Explanation 1) Concept: By taking the scalar product of the magnetic dipole moment μ → of the coil with the magnetic field B → , we can find the orientation energy of the coil. By taking vector product of the magnetic dipole moment μ → and magnetic field B → , we can find the torque on the coil due to the magnetic field. 2) Formula: i) The orientation energy of the magnetic dipole is U = - μ → . B → ii) The magnitude of μ → is μ = N i A iii) Torque on the coil is τ → = μ → × B → 3) Given: i) Fig 28.50 of the textbook. ii) The current through the coil, i = 2.00 A iii) The number of turns of the coil, N = 3.00 iv) The area of coil, A = 4.00 × 10 - 3 m 2 v) The uniform magnetic field, B → = 2.00 i ^ - 3.00 j ^ - 4.00 k ^ m T = 2.00 i ^ - 3.00 j ^ - 4.00 k ^ × 10 - 3 T 4) Calculations: a) The orientation energy of the magnetic dipole is given by U = - μ → . B → Where μ → is the magnetic dipole moment of the coil and B → is the magnetic field We know that the magnitude of μ → is μ = N i A Where i is the current in the coil, N is the number of turns, A is the area of coil. By using the right-hand rule, we see that μ → is in - y direction. Thus, we have, μ = N i A - j ^ μ = - 3 × 2.00 A × 4.00 × 10 - 3 m 2 j ^ μ = - 0.0240 A . m 2 j ^ The corresponding orientation energy is given by U = - μ →

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ISBN: 9781119455608

Author: Halliday

Publisher: WILEY

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Magnetic Force

A magnetic force arises when a charged particle or a current-carrying conductor is placed in a magnetic field. It is created because of the movement of the charged particles.

Question

Chapter 28, Problem 61P

To determine

To find:

a) The orientation energy of the coil in the magnetic field

b) The torque on the coil due to the magnetic field in unit vector notation.

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Chapter 28, Problem 60P

Chapter 28, Problem 62P

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Chapter 28 Solutions

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Ch. 28 - Prob. 11Q Ch. 28 - Prob. 12Q Ch. 28 - Prob. 1P Ch. 28 - A particle of mass 10 g and charge 80 C moves...Ch. 28 - An electron that has an instantaneous velocity of...Ch. 28 - An alpa particle travels at a velocity of...Ch. 28 - GO An electron moves through a unifrom magnetic...Ch. 28 - Prob. 6P Ch. 28 - Prob. 7P Ch. 28 - An electric field of 1.50 kV/m and a perpendicular...Ch. 28 - ILW In Fig. 28-32, an electron accelerated from...Ch. 28 - A proton travels through uniform magnetic and...Ch. 28 - Prob. 11P Ch. 28 - Go At time t1 an electron is sent along the...Ch. 28 - Prob. 13P Ch. 28 - A metal strip 6.50 cm long, 0.850 cm wide, and...Ch. 28 - Prob. 15P Ch. 28 - Prob. 16P Ch. 28 - An alpha particle can be produced in certain...Ch. 28 - Prob. 18P Ch. 28 - Prob. 19P Ch. 28 - Prob. 20P Ch. 28 - SSM An electron of kinetic energy 1.20 keV circles...Ch. 28 - In a nuclear experiment a proton with kinetic...Ch. 28 - What uniform magnetic field, applied perpendicular...Ch. 28 - An electron is accelerated from rest by a...Ch. 28 - a Find the frequency of revolution of an electron...Ch. 28 - Prob. 26P Ch. 28 - A mass spectrometer Fig. 28-12 is used to separate...Ch. 28 - A particle undergoes uniform circular motion of...Ch. 28 - An electron follows a helical path in a uniform...Ch. 28 - GO In Fig. 28-40. an electron with an initial...Ch. 28 - A particular type of fundamental particle decays...Ch. 28 - An source injects an electron of speed v = 1.5 ...Ch. 28 - Prob. 33P Ch. 28 - An electron follows a helical path in a uniform...Ch. 28 - A proton circulates in a cyclotron, beginning...Ch. 28 - Prob. 36P Ch. 28 - Prob. 37P Ch. 28 - In a certain cyclotron a proton moves in a circle...Ch. 28 - SSM A horizontal power line carries a current of...Ch. 28 - A wire 1.80 m long carries a current of 13.0 A and...Ch. 28 - Prob. 41P Ch. 28 - Prob. 42P Ch. 28 - A single-turn current loop, carrying a current of...Ch. 28 - Prob. 44P Ch. 28 - ACA /ACwire 50.0 cm long carries a 0.500 A current...Ch. 28 - In Fig. 28-44, a metal wire of mass m = 24.1 mg...Ch. 28 - GO A 1.0 kg copper rod rests on two horizontal...Ch. 28 - GO A long, rigid conductor, lying along an x axis,...Ch. 28 - Prob. 49P Ch. 28 - An electron moves in a circle of radius r = 5.29 ...Ch. 28 - Prob. 51P Ch. 28 - Prob. 52P Ch. 28 - Prob. 53P Ch. 28 - A magnetic dipole with a dipole moment of...Ch. 28 - Prob. 55P Ch. 28 - Prob. 56P Ch. 28 - Prob. 57P Ch. 28 - Prob. 58P Ch. 28 - A Current loop, carrying a current of 5.0 A, is in...Ch. 28 - Prob. 60P Ch. 28 - Prob. 61P Ch. 28 - Prob. 62P Ch. 28 - A circular loop of wire having a radius of 8.0 cm...Ch. 28 - GO Figure 28-52 gives the orientation energy U of...Ch. 28 - Prob. 65P Ch. 28 - Prob. 66P Ch. 28 - A stationary circular wall clock has a face with a...Ch. 28 - A wire lying along a y axis from y = 0 to y =...Ch. 28 - Atom 1 of mass 35 u and atom 2 of mass 37 u are...Ch. 28 - Prob. 70P Ch. 28 - Physicist S. A. Goudsmit devised a method for...Ch. 28 - A beam of electrons whose kinetic energy is K...Ch. 28 - Prob. 73P Ch. 28 - Prob. 74P Ch. 28 - Prob. 75P Ch. 28 - Prob. 76P Ch. 28 - Prob. 77P Ch. 28 - In Fig. 28-8, show that the ratio of the Hall...Ch. 28 - Prob. 79P Ch. 28 - An electron is moving at 7.20 106 m/s in a...Ch. 28 - Prob. 81P Ch. 28 - Prob. 82P Ch. 28 - Prob. 83P Ch. 28 - A write lying along an x axis from x = 0 to x =...Ch. 28 - Prob. 85P Ch. 28 - Prob. 86P Ch. 28 - Prob. 87P Ch. 28 - Prob. 88P Ch. 28 - In Fig. 28-58, an electron of mass m, charge e,...Ch. 28 - Prob. 90P Ch. 28 - Prob. 91P Ch. 28 - An electron that is moving through a uniform...

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a) The orientation energy of the coil in the magnetic field b) The torque on the coil due to the magnetic field in unit vector notation.

Solution Summary: The author explains how to find the orientation energy of the coil in the magnetic field, and the torque due to it.

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To find: a) The orientation energy of the coil in the magnetic field b) The torque on the coil due to the magnetic field in unit vector notation.

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Chapter 28 Solutions

To find:

a) The orientation energy of the coil in the magnetic field

b) The torque on the coil due to the magnetic field in unit vector notation.