Chapter 29, Problem 1P

To determine

The time elapses between successive peak EMF values of the coil.

Answer to Problem 1P

  $\boxed{T\approx 0.02\text{s}}$

Explanation of Solution

Given:The Frequency of the ac generator is $f=60\text{Hz}$ .

Formula used:The time elapsed between two successive peaks is expressed as

  $T=\frac{1}{f}$........ (1)

Here, $T$ is time period and $f$ is the frequency.

Calculation:

The time elapsed is calculated as

  $\begin{array}{c}T=\frac{1}{f}\\ =\frac{1}{60}\text{s}\\ \text{=}\text{0}\text{.016}\text{s}\\ \boxed{\therefore T\approx 0.02\text{s}}\end{array}$

Conclusion:

Hence, the required time elapsed is $\boxed{T\approx 0.02\text{s}}$ .