a. Explanation Given data: Wavelength of the length of the light is 690 nm. Energy of the pulse is 5.0 mW. On time of the laser is 10 ns. Formula used: Write the expression for energy of photon and wavelength. E photon = h c λ (1) Here, E photon is the energy, h is the plank’s constant with value 6.63 × 10 − 34 J ⋅ s , c is the speed of light with value 3.0 × 10 8 m s , and λ is the wavelength. Write the expression for total energy. E total = n E photon (2) Here, E photon is the energy of the photon and n is the number of photons. Substitute 6.63 × 10 − 34 J ⋅ s for h , 3.0 × 10 8 m s for c and 690 × 10 − 9 m for λ in equation (1), E = ( 6.63 × 10 − 34 J ⋅ s ) ( 3.0 × 10 8 m s ) 690 × 10 − 9 m = ( 6 b. To determine The rate of photon emission in photons per second.

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Question

Chapter 28, Problem 62GP

To determine

The number of photons emitted in each pulse.

To determine

The rate of photon emission in photons per second.

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Chapter 28, Problem 61GP

Chapter 28, Problem 63GP

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