(a)
Interpretation: Bonding and anti-bonding molecular orbitals has to be determined for the molecular orbitals of
Concept introduction:
Molecular orbital theory suggests that atomic orbitals of different atoms combines to create molecular orbitals.
Molecular orbitals can be constructed from linear combination of atomic orbitals.
Bonding orbotals are formed by the additive combination of atomic orbitals and the antibonding orbitals are formed by the substractive combination of atomic orbitals.
Antibonding orbital is a molecular orbital that results when two parallel atomic orbitals with opposite phases interact.
Antibonding orbitals have higher energy than the bonding molecular orbitals.
HOMO is a molecular orbital which is the abbrevation of Highest Occupied Molecular Orbital.
LUMO is also a molecular orbital which is the short form of Lowest Unoccupied Molecular Orbital.
If the lobes at the ends of the MO are in phase, then the MO is symmetric.
If the two lobes are out phase then the MO is antisymmetric.
(b)
Interpretation: HOMO and LUMO molecular orbitals in the ground state has to be determined for the molecular orbitals of
Concept introduction:
Molecular orbital theory suggests that atomic orbitals of different atoms combines to create molecular orbitals.
Molecular orbitals can be constructed from linear combination of atomic orbitals.
Bonding orbotals are formed by the additive combination of atomic orbitals and the antibonding orbitals are formed by the substractive combination of atomic orbitals.
Antibonding orbital is a molecular orbital that results when two parallel atomic orbitals with opposite phases interact.
Antibonding orbitals have higher energy than the bonding molecular orbitals.
Ground state and and exited states are the positions with lower and higher energy respectively.
HOMO is a molecular orbital which is the abbrevation of Highest Occupied Molecular Orbital.
LUMO is also a molecular orbital which is the short form of Lowest Unoccupied Molecular Orbital.
If the lobes at the ends of the MO are in phase, then the MO is symmetric.
If the two lobes are out phase then the MO is antisymmetric.
(c)
Interpretation: HOMO and LUMO molecular orbitals in the existed state has to be determined for the molecular orbitals of
Concept introduction:
Molecular orbital theory suggests that atomic orbitals of different atoms combines to create molecular orbitals.
Molecular orbitals can be constructed from linear combination of atomic orbitals.
Bonding orbotals are formed by the additive combination of atomic orbitals and the antibonding orbitals are formed by the substractive combination of atomic orbitals.
Antibonding orbital is a molecular orbital that results when two parallel atomic orbitals with opposite phases interact.
Antibonding orbitals have higher energy than the bonding molecular orbitals.
Ground state and and exited states are the positions with lower and higher energy respectively.
HOMO is a molecular orbital which is the abbrevation of Highest Occupied Molecular Orbital.
LUMO is also a molecular orbital which is the short form of Lowest Unoccupied Molecular Orbital.
If the lobes at the ends of the MO are in phase, then the MO is symmetric.
If the two lobes are out phase then the MO is antisymmetric.
(d)
Interpretation: Symmetric and anti-symmetric MOs has to be determined for the molecular orbitals of
Concept introduction:
Molecular orbital theory suggests that atomic orbitals of different atoms combines to create molecular orbitals.
Molecular orbitals can be constructed from linear combination of atomic orbitals.
Bonding orbotals are formed by the additive combination of atomic orbitals and the antibonding orbitals are formed by the substractive combination of atomic orbitals.
Antibonding orbital is a molecular orbital that results when two parallel atomic orbitals with opposite phases interact.
Antibonding orbitals have higher energy than the bonding molecular orbitals.
Ground state and and exited states are the positions with lower and higher energy respectively.
HOMO is a molecular orbital which is the abbrevation of Highest Occupied Molecular Orbital.
LUMO is also a molecular orbital which is the short form of Lowest Unoccupied Molecular Orbital.
If the lobes at the ends of the MO are in phase, then the MO is symmetric.
If the two lobes are out phase then the MO is antisymmetric.
(e)
Interpretation: The relationship between HOMO and LUMO and symmetric and antisymmetric molecular orbitals has to be determined.
Concept introduction:
Molecular orbital theory suggests that atomic orbitals of different atoms combines to create molecular orbitals.
Molecular orbitals can be constructed from linear combination of atomic orbitals.
Bonding orbotals are formed by the additive combination of atomic orbitals and the antibonding orbitals are formed by the substractive combination of atomic orbitals.
Antibonding orbital is a molecular orbital that results when two parallel atomic orbitals with opposite phases interact.
Antibonding orbitals have higher energy than the bonding molecular orbitals.
Ground state and and exited states are the positions with lower and higher energy respectively.
HOMO is a molecular orbital which is the abbrevation of Highest Occupied Molecular Orbital.
