EBK PHYSICS FOR SCIENTISTS AND ENGINEER
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
9th Edition
ISBN: 9780100461260
Author: SERWAY
Publisher: YUZU
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Book Icon
Chapter 29, Problem 29.8OQ

Classify each of die following statements as a characteristic (a) of electric forces only, (b) of magnetic forces only, (c) of both electric and magnetic forces, or (d) of neither electric nor magnetic forces. (i) The force is proportional to the magnitude of the field exerting it. (ii) The force is proportional to the magnitude of the charge of the object on which the force is exerted. (iii) The force exerted on a negatively charged object is opposite in direction to the force on a positive charge. (iv) The force exerted on a stationary charged object is nonzero. (v) The force exerted on a moving charged object is zero. (vi) The force exerted on a charged object is proportional to its speed. (vii) The force exerted on a charged object cannot alter the object’s speed. (viii) The magnitude of the force depends on the charged object’s direction of motion.

(i)

Expert Solution
Check Mark
To determine

The forces which are proportional to the magnitude of their respective fields.

Answer to Problem 29.8OQ

Option(c) of both electric and magnetic forces.

Explanation of Solution

The expression for electrical force is,

Fe=qE

Here,

Fe is the force on the particle due to electric field.

q is the magnitude of charge on the particle.

E is the magnitude of electric field intensity.

Increase the electric field, the force on the charge will also increase proportional to it.

FeE

The expression for magnetic force is,

Fm=qvBsinθ

Here,

Fm is the force on the particle due to magnetic field.

q is the magnitude of charge on the particle.

B is the magnitude of magnetic flux density.

θ is the angle between the motion of the particle and the magnetic field line.

Increase the magnetic field with same speed on same charge in the same direction, the force on the charge will also increase proportional to it.

FmB

Conclusion:

The electric force is proportional to the electric field and the magnetic force is proportional to the magnetic field. Both electric and magnetic forces are proportional to their respective fields but option (a) includes only electric force. Thus, option (a) is incorrect.

The magnetic force is proportional to the magnetic field and the electric force is proportional to the electric field. Both the forces are proportional to their respective fields but option (b) includes only magnetic force. Thus, option (b) is incorrect.

Both the forces are proportional to their respective fields. Thus option (c) is correct.

The exerted forces in magnetic field as well as electric field are proportional to their respective field that contradicts the option (d). Thus, option (d) is incorrect.

(ii)

Expert Solution
Check Mark
To determine

The forces proportional to the magnitude of the charge.

Answer to Problem 29.8OQ

Option (c) both electric and magnetic forces

Explanation of Solution

The expression for electrical force is,

Fe=qE

Increase the magnitude of charge, the force on the charge will also increase proportional to it.

Feq

The expression for magnetic force is

Fm=qvBsinθ

Increase the magnitude of charge with same speed and in the same field, in the same direction, the force on the charge will also increase proportional to it.

Fmq

Conclusion:

The electric force is proportional to the magnitude of charge and the magnetic force is also proportional to magnitude of charge. Both electric and magnetic forces are proportional to the magnitude of charge but option (a) includes only electric force. Thus, option (a) is incorrect.

The magnetic force is proportional to the magnitude of charge and also the electric force is proportional to magnitude of charge .Both the forces are proportional to the magnitude of charge but option (b) only magnetic force. Thus, option (b) is incorrect.

Both the forces are proportional to the magnitude of charge. Thus option (c) is correct.

The exerted forces in magnetic field as well as electric field are proportional to the magnitude of charge that contradicts the option (d). Thus, option (d) is incorrect.

(iii)

Expert Solution
Check Mark
To determine

The forces which exert force on a negatively charged particle in opposite direction to the force on a positively charged particle.

Answer to Problem 29.8OQ

Option (c) both electric and magnetic forces.

Explanation of Solution

The electric force on a positively charged particle is

Fe+=+qE (1)

Here

Fe+ is the electric force vector on the positively charged particle.

q is the magnitude of charge on the particle.

E is the electric field intensity.

The electric force on a negatively charged particle is

Fe=qE (2)

Here

Fe is the electric force vector on the positively charged particle.

From equation (1) and equation (2),

Fe+=Fe

Thus, electric force on the same magnitude of electric charge of opposite nature are equal but opposite in direction.

