Chapter 2.2, Problem 20E

Guess the value of the limit (if it exists) by evaluating the function at the given numbers (correct to six decimal places).

$\underset{x\to -3}{\lim }\frac{x^2-3x}{x^2-9},$

x= –2.5, –2.9, –2.95, –2.99, –2.999, –2.9999, –3.5, –3.1, –3.05, –3.01, –3.001, –3.0001