Explanation Given data: Kinetic energy of the emitted electrons is 1.50eV. Wavelength of light is 250 nm. Formula used: Consider the work function equation. E = h c λ (1) Here, h is the planks constant, which has a standard value as 6.63 × 10 − 34 J ⋅ s , c is the speed of light , which has a standard value as 3 × 10 8 m s , and λ is the wavelength. Explanation: Substitute 6.63 × 10 − 34 J ⋅ s for h , 3 × 10 8 m s for c , and 250 nm for λ in equation (1), E = ( 6.63 × 10 − 34 J ⋅ s ) ( 3 × 10 8 m s ) 250nm = ( 6.63 × 10 − 34 J ⋅ s ) ( 3 × 10 8 m s ) 250 × 10 − 9 m = 0.0795 × 10 − 17 J Consider the conversion factor for J to eV

16th Edition

ISBN: 9781323515303

Author: Knight

Publisher: PEARSON C

See similar textbooks

Concept explainers

Particle Theory of Light

The particle theory of light was the proposal made by Newton in 1704 in his treatise Opticks. This is the most basic light theory, in which light is thought to be made up of microscopic particles known as "corpuscles" and that's why this particle theory …

Stopping Potential

In an experiment conducted by Heinrich Hertz, an apparatus was made where the incident light was made to fall on the metallic plate, it was discovered that metals emit electrons. The surface electrons are bound to metals with a minimum amount of energy a…

Quantization of Charges

An electron is a negatively charged subatomic particle either attached to an an atom or sticks to the nucleus of the atom. Electrons exert the negative charge that tries to balance the positive charge of the nucleus.

Question

Chapter 28, Problem 9P

To determine

The maximum kinetic energy of the metal when illuminated by light with a wavelength of 250 nm.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 28, Problem 8P

Chapter 28, Problem 10P

Students have asked these similar questions

T1. Calculate what is the received frequency when the car drives away from the radar antenna at a speed v of a) 1 m/s ( = 3.6 km/h), b) 10 m/s ( = 36 km/h), c) 30 m /s ( = 108 km/h) . The radar transmission frequency f is 24.125 GHz = 24.125*10^9 Hz, about 24 GHz. Speed of light 2.998 *10^8 m/s.

No Chatgpt please will upvote

Chapter 28 Solutions

COLLEGE PHY2053 W/MODIFIED ACCESS>BI<

Ch. 28 - Prob. 1CQ Ch. 28 - Prob. 2CQ Ch. 28 - Prob. 3CQ Ch. 28 - Prob. 4CQ Ch. 28 - Prob. 5CQ Ch. 28 - Prob. 6CQ Ch. 28 - Prob. 7CQ Ch. 28 - Prob. 8CQ Ch. 28 - Prob. 9CQ Ch. 28 - Prob. 10CQ