The magnetic force on a positively charged particle is,

Fm+=+q(vB) (3)

Here

Fm+ is the magnetic force vector on the positively charged particle.

q is the magnitude of charge on the particle.

B is the electric flux density.

v is the speed of the particle.

The magnetic force on a negatively charged particle is,

Fm=q(vB) (4)

Here,

Fm is the electric force vector on the positively charged particle.

From equation (3) and (4),

Fm+=Fm

Thus, magnetic force on the same magnitude of electric charge moving with same speed but of opposite nature are equal but opposite in direction.

Conclusion:

Both magnetic force and electric force exert force on negative charge in the opposite direction to the force on positive charge but option (a) includes only electric force. Thus, option (a) is incorrect.

Both magnetic force and electric force exert force on negative charge in the opposite direction to the force on positive charge but option (b) includes only magnetic force. Thus option (b) is incorrect.

Both magnetic force and electric force exert force on negative charge in the opposite direction to the force on positive charge. Thus, option (c) is correct.

Both the forces exert force on negative charge in the opposite direction to the force on positive charge that contradicts the option (d). Thus, option (d) is incorrect.

(iv)

Expert Solution
Check Mark
To determine

The forces which are non-zero on a stationary object.

Answer to Problem 29.8OQ

Option (a) only electric forces exert non-zero force on stationary object.

Explanation of Solution

The expression for electrical force is,

Fe=qE

There is no relation between motion of charged object and electric field because electric field exists for all orientations of charges, whether it is stationary or in motion.

The expression for magnetic force is,

Fm=qvBsinθ

Magnetic force exists only when charges are in motion. Thus for stationary charges the magnetic force is not valid.

Conclusion:

Electrical force is valid for any particle that has charge; it is fundamental force in nature. Thus, option (a) is correct.

Magnetic field is existence for any charged particle in motion. Stationary charged particles have zero magnetic force. Thus option (b) is incorrect.

For a stationary charge only electric force is non-zero and magnetic force is zero that contradicts the option (c). Thus, option (c) is incorrect.

For a stationary charge only electric force is non-zero and magnetic field is zero which is contradictory to the option (d). Thus, option (d) is incorrect.

(v)

Expert Solution
Check Mark
To determine

The forces which are zero on a moving charge.

Answer to Problem 29.8OQ

Option (d) neither electric nor magnetic force.

Explanation of Solution

The expression for electrical force is,

Fe=qE

There is no relation between motion of charged object and electric field because electric field exists for all orientations of charges, whether it is stationary or in motion. If electric field exists then there is a non-zero force on the charged object.

The expression for magnetic force is,

Fm=qvBsinθ

Magnetic force exists only when charges are in motion. Thus for moving charges the magnetic force may be zero if the charge moves either in the direction of the magnetic field or opposite to it.

Conclusion:

Electrical force is valid for any particle that has charge; it is fundamental force in nature. Thus, option (a) is incorrect.

Magnetic field is existence for any charged object in motion. Moving charged objects may have zero magnetic force if the charged object moves along or against the direction of the magnetic field. Thus, option (b) is incorrect.

For a moving charge, electric force is non-zero but the magnetic force may or may not be zero that contradicts the option (c). Thus, option (c) is incorrect.

For a moving charge only electric force is non-zero and magnetic force may or may not be zero. Thus option (d) is correct.

(vi)

Expert Solution
Check Mark
To determine

The forces proportional to the speed of the charged object.

Answer to Problem 29.8OQ

option (b) magnetic forces only.

Explanation of Solution

The expression for electrical force is,

Fe=qE

There is no relation between motion of charged object and the electric field force.

The expression for magnetic force is,

Fm=qvBsinθ

The magnetic force exists only if there is motion and is directly proportional to the speed of the charged particle.

Fmv

Conclusion:

The electric force exerted on the charged object has no relation with its motion. Thus option (a) is incorrect.

The magnetic force is exerted on a body in motion and is directly proportional to the speed of the object. Thus option (b) is correct.

The electric force exerted on the charged object has no relation with its motion while magnetic force on it is proportional to the speed of the object. Thus, option (c) is incorrect.

