
Concept explainers
Classify each of die following statements as a characteristic (a) of electric forces only, (b) of magnetic forces only, (c) of both electric and magnetic forces, or (d) of neither electric nor magnetic forces. (i) The force is proportional to the magnitude of the field exerting it. (ii) The force is proportional to the magnitude of the charge of the object on which the force is exerted. (iii) The force exerted on a negatively charged object is opposite in direction to the force on a positive charge. (iv) The force exerted on a stationary charged object is nonzero. (v) The force exerted on a moving charged object is zero. (vi) The force exerted on a charged object is proportional to its speed. (vii) The force exerted on a charged object cannot alter the object’s speed. (viii) The magnitude of the force depends on the charged object’s direction of motion.
(i)

The forces which are proportional to the magnitude of their respective fields.
Answer to Problem 29.8OQ
Option(c) of both electric and magnetic forces.
Explanation of Solution
The expression for electrical force is,
Here,
Increase the electric field, the force on the charge will also increase proportional to it.
The expression for magnetic force is,
Here,
Increase the magnetic field with same speed on same charge in the same direction, the force on the charge will also increase proportional to it.
Conclusion:
The electric force is proportional to the electric field and the magnetic force is proportional to the magnetic field. Both electric and magnetic forces are proportional to their respective fields but option (a) includes only electric force. Thus, option (a) is incorrect.
The magnetic force is proportional to the magnetic field and the electric force is proportional to the electric field. Both the forces are proportional to their respective fields but option (b) includes only magnetic force. Thus, option (b) is incorrect.
Both the forces are proportional to their respective fields. Thus option (c) is correct.
The exerted forces in magnetic field as well as electric field are proportional to their respective field that contradicts the option (d). Thus, option (d) is incorrect.
(ii)

The forces proportional to the magnitude of the charge.
Answer to Problem 29.8OQ
Option (c) both electric and magnetic forces
Explanation of Solution
The expression for electrical force is,
Increase the magnitude of charge, the force on the charge will also increase proportional to it.
The expression for magnetic force is
Increase the magnitude of charge with same speed and in the same field, in the same direction, the force on the charge will also increase proportional to it.
Conclusion:
The electric force is proportional to the magnitude of charge and the magnetic force is also proportional to magnitude of charge. Both electric and magnetic forces are proportional to the magnitude of charge but option (a) includes only electric force. Thus, option (a) is incorrect.
The magnetic force is proportional to the magnitude of charge and also the electric force is proportional to magnitude of charge .Both the forces are proportional to the magnitude of charge but option (b) only magnetic force. Thus, option (b) is incorrect.
Both the forces are proportional to the magnitude of charge. Thus option (c) is correct.
The exerted forces in magnetic field as well as electric field are proportional to the magnitude of charge that contradicts the option (d). Thus, option (d) is incorrect.
(iii)

The forces which exert force on a negatively charged particle in opposite direction to the force on a positively charged particle.
Answer to Problem 29.8OQ
Option (c) both electric and magnetic forces.
Explanation of Solution
The electric force on a positively charged particle is
Here
The electric force on a negatively charged particle is
Here
From equation (1) and equation (2),
Thus, electric force on the same magnitude of electric charge of opposite nature are equal but opposite in direction.
The magnetic force on a positively charged particle is,
Here
The magnetic force on a negatively charged particle is,
Here,
From equation (3) and (4),
Thus, magnetic force on the same magnitude of electric charge moving with same speed but of opposite nature are equal but opposite in direction.
Conclusion:
Both magnetic force and electric force exert force on negative charge in the opposite direction to the force on positive charge but option (a) includes only electric force. Thus, option (a) is incorrect.
Both magnetic force and electric force exert force on negative charge in the opposite direction to the force on positive charge but option (b) includes only magnetic force. Thus option (b) is incorrect.
Both magnetic force and electric force exert force on negative charge in the opposite direction to the force on positive charge. Thus, option (c) is correct.
Both the forces exert force on negative charge in the opposite direction to the force on positive charge that contradicts the option (d). Thus, option (d) is incorrect.
(iv)