LUMO is also a molecular orbital which is the short form of Lowest Unoccupied Molecular Orbital.
If the lobes at the ends of the MO are in phase, then the MO is symmetric.
If the two lobes are out phase then the MO is antisymmetric.

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Chapter 28 Solutions
CHEM 262 ORG CHEM EBOOK DIGITAL DELIVERY
- 4. For the reactions below, draw the expected product. Be sure to indicate relevant stereochemistry or formal charges in the product structure. a) CI, H e b) H lux ligh Br 'Harrow_forwardArrange the solutions in order of increasing acidity. (Note that K (HF) = 6.8 x 10 and K (NH3) = 1.8 × 10-5) Rank solutions from least acidity to greatest acidity. To rank items as equivalent, overlap them. ▸ View Available Hint(s) Least acidity NH&F NaBr NaOH NH,Br NaCIO Reset Greatest acidityarrow_forward1. Consider the following molecular-level diagrams of a titration. O-HA molecule -Aion °° о ° (a) о (b) (c) (d) a. Which diagram best illustrates the microscopic representation for the EQUIVALENCE POINT in a titration of a weak acid (HA) with sodium. hydroxide? (e)arrow_forward
- Answers to the remaining 6 questions will be hand-drawn on paper and submitted as a single file upload below: Review of this week's reaction: H₂NCN (cyanamide) + CH3NHCH2COOH (sarcosine) + NaCl, NH4OH, H₂O ---> H₂NC(=NH)N(CH3)CH2COOH (creatine) Q7. Draw by hand the reaction of creatine synthesis listed above using line structures without showing the Cs and some of the Hs, but include the lone pairs of electrons wherever they apply. (4 pts) Q8. Considering the Zwitterion form of an amino acid, draw the Zwitterion form of Creatine. (2 pts) Q9. Explain with drawing why the C-N bond shown in creatine structure below can or cannot rotate. (3 pts) NH2(C=NH)-N(CH)CH2COOH This bond Q10. Draw two tautomers of creatine using line structures. (Note: this question is valid because problem Q9 is valid). (4 pts) Q11. Mechanism. After seeing and understanding the mechanism of creatine synthesis, students should be ready to understand the first half of one of the Grignard reactions presented in a past…arrow_forwardPropose a synthesis pathway for the following transformations. b) c) d)arrow_forwardThe rate coefficient of the gas-phase reaction 2 NO2 + O3 → N2O5 + O2 is 2.0x104 mol–1 dm3 s–1 at 300 K. Indicate whether the order of the reaction is 0, 1, or 2.arrow_forward
- 8. Draw all the resonance forms for each of the following molecules or ions, and indicate the major contributor in each case, or if they are equivalent. (4.5 pts) (a) PH2 سمةarrow_forward3. Assign absolute configuration (Rors) to each chirality center. a. H Nitz C. он b. 0 H-C. C H 7 C. ་-4 917-417 refs H 1つ ८ ડુ d. Но f. -2- 01 Ho -OH 2HNarrow_forwardHow many signals do you expect in the H NMR spectrum for this molecule? Br Br Write the answer below. Also, in each of the drawing areas below is a copy of the molecule, with Hs shown. In each copy, one of the H atoms is colored red. Highlight in red all other H atoms that would contribute to the same signal as the H already highlighted red. Note for advanced students: In this question, any multiplet is counted as one signal. Number of signals in the 'H NMR spectrum. For the molecule in the top drawing area, highlight in red any other H atoms that will contribute to the same signal as the H atom already highlighted red. If no other H atoms will contribute, check the box at right. No additional Hs to color in top molecule For the molecule in the bottom drawing area, highlight in red any other H atoms that will contribute to the same signal as the H atom already highlighted red. If no other H atoms will contribute, check the box at right. No additional Hs to color in bottom moleculearrow_forward
- In the drawing area below, draw the major products of this organic reaction: 1. NaOH ? 2. CH3Br If there are no major products, because nothing much will happen to the reactant under these reaction conditions, check the box under the drawing area instead. No reaction. Click and drag to start drawing a structure. ☐ : A คarrow_forwardPredict the major products of the following organic reaction: NC Δ ? Some important Notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to draw bonds carefully to show important geometric relationships between substituents. Note: if your answer contains a complicated ring structure, you must use one of the molecular fragment stamps (available in the menu at right) to enter the ring structure. You can add any substituents using the pencil tool in the usual way. Click and drag to start drawing a structure. Х аarrow_forwardPredict the major products of this organic reaction. Be sure you use dash and wedge bonds to show stereochemistry where it's important. + ☑ OH 1. TsCl, py .... 文 P 2. t-BuO K Click and drag to start drawing a structure.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning

