ILW In Fig. 28-32, an electron accelerated from rest through potential difference V 1 = 1.00 kV enters the gap between two parallel plates having separation d = 20.0 mm potential difference V 2 = 100 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron’s velocity vector is perpendicular to the electric field vector between the plates. In unit-vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap? Figure 28-32 Question 9.
ILW In Fig. 28-32, an electron accelerated from rest through potential difference V 1 = 1.00 kV enters the gap between two parallel plates having separation d = 20.0 mm potential difference V 2 = 100 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron’s velocity vector is perpendicular to the electric field vector between the plates. In unit-vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap? Figure 28-32 Question 9.
ILW In Fig. 28-32, an electron accelerated from rest through potential difference V1 = 1.00 kV enters the gap between two parallel plates having separation d = 20.0 mm potential difference V2 = 100 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron’s velocity vector is perpendicular to the electric field vector between the plates. In unit-vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap?
What is the resistance (in (2) of a 27.5 m long piece of 17 gauge copper wire having a 1.150 mm diameter?
0.445
ΧΩ
Find the ratio of the diameter of silver to iron wire, if they have the same resistance per unit length (as they might in household wiring).
d.
Ag
dFe
= 2.47
×
Find the ratio of the diameter of silver to iron wire, if they have the same resistance per unit length (as they might in household wiring).
d
Ag
= 2.51
dFe
×
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