Concept explainers
(a)
Interpretation:
The correct formula for potassium sulfide is to be determined.
Concept introduction:
The formula of an ionic compound represents the total number of ions of each element present in it.
The general rules for writing the systematic names of ionic compounds are as follows:
1) In binary ionic compounds, the name of the metal is written as the original name whereas the name of the non-metal has the root word with the suffix
2) In metals that form more than one ion, the Latin root of the metal is followed by a suffix
3) In the family of two oxoanions, the ion with more oxygen atoms has the non-metal root and a suffix
4) For hydrated ionic compounds, the total number of water molecules are represented by the Greek numerical prefixes followed by the word hydrate.
(b)
Interpretation:
The correct formula for barium iodide is to be determined.
Concept introduction:
The formula of an ionic compound represents the total number of ions of each element present in it.
The general rules for writing the systematic names of ionic compounds are as follows:
1) In binary ionic compounds, the name of the metal is written as the original name whereas the name of the non-metal has the root word with the suffix
2) In metals that form more than one ion, the Latin root of the metal is followed by a suffix
3) In the family of two oxoanions, the ion with more oxygen atoms has the non-metal root and a suffix
4) For hydrated ionic compounds, the total number of water molecules are represented by the Greek numerical prefixes followed by the word hydrate.
(c)
Interpretation:
The correct formula for cesium nitride is to be determined.
Concept introduction:
The formula of an ionic compound represents the total number of ions of each element present in it.
The general rules for writing the systematic names of ionic compounds are as follows:
1) In binary ionic compounds, the name of the metal is written as the original name whereas the name of the non-metal has the root word with the suffix
2) In metals that form more than one ion, the Latin root of the metal is followed by a suffix
3) In the family of two oxoanions, the ion with more oxygen atoms has the non-metal root and a suffix
4) For hydrated ionic compounds, the total number of water molecules are represented by the Greek numerical prefixes followed by the word hydrate.
(d)
Interpretation:
The correct formula for sodium hydride is to be determined.
Concept introduction:
The formula of an ionic compound represents the total number of ions of each element present in it.
The general rules for writing the systematic names of ionic compounds are as follows:
1) In binary ionic compounds, the name of the metal is written as the original name whereas the name of the non-metal has the root word with the suffix
2) In metals that form more than one ion, the Latin root of the metal is followed by a suffix
3) In the family of two oxoanions, the ion with more oxygen atoms has the non-metal root and a suffix
4) For hydrated ionic compounds, the total number of water molecules are represented by the Greek numerical prefixes followed by the word hydrate.
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Chapter 2 Solutions
CHEMISTRY/ALEKS AND CONNECT
- Nonearrow_forwardRedraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forwardK m Choose the best reagents to complete the following reaction. L ZI 0 Problem 4 of 11 A 1. NaOH 2. CH3CH2CH2NH2 1. HCI B OH 2. CH3CH2CH2NH2 DII F1 F2 F3 F4 F5 A F6 C CH3CH2CH2NH2 1. SOCl2 D 2. CH3CH2CH2NH2 1. CH3CH2CH2NH2 E 2. SOCl2 Done PrtScn Home End FA FQ 510 * PgUp M Submit PgDn F11arrow_forward
- given cler asnwerarrow_forwardAdd curved arrows to the reactants in this reaction. A double-barbed curved arrow is used to represent the movement of a pair of electrons. Draw curved arrows. : 0: si H : OH :: H―0: Harrow_forwardConsider this step in a radical reaction: Br N O hv What type of step is this? Check all that apply. Draw the products of the step on the right-hand side of the drawing area below. If more than one set of products is possible, draw any set. Also, draw the mechanism arrows on the left-hand side of the drawing area to show how this happens. O primary Otermination O initialization O electrophilic O none of the above × ☑arrow_forward
- Nonearrow_forwardCan I get a drawing of what is happening with the orbitals (particularly the p orbital) on the O in the OH group? Is the p orbital on the O involved in the ring resonance? Why or why not?arrow_forward1) How many monochlorination products-including stereochemistry- are there for the molecule below:arrow_forward
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