![Nester's Microbiology: A Human Perspective](https://www.bartleby.com/isbn_cover_images/9781259709999/9781259709999_largeCoverImage.gif)
Concept explainers
Describe how the BOD of a water sample is determined.
![Check Mark](/static/check-mark.png)
To review:
The method of determination of BOD (biological oxygen demand) of a water sample.
Introduction:
The oxygen required by the microorganisms for decomposing the organic waste is known as biological oxygen demand. This procedure is utilized during the secondary treatment of wastewater. This property of the water determines its microbial content.
Explanation of Solution
A high BOD indicates the presence of a high amount of organic waste in the water sample. While a low BOD indicates a water sample with low organic waste. The higher the organic waste, more time will be utilizedby the microorganisms to degrade the organic waste. In this process, they utilize oxygen, which is measured as BOD. When the organic waste is degraded completely, the BOD of a wastewater decline.
Every water body contains naturally dissolved oxygen (DO), which gets depleted in the presence of organic material. This property is utilized for calculating the BOD of a water sample. The initial DO is calculated from the fresh water sample. The container should be left undisturbed for 5 days at standard temperature (20 degrees Celsius) in dark.
The final oxygen is then measured after 5 days of incubation. A difference in the initial DO and final DO mark the BOD of the water sample. In the case of a highly polluted water body, the sample should be diluted to avoid the depletion of oxygen before the incubation period.
Therefore, it can be concluded that the BOD of a water sample is determined by measuring the initial and final dissolved oxygen from the fresh, aerated sample and sample after 5 days of incubation, respectively. The difference of the DO gives the BOD of the water sample.
Want to see more full solutions like this?
Chapter 29 Solutions
Nester's Microbiology: A Human Perspective
- Identify the indicated tissue. (Tilia stem x.s.) parenchyma collenchyma sclerenchyma xylem phloem none of thesearrow_forwardIdentify the indicated structure. (Cucurbita stem l.s.) pit lenticel stomate tendril none of thesearrow_forwardIdentify the specific cell? (Zebrina leaf peel) vessel element sieve element companion cell tracheid guard cell subsidiary cell none of thesearrow_forward
- What type of cells flank the opening on either side? (leaf x.s.) vessel elements sieve elements companion cells tracheids guard cells none of thesearrow_forwardWhat specific cell is indicated. (Cucurbita stem I.s.) vessel element sieve element O companion cell tracheid guard cell none of thesearrow_forwardWhat specific cell is indicated? (Aristolochia stem x.s.) vessel element sieve element ○ companion cell O O O O O tracheid O guard cell none of thesearrow_forward
- Identify the tissue. parenchyma collenchyma sclerenchyma ○ xylem O phloem O none of thesearrow_forwardPlease answer q3arrow_forwardRespond to the following in a minimum of 175 words: How might CRISPR-Cas 9 be used in research or, eventually, therapeutically in patients? What are some potential ethical issues associated with using this technology? Do the advantages of using this technology outweigh the disadvantages (or vice versa)? Explain your position.arrow_forward
- You are studying the effect of directional selection on body height in three populations (graphs a, b, and c below). (a) What is the selection differential? Show your calculation. (2 pts) (b) Which population has the highest narrow sense heritability for height? Explain your answer. (2 pts) (c) If you examined the offspring in the next generation in each population, which population would have the highest mean height? Why? (2 pts) (a) Midoffspring height (average height of offspring) Short Short Short Short (c) Short (b) Short Tall Short Tall Short Short Tall Midparent height (average height of Mean of population = 65 inches Mean of breading parents = 70 inches Mean of population = 65 inches Mean of breading parents = 70 inches Mean of population = 65 inches Mean of breading parents = 70 inchesarrow_forwardP You are studying a population of 100 flowers that has two alleles at a locus for flower color, blue (B) and green (G). There are 15 individuals with the BB genotype, 70 individuals with the BG genotype, and 15 individuals with the GG genotype. (a) What are the allele frequencies of B and G in the starting population? Show your calculations. (2 pts) (b) Is this population in Hardy-Weinberg equilibrium? Show your calculations. (3 pts) 12pt v Paragraph BIU UA AV & VT2V f CO Varrow_forwardIn a natural population of outbreeding plants, the variance of the total number of seeds per plant is 16. From the natural population, 20 plants are taken into the laboratory and developed into separate true-breeding lines by self- fertilization-with selection for high, low, or medium number of seeds-for 10 generations. The average variance in the tenth generation in each of the 20 sets is about equal and averages 5.8 across all the sets. Estimate the broad-sense heritability for seed number in this population. (4 pts) 12pt v Paragraph BIUA V V T² v B ① O wordsarrow_forward
- Essentials of Pharmacology for Health ProfessionsNursingISBN:9781305441620Author:WOODROWPublisher:CengagePrinciples Of Radiographic Imaging: An Art And A ...Health & NutritionISBN:9781337711067Author:Richard R. Carlton, Arlene M. Adler, Vesna BalacPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337711067/9781337711067_smallCoverImage.jpg)