6 A in Y, 43.5 A in Barrow_forward. Two wattmeters connected to measure the input to a balanced three-phase circuit indicate 2500 W and 500 W respectively. Find the power factor of the circuit: (a) when both readings are positive; (b) when the latter reading is obtained after reversing the con nections to the current-coil of one instrument. Draw the phasor and connection diagrams. ANS: 0.655, 0.359arrow_forwardExplain the advantage of connecting the low-voltage winding of distribution transformers in star. A factory has the following load with power factor of 0.9 lagging in each phase. Red phase 40 A, yellow phase 50 A and blue phase 60 A. If the supply is 400 V, three phase, four-wire, calculate the current in the neutral and the total active power. Draw a phasor diagram for phase and line quantities. Assume that, relative to the current in the red phase, the current in the yellow phase lags by 120° and that in the blue phase leads by 120°. ANS: 17.3 A, 31.2 kWarrow_forward
- A three-phase, 400 V system has the following load connected in delta: between the red and yellow lines, a non-reactive resistor of 100 Ω; between the yellow and blue lines, a coil having a reactance of 60 Ω and negligible resistance; between the blue and red lines, a loss-free capacitor having a reactance of 130 Ω. Calculate: (a) the phase currents; (b) the line currents. Assume the phase sequence to be R–Y, Y–B and B–R. Also, draw the complete phasor diagram. ANS: 4.00 A, 6.67 A, 3.08 A, 6.85 A, 10.33 A, 5.8 Aarrow_forwardWith the aid of a circuit diagram, show that two wattmeters can be connected to read the total power in a three-phase, three-wire system. Two wattmeters connected to read the total power in a three-phase system supplying a balanced load read 10.5 kW and −2.5 kW respectively. Calculate the total active power. Drawing suitable phasor diagrams, explain the significance of: (a) equal wattmeter readings; (b) a zero reading on one wattmeter. ANS: 8 kWarrow_forwardA factory has the following load with power factor of 0.9 lagging in each phase. Red phase 40 A, yellow phase 50 A and blue phase 60 A. If the supply is 400 V, three-phase, four-wire, calculate the current in the neutral and the total active power. Draw a phasor diagram for phase and line quantities. Assume that, relative to the current in the red phase, the current in the yellow phase lags by 120° and that in the blue phase leads by 120°.arrow_forward
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