The forces which are non-zero on a stationary object.
Answer to Problem 29.8OQ
Option (a) only electric forces exert non-zero force on stationary object.
Explanation of Solution
The expression for electrical force is,
There is no relation between motion of charged object and electric field because electric field exists for all orientations of charges, whether it is stationary or in motion.
The expression for magnetic force is,
Magnetic force exists only when charges are in motion. Thus for stationary charges the magnetic force is not valid.
Conclusion:
Electrical force is valid for any particle that has charge; it is fundamental force in nature. Thus, option (a) is correct.
Magnetic field is existence for any charged particle in motion. Stationary charged particles have zero magnetic force. Thus option (b) is incorrect.
For a stationary charge only electric force is non-zero and magnetic force is zero that contradicts the option (c). Thus, option (c) is incorrect.
For a stationary charge only electric force is non-zero and magnetic field is zero which is contradictory to the option (d). Thus, option (d) is incorrect.
(v)

The forces which are zero on a moving charge.
Answer to Problem 29.8OQ
Option (d) neither electric nor magnetic force.
Explanation of Solution
The expression for electrical force is,
There is no relation between motion of charged object and electric field because electric field exists for all orientations of charges, whether it is stationary or in motion. If electric field exists then there is a non-zero force on the charged object.
The expression for magnetic force is,
Magnetic force exists only when charges are in motion. Thus for moving charges the magnetic force may be zero if the charge moves either in the direction of the magnetic field or opposite to it.
Conclusion:
Electrical force is valid for any particle that has charge; it is fundamental force in nature. Thus, option (a) is incorrect.
Magnetic field is existence for any charged object in motion. Moving charged objects may have zero magnetic force if the charged object moves along or against the direction of the magnetic field. Thus, option (b) is incorrect.
For a moving charge, electric force is non-zero but the magnetic force may or may not be zero that contradicts the option (c). Thus, option (c) is incorrect.
For a moving charge only electric force is non-zero and magnetic force may or may not be zero. Thus option (d) is correct.
(vi)

The forces proportional to the speed of the charged object.
Answer to Problem 29.8OQ
option (b) magnetic forces only.
Explanation of Solution
The expression for electrical force is,
There is no relation between motion of charged object and the electric field force.
The expression for magnetic force is,
The magnetic force exists only if there is motion and is directly proportional to the speed of the charged particle.
Conclusion:
The electric force exerted on the charged object has no relation with its motion. Thus option (a) is incorrect.
The magnetic force is exerted on a body in motion and is directly proportional to the speed of the object. Thus option (b) is correct.
The electric force exerted on the charged object has no relation with its motion while magnetic force on it is proportional to the speed of the object. Thus, option (c) is incorrect.
The electric force exerted on the charged object has no relation with its motion while magnetic force on it is proportional to the speed of the object that contradicts the option (d). Thus, option (d) is incorrect.
(vii)

The forces on the charged object which can alter its speed.
Answer to Problem 29.8OQ
Option (b) magnetic forces only.
Explanation of Solution
The expression for electrical force is,
There is no relation between motion of charged object and the electric field force.
The expression for magnetic force is,
The magnetic force acts on the perpendicular direction of the motion of the object because it is along the direction of cross product vector of
Conclusion:
There is no relation of motion of the charged object and the electric field force. Thus option (a) is incorrect.
The magnetic force has no change in the speed but it does change the direction of motion of the object. Thus option (b) is correct.
Electric forces have no relation with speed of the charged body while magnetic forces cannot alter speed of the object but it can change its direction of motion. Thus option (c) is incorrect.
Electric forces are independent of any motion of the charged object while magnetic forces can change only the direction of motion of the object. Thus option (d) is incorrect
(viii)