The electric force exerted on the charged object has no relation with its motion while magnetic force on it is proportional to the speed of the object that contradicts the option (d). Thus, option (d) is incorrect.

(vii)

Expert Solution
Check Mark
To determine

The forces on the charged object which can alter its speed.

Answer to Problem 29.8OQ

Option (b) magnetic forces only.

Explanation of Solution

The expression for electrical force is,

Fe=qE

There is no relation between motion of charged object and the electric field force.

The expression for magnetic force is,

Fm=q(vB)

The magnetic force acts on the perpendicular direction of the motion of the object because it is along the direction of cross product vector of v and B . The force does not change the magnitude of the velocity but it changes the direction of motion.

Conclusion:

There is no relation of motion of the charged object and the electric field force. Thus option (a) is incorrect.

The magnetic force has no change in the speed but it does change the direction of motion of the object. Thus option (b) is correct.

Electric forces have no relation with speed of the charged body while magnetic forces cannot alter speed of the object but it can change its direction of motion. Thus option (c) is incorrect.

Electric forces are independent of any motion of the charged object while magnetic forces can change only the direction of motion of the object. Thus option (d) is incorrect

(viii)

Expert Solution
Check Mark
To determine

The force whose magnitude depends on the charged object’s direction of motion.

Answer to Problem 29.8OQ

Option (b) magnetic forces only

Explanation of Solution

The expression for electrical force is

Fe=qE

There is no relation between motion of charged object and the electric field force.

The expression for magnetic force is

Fm=qvBsinθ

The value of θ depends upon the direction of motion of the charged object Change in the direction of motion changes value of θ and so the magnetic force varies.

Conclusion:

The electric field has no relation with the motion of the charged object Thus option (a) is incorrect.

The variation in direction of motion varies the value of θ which in turn varies the value of the magnitude of magnetic force. Thus option (b) is correct.

The direction of motion of the charged object affects only the magnetic force but not electric force. Thus option (c) is incorrect as it considers both the forces.

Only the magnetic force is affected by variation in direction of motion of the charged object but not electric force. Thus option (d) is incorrect as it considers neither of the forces.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
No chatgpt pls will upvote
No chatgpt pls will upvote
No chatgpt pls will upvote