Ch. 28 - Prob. 11CQ Ch. 28 - Prob. 12CQ Ch. 28 - Prob. 13CQ Ch. 28 - Prob. 14CQ Ch. 28 - Prob. 15CQ Ch. 28 - Prob. 16CQ Ch. 28 - Prob. 17CQ Ch. 28 - Prob. 18CQ Ch. 28 - Prob. 19CQ Ch. 28 - Prob. 20CQ Ch. 28 - Prob. 21CQ Ch. 28 - Prob. 22CQ Ch. 28 - Prob. 23CQ Ch. 28 - Prob. 24CQ Ch. 28 - Prob. 25CQ Ch. 28 - Prob. 26CQ Ch. 28 - Prob. 27CQ Ch. 28 - Prob. 28MCQ Ch. 28 - Prob. 29MCQ Ch. 28 - Prob. 30MCQ Ch. 28 - Prob. 31MCQ Ch. 28 - Prob. 32MCQ Ch. 28 - Prob. 33MCQ Ch. 28 - Prob. 34MCQ Ch. 28 - Prob. 35MCQ Ch. 28 - Prob. 36MCQ Ch. 28 - Prob. 37MCQ Ch. 28 - Prob. 38MCQ Ch. 28 - Prob. 1P Ch. 28 - Prob. 2P Ch. 28 - Prob. 3P Ch. 28 - Prob. 4P Ch. 28 - Prob. 5P Ch. 28 - Prob. 6P Ch. 28 - Prob. 7P Ch. 28 - Prob. 8P Ch. 28 - Prob. 9P Ch. 28 - Prob. 10P Ch. 28 - Prob. 11P Ch. 28 - Prob. 12P Ch. 28 - Prob. 13P Ch. 28 - Prob. 14P Ch. 28 - Prob. 15P Ch. 28 - Prob. 16P Ch. 28 - Prob. 17P Ch. 28 - Prob. 18P Ch. 28 - Prob. 19P Ch. 28 - Prob. 20P Ch. 28 - Prob. 21P Ch. 28 - Prob. 22P Ch. 28 - Prob. 23P Ch. 28 - Prob. 24P Ch. 28 - Prob. 25P Ch. 28 - Prob. 26P Ch. 28 - Prob. 27P Ch. 28 - Prob. 28P Ch. 28 - Prob. 29P Ch. 28 - Prob. 30P Ch. 28 - Prob. 31P Ch. 28 - Prob. 32P Ch. 28 - Prob. 33P Ch. 28 - Prob. 34P Ch. 28 - Prob. 35P Ch. 28 - Prob. 36P Ch. 28 - Prob. 37P Ch. 28 - Prob. 38P Ch. 28 - Prob. 39P Ch. 28 - Prob. 40P Ch. 28 - Prob. 41P Ch. 28 - Prob. 42P Ch. 28 - Prob. 43P Ch. 28 - Prob. 44P Ch. 28 - Prob. 45P Ch. 28 - Prob. 46P Ch. 28 - Prob. 47P Ch. 28 - Prob. 48P Ch. 28 - Prob. 49P Ch. 28 - Prob. 50P Ch. 28 - Prob. 51P Ch. 28 - Prob. 52P Ch. 28 - Prob. 53P Ch. 28 - Prob. 54P Ch. 28 - Prob. 55P Ch. 28 - Prob. 56P Ch. 28 - Prob. 57P Ch. 28 - Prob. 58GP Ch. 28 - Prob. 59GP Ch. 28 - Prob. 60GP Ch. 28 - Prob. 61GP Ch. 28 - Prob. 62GP Ch. 28 - Prob. 63GP Ch. 28 - Prob. 64GP Ch. 28 - Prob. 65GP Ch. 28 - Prob. 66GP Ch. 28 - Prob. 67GP Ch. 28 - Prob. 68GP Ch. 28 - Prob. 69GP Ch. 28 - Prob. 70GP Ch. 28 - Prob. 71GP Ch. 28 - Prob. 72GP Ch. 28 - Prob. 73GP Ch. 28 - Prob. 74GP Ch. 28 - Prob. 75GP Ch. 28 - Prob. 76GP Ch. 28 - Prob. 77GP Ch. 28 - Prob. 78GP Ch. 28 - Prob. 79MSPP Ch. 28 - Prob. 80MSPP Ch. 28 - Prob. 81MSPP Ch. 28 - Prob. 82MSPP Ch. 28 - Prob. 83MSPP Ch. 28 - Prob. 84MSPP Ch. 28 - Prob. 85MSPP Ch. 28 - Prob. 86MSPP Ch. 28 - Prob. 87MSPP Ch. 28 - Prob. 88MSPP Ch. 28 - Prob. 89MSPP Ch. 28 - Prob. 90MSPP Ch. 28 - Prob. 91MSPP Ch. 28 - Prob. 92MSPP

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The maximum kinetic energy of the metal when illuminated by light with a wavelength of 250 nm.

Solution Summary: The author determines the maximum kinetic energy of the metal when illuminated by light with a wavelength of 250 nm.

Concept explainers

The maximum kinetic energy of the metal when illuminated by light with a wavelength of 250 nm.

Want to see the full answer?

Chapter 28 Solutions