The force whose magnitude depends on the charged object’s direction of motion.
Answer to Problem 29.8OQ
Option (b) magnetic forces only
Explanation of Solution
The expression for electrical force is
There is no relation between motion of charged object and the electric field force.
The expression for magnetic force is
The value of
Conclusion:
The electric field has no relation with the motion of the charged object Thus option (a) is incorrect.
The variation in direction of motion varies the value of
The direction of motion of the charged object affects only the magnetic force but not electric force. Thus option (c) is incorrect as it considers both the forces.
Only the magnetic force is affected by variation in direction of motion of the charged object but not electric force. Thus option (d) is incorrect as it considers neither of the forces.
Want to see more full solutions like this?
Chapter 29 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
- The stress-strain diagram for a steel alloy is given in fig. 3. Determine the modulus of elasticity (E). σ (ksi) 40 30 20 10 0 0 0.0005 0.001 0.0015 0.002 0.0025 0.0030.0035 Earrow_forwardA Van de Graff generator, if the metal sphere on the Van de Graff has a charge of 0.14 Coulombs and the person has a mass of 62 kg, how much excess charge would the person need in order to levitate at a distance 25 cm from the center of the charged metal sphere? Assume you can treat both the person and the metal sphere as point charges a distance 25 cm from each other using Coulomb's Law to calculate the electrical force. Give your answer as the number of Coulombsarrow_forwardPlease help me answer the following question. I am having trouble understanding the directions of the things the question is asking for. Please include a detailed explanation and possibly drawings of the directions of Bsource, Binduced, and Iinduced.arrow_forward
- 43. A mass må undergoes circular motion of radius R on a hori- zontal frictionless table, con- nected by a massless string through a hole in the table to a second mass m² (Fig. 5.33). If m₂ is stationary, find expres- sions for (a) the string tension and (b) the period of the circu- lar motion. m2 R m₁ FIGURE 5.33 Problem 43arrow_forwardCH 70. A block is projected up an incline at angle 0. It returns to its initial position with half its initial speed. Show that the coefficient of ki- netic friction is μk = tano.arrow_forwardPassage Problems A spiral is an ice-skating position in which the skater glides on one foot with the other foot held above hip level. It's a required element in women's singles figure-skating competition and is related to the arabesque performed in ballet. Figure 5.40 shows Canadian skater Kaetlyn Osmond executing a spiral during her medal-winning perfor- mance at the 2018 Winter Olympics in Gangneung, South Korea. 77. From the photo, you can conclude that the skater is a. executing a turn to her left. b. executing a turn to her right. c. moving in a straight line out of the page. 78. The net force on the skater a. points to her left. b. points to her right. c. is zero. 79. If the skater were to execute the same maneuver but at higher speed, the tilt evident in the photo would be a. less. b. greater. c. unchanged. FIGURE 5.40 Passage Problems 77-80 80. The tilt angle 0 that the skater's body makes with the vertical is given ap- proximately by 0 = tan¯¹(0.5). From this you can conclude…arrow_forward
- Frictionless surfarrow_forward71. A 2.1-kg mass is connected to a spring with spring constant 72 k = 150 N/m and unstretched length 18 cm. The two are mounted on a frictionless air table, with the free end of the spring attached to a frictionless pivot. The mass is set into circular mo- tion at 1.4 m/s. Find the radius of its path. cor moving at 77 km/h negotiat CH —what's the minimum icient of frictioarrow_forward12. Two forces act on a 3.1-kg mass that undergoes acceleration = 0.91 0.27 m/s². If one force is -1.2î – 2.5ĵ N, what's the other?arrow_forward
- 36. Example 5.7: You whirl a bucket of water around in a vertical circle of radius 1.22 m. What minimum speed at the top of the circle will keep the water in the bucket?arrow_forwardPassage Problems Laptop computers are equipped with accelerometers that sense when the device is dropped and then put the hard drive into a protective mode. Your computer geek friend has written a program that reads the accel- erometer and calculates the laptop's apparent weight. You're amusing yourself with this program on a long plane flight. Your laptop weighs just 5 pounds, and for a long time that's what the program reports. But then the "Fasten Seatbelt" light comes on as the plane encounters turbu- lence. Figure 4.27 shows the readings for the laptop's apparent weight over a 12-second interval that includes the start of the turbulence. 76. At the first sign of turbulence, the plane's acceleration a. is upward. b. is downward. c. is impossible to tell from the graph. 77. The plane's vertical ac- celeration has its greatest magnitude a. during interval B. b. during interval C. c. during interval D. 78. During interval C, you can conclude for certain that the plane is Apparent…arrow_forwardIf the metal sphere on the Van de Graff has a charge of 0.14 Coulombs and the person has a mass of 62 kg, how much excess charge would the person need in order to levitate at a distance 25 cm from the center of the charged metal sphere? Assume you can treat both the person and the metal sphere as point charges a distance 25 cm from each otherarrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
- College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-HillClassical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage Learning