Chapter 29 Solutions

EBK PHYSICS FOR SCIENTISTS AND ENGINEER

Ch. 29 - Prob. 29.7OQCh. 29 - Classify each of die following statements as a...Ch. 29 - An electron moves horizontally across the Earths...Ch. 29 - A charged particle is traveling through a uniform...Ch. 29 - In the velocity selector shown in Figure 29.13....Ch. 29 - Prob. 29.12OQCh. 29 - A magnetic field exerts a torque on each of the...Ch. 29 - Can a constant magnetic field set into motion an...Ch. 29 - Explain why it is not possible to determine the...Ch. 29 - Is it possible to orient a current loop in a...Ch. 29 - How can the motion of a moving charged particle be...Ch. 29 - Prob. 29.5CQCh. 29 - Charged panicles from outer space, called cosmic...Ch. 29 - Two charged particles are projected in the same...Ch. 29 - At the equator, near the surface of the Earth, the...Ch. 29 - Determine the initial direction of the deflection...Ch. 29 - Find the direction of the magnetic field acting on...Ch. 29 - Consider an electron near the Earths equator. In...Ch. 29 - Prob. 29.5PCh. 29 - A proton moving at 4.00 106 m/s through a...Ch. 29 - An electron is accelerated through 2.40 103 V...Ch. 29 - A proton moves with a velocity of v = (2i 4j + k)...Ch. 29 - A proton travels with a speed of 5.02 106 m/s in...Ch. 29 - A laboratory electromagnet produces a magnetic...Ch. 29 - A proton moves perpendicular to a uniform magnetic...Ch. 29 - Review. A charged particle of mass 1.50 g is...Ch. 29 - An electron moves in a circular path perpendicular...Ch. 29 - An accelerating voltage of 2.50103 V is applied to...Ch. 29 - A proton (charge + e, mass mp), a deuteron (charge...Ch. 29 - A particle with charge q and kinetic energy K...Ch. 29 - Review. One electron collides elastically with a...Ch. 29 - Review. One electron collides elastically with a...Ch. 29 - Review. An electron moves in a circular path...Ch. 29 - Review. A 30.0-g metal hall having net charge Q =...Ch. 29 - A cosmic-ray proton in interstellar space has an...Ch. 29 - Assume the region to the right of a certain plane...Ch. 29 - A singly charged ion of mass m is accelerated from...Ch. 29 - A cyclotron designed to accelerate protons has a...Ch. 29 - Prob. 29.25PCh. 29 - Singly charged uranium-238 ions are accelerated...Ch. 29 - A cyclotron (Fig. 28.16) designed to accelerate...Ch. 29 - A particle in the cyclotron shown in Figure 28.16a...Ch. 29 - Prob. 29.29PCh. 29 - Prob. 29.30PCh. 29 - Prob. 29.31PCh. 29 - A straight wire earning a 3.00-A current is placed...Ch. 29 - A conductor carrying a current I = 15.0 A is...Ch. 29 - A wire 2.80 m in length carries a current of 5.00...Ch. 29 - A wire carries a steady current of 2.40 A. A...Ch. 29 - Why is the following situation impossible? Imagine...Ch. 29 - Review. A rod of mass 0.720 kg and radius 6.00 cm...Ch. 29 - Review. A rod of mass m and radius R rests on two...Ch. 29 - A wire having a mass per unit length of 0.500 g/cm...Ch. 29 - Consider the system pictured in Figure P28.26. A...Ch. 29 - A horizontal power line oflength 58.0 in carries a...Ch. 29 - A strong magnet is placed under a horizontal...Ch. 29 - Assume the Earths magnetic field is 52.0 T...Ch. 29 - In Figure P28.28, the cube is 40.0 cm on each...Ch. 29 - Prob. 29.45PCh. 29 - A 50.0-turn circular coil of radius 5.00 cm can be...Ch. 29 - A magnetized sewing needle has a magnetic moment...Ch. 29 - A current of 17.0 mA is maintained in a single...Ch. 29 - An eight-turn coil encloses an elliptical area...Ch. 29 - Prob. 29.50PCh. 29 - A rectangular coil consists of N = 100 closely...Ch. 29 - A rectangular loop of wire has dimensions 0.500 m...Ch. 29 - A wire is formed into a circle having a diameter...Ch. 29 - A Hall-effect probe operates with a 120-mA...Ch. 29 - Prob. 29.55PCh. 29 - Prob. 29.56APCh. 29 - Prob. 29.57APCh. 29 - Prob. 29.58APCh. 29 - A particle with positive charge q = 3.20 10-19 C...Ch. 29 - Figure 28.11 shows a charged particle traveling in...Ch. 29 - Review. The upper portion of the circuit in Figure...Ch. 29 - Within a cylindrical region of space of radius 100...Ch. 29 - Prob. 29.63APCh. 29 - (a) A proton moving with velocity v=ii experiences...Ch. 29 - Review. A 0.200-kg metal rod carrying a current of...Ch. 29 - Prob. 29.66APCh. 29 - A proton having an initial velocity of 20.0iMm/s...Ch. 29 - Prob. 29.68APCh. 29 - A nonconducting sphere has mass 80.0 g and radius...Ch. 29 - Why is the following situation impossible? Figure...Ch. 29 - Prob. 29.71APCh. 29 - A heart surgeon monitors the flow rate of blood...Ch. 29 - A uniform magnetic Held of magnitude 0.150 T is...Ch. 29 - Review. (a) Show that a magnetic dipole in a...Ch. 29 - Prob. 29.75APCh. 29 - Prob. 29.76APCh. 29 - Consider an electron orbiting a proton and...Ch. 29 - Protons having a kinetic energy of 5.00 MeV (1 eV...Ch. 29 - Review. A wire having a linear mass density of...Ch. 29 - A proton moving in the plane of the page has a...
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
Glencoe Physics: Principles and Problems, Student...
Physics
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Glencoe/McGraw-Hill
Text book image
Classical Dynamics of Particles and Systems
Physics
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Cengage Learning
Magnets and Magnetic Fields; Author: Professor Dave explains;https://www.youtube.com/watch?v=IgtIdttfGVw;License: Standard YouTube License, CC-BY