Explanation Given data: Magnetic moment of the electron is ( μ ) 9.3 × 10 − 24 J T . Length of the solenoid is 15 cm. Number of turns of the solenoid is 1200. Current in the wire is 3.5 A. Formula used: Write the expression for magnetic field of the solenoid. B = μ 0 I N L (1) Here, B is the magnetic field, μ 0 is the permeability having a value of 1.26 × 10 − 6 T ⋅ m A , I is the current, N is the number of turns, and L is the length of the solenoid. Write the expression for energy required to flip an electron. Δ E = 2 μ B (2) Here, Δ E is the energy required, and μ is the magnetic moment. Write the expression for photon’s energy and wavelength. Δ E = h f (3) Here, h is the plank’s constant with value 6.63 × 10 − 34 J ⋅ s , and f is the frequency. Explanation: Substitute 1.26 × 10 − 6 T ⋅ m A for μ 0 , 3.5 A for I, 1.2 × 10 3 for N and 0.15 m for L in equation (1), B = ( 1.26 × 10 − 6 T ⋅ m A ) ( 3.5 A ) ( 1.2 × 10 3 ) ( 0.15 m ) = 5.292 × 10 − 3 T ⋅ m ( 0

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ISBN: 9780321989246

Author: Knight

Publisher: PEARSON CO

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Chapter 28, Problem 84GP

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The necessary frequency for the probe coil.

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Chapter 28, Problem 83GP

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Chapter 28 Solutions

EBK COLLEGE PHYSICS

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The necessary frequency for the probe coil.

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Chapter 28 Solutions