The left-hand and right-hand derivatives off at a are defined by f ' ( a ) = lim h → 0 − f ( a + h ) − f ( a ) a and f ' + ( a ) = lim h → 0 + f ( a + h ) − f ( a ) h if these limits exist. Then f' ( a ) exists if and only if these one-sided derivatives exist and are equal. (a) Find f ' − ( 4 ) and f ' + ( 4 ) for the function f ( x ) = { 0 if x ≤ 0 5 − x if 0 < x < 4 1 5 − x if x ≥ 4 (b) Sketch the graph of f (c) Where is f discontinuous? (d) Where is f not differentiable ?
The left-hand and right-hand derivatives off at a are defined by f ' ( a ) = lim h → 0 − f ( a + h ) − f ( a ) a and f ' + ( a ) = lim h → 0 + f ( a + h ) − f ( a ) h if these limits exist. Then f' ( a ) exists if and only if these one-sided derivatives exist and are equal. (a) Find f ' − ( 4 ) and f ' + ( 4 ) for the function f ( x ) = { 0 if x ≤ 0 5 − x if 0 < x < 4 1 5 − x if x ≥ 4 (b) Sketch the graph of f (c) Where is f discontinuous? (d) Where is f not differentiable ?
Solution Summary: The author explains how to calculate the left-hand derivative of f at x=a.
The left-hand and right-hand derivatives off at a are defined by
f
'
(
a
)
=
lim
h
→
0
−
f
(
a
+
h
)
−
f
(
a
)
a
and
f
'
+
(
a
)
=
lim
h
→
0
+
f
(
a
+
h
)
−
f
(
a
)
h
if these limits exist. Then f'(a) exists if and only if these one-sided derivatives exist and are equal.
(a) Find
f
'
−
(
4
)
and
f
'
+
(
4
)
for the function
f
(
x
)
=
{
0
if
x
≤
0
5
−
x
if
0
<
x
<
4
1
5
−
x
if
x
≥
4
(b) Sketch the graph of f
(c) Where is f discontinuous?
(d) Where is f not differentiable?
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
The bracket BCD is hinged at C and attached to a control cable at B. Let F₁ = 275 N and F2 = 275 N.
F1
B
a=0.18 m
C
A
0.4 m
-0.4 m-
0.24 m
Determine the reaction at C.
The reaction at C
N Z
F2
D
The correct answer is C,i know that we need to use stokes theorem and parametrize the equations then write the equation F with respect to the curve but i cant seem to find a way to do it, the integral should be from 0 to 2pi but i might be wrongcould you show me the steps to get to 18pi
A 10-ft boom is acted upon by the 810-lb force as shown in the figure.
D
6 ft
6 ft
E
B
7 ft
C
6 ft
4 ft
W
Determine the tension in each cable and the reaction at the ball-and-socket joint at A.
The tension in cable BD is
lb.
The tension in cable BE is
lb.
The reaction at A is (
lb) i +
Ib) j. (Include a minus sign if necessary.)
Chapter 2 Solutions
Bundle: Calculus: Early Transcendentals, 8th + WebAssign Printed Access Card for Stewart's Calculus: Early Transcendentals, 8th Edition, Multi-Term
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Differential Equation | MIT 18.01SC Single Variable Calculus, Fall 2010; Author: MIT OpenCourseWare;https://www.youtube.com/watch?v=HaOHUfymsuk;License: Standard YouTube License, CC-BY