Explanation Section 1: To determine: The force that the wire exerts on the electron. Answer : The force that the wire exerts on the electron F → in terms of unit vectors is ( − 4.32 × 10 − 20 N ) i ^ + ( − 7.20 × 10 − 20 N ) j ^ Explanation : Given Info : The current ( I ) in the wire is 9.00 A in − x direction, electron present at point ( 0 , 0.200 m,0 ) and velocity of the electron ( v → ) is ( 5.00 × 10 4 N ) i ^ − ( 3.00 × 10 4 N ) j ^ . Write the position vector in Cartesian co-ordinate system. r → = x i ^ + y j ^ + z k ^ Substitute 0 m for x , 0.200 m for y , and 0 m for z in r → , r → = ( 0 m ) i ^ + ( 0.200 m ) j ^ + ( 0 m ) k ^ = ( 0.200 m ) j ^ Formula to calculate the magnitude of the r → , r = ( 0 m ) 2 + ( 0.200 m ) 2 + ( 0 m ) 2 = 0.200 m Formula to determine the magnetic field due to the wire at point ( 0 m , 0.200 m,0 m ) , B = μ 0 I 2 π r (I) μ 0 is the magnetic constant, I is the current in the wire, r is the distance between the wire to the electron. Substitute 4 π × 10 − 7 T ⋅ m / A for μ 0 , 9.00 A for I , 3.14 for π and 0.200 m for r in equation (I). B = ( 4 π × 10 − 7 T ⋅ m / A ) ( 9.00 A ) 2 ( 3.14 ) ( 0.200 m ) = 9.00 × 10 − 6 T By using right hand thumb rule the direction of magnetic field will be in the negative z direction. Therefore, B = ( − 9.00 × 10 − 6 T ) k ^ Consider the formula to determine the force on the electron, F → = q ( v → × B → ) (II) Substitute − 1.6 × 10 − 19 C for q , ( 5.00 × 10 4 m / s ) i ^ − ( 3.00 × 10 4 m / s ) j ^ for v → and ( − 9 × 10 − 19 T ) k ^ for B → in equation (II)

University Physics, Volume 2 - Technology Update Custom Edition for Texas A&M - College Station, 2/e

1st Edition

ISBN: 9781323390382

Author: YOUNG

Publisher: Pearson Education

See similar textbooks

Concept explainers

Ferromagnetism

Ferromagnetism is a mechanism by which some materials show magnetic properties. Iron and magnetite, an oxide of iron, are two naturally occurring materials that show the property of ferromagnetism. The word ferromagnetism is derived from the Latin name o…

Question

Chapter 28, Problem 28.60P

To determine

The force that the wire exerts on the electron and its magnitude.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 28, Problem 28.59P

Chapter 28, Problem 28.61P

Students have asked these similar questions

(a) A physics lab instructor is working on a new demonstration. She attaches two identical copper spheres with mass m = 0.180 g to cords of length L as shown in the figure. A Both spheres have the same charge of 6.80 nC, and are in static equilibrium when = 4.95°. What is L (in m)? Assume the cords are massless. 0.150 Draw a free-body diagram, apply Newton's second law for a particle in equilibrium to one of the spheres. Find an equation for the distance between the two spheres in terms of L and 0, and use this expression in your Coulomb force equation. m (b) What If? The charge on both spheres is increased until each cord makes an angle of 0 = 9.90° with the vertical. If both spheres have the same electric charge, what is the charge (in nC) on each sphere in this case? 13.6 ☑ Use the same reasoning as in part (a), only now, use the length found in part (a) and the new angle to solve for the charge. nC

A proton moves at 5.20 x 105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 8.40 × 10³ N/C. Ignore any gravitational effects. (a) Find the time interval required for the proton to travel 6.00 cm horizontally. 1.15e-7 ☑ Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. ns (b) Find its vertical displacement during the time interval in which it travels 6.00 cm horizontally. (Indicate direction with the sign of your answer.) 5.33e-3 ☑ Your response is off by a multiple of ten. mm (c) Find the horizontal and vertical components of its velocity after it has traveled 6.00 cm horizontally. | ↑ + jkm/s

A proton moves at 5.20 105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 8.40 103 N/C. Ignore any gravitational effects. (a) Find the time interval required for the proton to travel 6.00 cm horizontally. (b) Find its vertical displacement during the time interval in which it travels 6.00 cm horizontally. (Indicate direction with the sign of your answer.)

Chapter 28 Solutions

University Physics, Volume 2 - Technology Update Custom Edition for Texas A&M - College Station, 2/e

Ch. 28 - A topic of current interest in physics research is...Ch. 28 - Streams of charged particles emitted from the sun...Ch. 28 - The text discussed the magnetic field of an...Ch. 28 - Prob. Q28.4DQ Ch. 28 - Pairs of conductors carrying current into or out...Ch. 28 - Suppose you have three long, parallel wires...Ch. 28 - In deriving the force on one of the long,...Ch. 28 - Two concentric, coplanar, circular loops of wire...Ch. 28 - A current was sent through a helical coil spring....Ch. 28 - Prob. Q28.10DQ

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The force that the wire exerts on the electron and its magnitude.

Solution Summary: The author explains the force that the wire exerts on the electron and its magnitude.

Concept explainers

The force that the wire exerts on the electron and its magnitude.

Want to see the full answer?

Chapter 28 Solutions