Explanation Given: The magnitude of component force F 1 = 200 lb . The magnitude of component force F 2 = 400 lb . The magnitude of component force F 3 = 300 lb . The magnitude of component force F 4 = 300 lb . Show the free body diagram of the magnitude of component forces F 1 , F 2 , F 3 and F 4 into x and y axis components as in Figure (1). Express the magnitude of component force F 1 along the x direction using Figure (1). ( F 1 ) x = F 1 (I) Express the magnitude of component force F 1 along the y direction using Figure (1). ( F 1 ) y = 0 Express the magnitude of component force F 2 along the x direction using Figure (1). ( F 2 ) x = F 2 cos θ (II) Express the magnitude of component force F 2 along the y direction using Figure (1). ( F 2 ) y = F 2 sin θ (III) Use Figure (1) to find out the cos θ and sin θ . cos θ = 4 5 sin θ = 3 5 Express the magnitude of component force F 3 along the x direction using Figure (1). ( F 3 ) x = F 3 sin θ (IV) Express the magnitude of component force F 3 along the y direction using Figure (1). ( F 3 ) y = F 3 cos θ (V) Express the magnitude of component force F 4 along the x direction using Figure (1). ( F 4 ) x = F 4 (VI) Express the magnitude of component force F 4 along the y direction using Figure (1). ( F 4 ) y = 0 Express the magnitude of the resultant force that is measured counterclockwise from the positive x axis using Figure (1). + → ( F R ) x = ∑ F x ( F R ) x = ( F 1 ) x + ( F 2 ) x + ( F 3 ) x + ( F 4 ) x (VII) Express the magnitude of the resultant force that is measured counterclockwise from the positive y axis using Figure (1). + → ( F R ) y = ∑ F y ( F R ) y = ( F 1 ) y + ( F 2 ) y + ( F 3 ) y + ( F 4 ) y (VIII) Calculate the magnitude of the resultant force F R that is measured counterclockwise from the positive x axis. F R = ( F R ) x 2 + ( F R ) y 2 (IX) Conclusion: Substitute − 200 lb for F 1 in Equation (I)

Engineering Mechanics: Statics & Dynamics, Student Value Edition Plus Modified Mastering Engineering Revision with Pearson eText -- Access Card Package

14th Edition

ISBN: 9780135841532

Author: HIBBELER, Russell , HIBBLER

Publisher: PEARSON

See similar textbooks

Videos

Question

Chapter 2.9, Problem 3RP

To determine

The magnitude of the resultant force acting on the gusset plate of the bridge truss (FR).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 2.9, Problem 2RP

Chapter 2.9, Problem 4RP

Students have asked these similar questions

Q4/ A compressor is driven motor by mean of a flat belt of thickness 10 mm and a width of 250 mm. The motor pulley is 300 mm diameter and run at 900 rpm and the compressor pulley is 1500 mm diameter. The shaft center distance is 1.5 m. The angle of contact of the smaller pulley is 220° and on the larger pulley is 270°. The coefficient of friction between the belt and the small pulley is 0.3, and between the belt and the large pulley is 0.25. The maximum allowable belt stress is 2 MPa and the belt density is 970 kg/m³. (a) What is the power capacity of the drive and (b) If the small pulley replaced by V-grooved pulley of diameter 300 mm, grooved angle of 34° and the coefficient of friction between belt and grooved pulley is 0.35. What will be the power capacity in this case, assuming that the diameter of the large pulley remain the same of 1500 mm.

You are tasked with designing a power drive system to transmit power between a motor and a conveyor belt in a manufacturing facility as illustrated in figure. The design must ensure efficient power transmission, reliability, and safety. Given the following specifications and constraints, design drive system for this application: Specifications: Motor Power: The electric motor provides 10 kW of power at 1,500 RPM. Output Speed: The output shaft should rotate at 150 rpm. Design Decisions: Transmission ratio: Determine the necessary drive ratio for the system. Shaft Diameter: Design the shafts for both the motor and the conveyor end. Material Selection: Choose appropriate materials for the gears, shafts. Bearings: Select suitable rolling element bearings. Constraints: Space Limitation: The available space for the gear drive system is limited to a 1-meter-long section. Attribute 4 of CEP Depth of knowledge required Fundamentals-based, first principles analytical approach…

- | العنوان In non-continuous dieless drawing process for copper tube as shown in Fig. (1), take the following data: Do-20mm, to=3mm, D=12mm, ti/to=0.6 and v.-15mm/s. Calculate: (1) area reduction RA, (2) drawing velocity v. Knowing that: ti: final thickness V. Fig. (1) ofthre

Chapter 2 Solutions

Engineering Mechanics: Statics & Dynamics, Student Value Edition Plus Modified Mastering Engineering Revision with Pearson eText -- Access Card Package

Ch. 2.3 - In each case, construct the parallelogram law to...Ch. 2.3 - In each case, show how to resolve the force F into...Ch. 2.3 - Determine the magnitude of the resultant force...Ch. 2.3 - Two forces act on the hook. Determine the...Ch. 2.3 - Determine the magnitude of the resultant force and...Ch. 2.3 - Resolve the 30-lb force into components along the...Ch. 2.3 - The force F = 450 lb acts on the frame. Resolve...Ch. 2.3 - If force F is to have a component along the u axis...Ch. 2.3 - If = 60 and F = 450 N, determine the magnitude of...Ch. 2.3 - If the magnitude of the resultant force is to be...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

The magnitude of the resultant force acting on the gusset plate of the bridge truss ( F R ) .

Solution Summary: The author explains how to determine the magnitude of the resultant force acting on the gusset plate of a bridge truss.

Videos

The magnitude of the resultant force acting on the gusset plate of the bridge truss (FR).

Want to see the full answer?

Chapter 2 Solutions