Explanation 1) Concept: We can use the concept of the magnetic force on the current carrying ring. We can use the expression of the vector product of two vectors. 2) Formulae: d F B → = i d L → × B → 3) Given: i) The radius of wire ring is a = 1.8 c m = 1.8 × 10 - 2 m ii) The magnitude of the magnetic field is B = 3.4 m T = 3.4 × 10 - 3 T iii) The direction of the magnetic field at the ring with the normal of the plane is θ = 20 ° iv) The current flowing through the ring is i = 4.6 m A = 4.6 × 10 - 3 A 4) Calculations: The magnitude of magnetic force exerted on the ring: Consider an infinitesimal segment of the loop of length d s . The expression of the magnetic force on the current carrying wire is d F B → = i d L → × B → The magnetic field is perpendicular to the segment. Hence the expression of magnitude of magnetic force on the segment is d F = i B d s The horizontal component of the force has magnitude d F h = i B cos ⁡ θ d s It has direction towards the center of the loop. The vertical component of the force has magnitude d F y = i B sin ⁡ θ d s It has upward direction

11th Edition

ISBN: 9781119455608

Author: Halliday

Publisher: WILEY

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Magnetic Force

A magnetic force arises when a charged particle or a current-carrying conductor is placed in a magnetic field. It is created because of the movement of the charged particles.

Question

Chapter 28, Problem 44P

To determine

To find:

The magnitude of the magnetic force exerted on the ring.

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Chapter 28 Solutions

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Ch. 28 - Prob. 1Q Ch. 28 - Prob. 2Q Ch. 28 - Prob. 3Q Ch. 28 - Prob. 4Q Ch. 28 - In Module 28-2, we discussed a charged particle...Ch. 28 - Prob. 6Q Ch. 28 - Figure 28-27 shows the path of an electron that...Ch. 28 - Figure 28-28 shows the path of an electron in a...Ch. 28 - Prob. 9Q Ch. 28 - Particle round about. Figure 28-29 shows 11 paths...

Ch. 28 - Prob. 11Q Ch. 28 - Prob. 12Q Ch. 28 - Prob. 1P Ch. 28 - A particle of mass 10 g and charge 80 C moves...Ch. 28 - An electron that has an instantaneous velocity of...Ch. 28 - An alpa particle travels at a velocity of...Ch. 28 - GO An electron moves through a unifrom magnetic...Ch. 28 - Prob. 6P Ch. 28 - Prob. 7P Ch. 28 - An electric field of 1.50 kV/m and a perpendicular...Ch. 28 - ILW In Fig. 28-32, an electron accelerated from...Ch. 28 - A proton travels through uniform magnetic and...Ch. 28 - Prob. 11P Ch. 28 - Go At time t1 an electron is sent along the...Ch. 28 - Prob. 13P Ch. 28 - A metal strip 6.50 cm long, 0.850 cm wide, and...Ch. 28 - Prob. 15P Ch. 28 - Prob. 16P Ch. 28 - An alpha particle can be produced in certain...Ch. 28 - Prob. 18P Ch. 28 - Prob. 19P Ch. 28 - Prob. 20P Ch. 28 - SSM An electron of kinetic energy 1.20 keV circles...Ch. 28 - In a nuclear experiment a proton with kinetic...Ch. 28 - What uniform magnetic field, applied perpendicular...Ch. 28 - An electron is accelerated from rest by a...Ch. 28 - a Find the frequency of revolution of an electron...Ch. 28 - Prob. 26P Ch. 28 - A mass spectrometer Fig. 28-12 is used to separate...Ch. 28 - A particle undergoes uniform circular motion of...Ch. 28 - An electron follows a helical path in a uniform...Ch. 28 - GO In Fig. 28-40. an electron with an initial...Ch. 28 - A particular type of fundamental particle decays...Ch. 28 - An source injects an electron of speed v = 1.5 ...Ch. 28 - Prob. 33P Ch. 28 - An electron follows a helical path in a uniform...Ch. 28 - A proton circulates in a cyclotron, beginning...Ch. 28 - Prob. 36P Ch. 28 - Prob. 37P Ch. 28 - In a certain cyclotron a proton moves in a circle...Ch. 28 - SSM A horizontal power line carries a current of...Ch. 28 - A wire 1.80 m long carries a current of 13.0 A and...Ch. 28 - Prob. 41P Ch. 28 - Prob. 42P Ch. 28 - A single-turn current loop, carrying a current of...Ch. 28 - Prob. 44P Ch. 28 - ACA /ACwire 50.0 cm long carries a 0.500 A current...Ch. 28 - In Fig. 28-44, a metal wire of mass m = 24.1 mg...Ch. 28 - GO A 1.0 kg copper rod rests on two horizontal...Ch. 28 - GO A long, rigid conductor, lying along an x axis,...Ch. 28 - Prob. 49P Ch. 28 - An electron moves in a circle of radius r = 5.29 ...Ch. 28 - Prob. 51P Ch. 28 - Prob. 52P Ch. 28 - Prob. 53P Ch. 28 - A magnetic dipole with a dipole moment of...Ch. 28 - Prob. 55P Ch. 28 - Prob. 56P Ch. 28 - Prob. 57P Ch. 28 - Prob. 58P Ch. 28 - A Current loop, carrying a current of 5.0 A, is in...Ch. 28 - Prob. 60P Ch. 28 - Prob. 61P Ch. 28 - Prob. 62P Ch. 28 - A circular loop of wire having a radius of 8.0 cm...Ch. 28 - GO Figure 28-52 gives the orientation energy U of...Ch. 28 - Prob. 65P Ch. 28 - Prob. 66P Ch. 28 - A stationary circular wall clock has a face with a...Ch. 28 - A wire lying along a y axis from y = 0 to y =...Ch. 28 - Atom 1 of mass 35 u and atom 2 of mass 37 u are...Ch. 28 - Prob. 70P Ch. 28 - Physicist S. A. Goudsmit devised a method for...Ch. 28 - A beam of electrons whose kinetic energy is K...Ch. 28 - Prob. 73P Ch. 28 - Prob. 74P Ch. 28 - Prob. 75P Ch. 28 - Prob. 76P Ch. 28 - Prob. 77P Ch. 28 - In Fig. 28-8, show that the ratio of the Hall...Ch. 28 - Prob. 79P Ch. 28 - An electron is moving at 7.20 106 m/s in a...Ch. 28 - Prob. 81P Ch. 28 - Prob. 82P Ch. 28 - Prob. 83P Ch. 28 - A write lying along an x axis from x = 0 to x =...Ch. 28 - Prob. 85P Ch. 28 - Prob. 86P Ch. 28 - Prob. 87P Ch. 28 - Prob. 88P Ch. 28 - In Fig. 28-58, an electron of mass m, charge e,...Ch. 28 - Prob. 90P Ch. 28 - Prob. 91P Ch. 28 - An electron that is moving through a uniform...

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The magnitude of the magnetic force exerted on the ring.

Solution Summary: The author explains how to find the magnitude of the magnetic force exerted on the ring by using the vector product of two vectors.

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To find: The magnitude of the magnetic force exerted on the ring.

Chapter 28 Solutions

To find:

The magnitude of the magnetic force exerted on the ring.