Student Study Guide and Solutions Manual T/A Organic Chemistry
2nd Edition
ISBN: 9781118647950
Author: David R. Klein
Publisher: WILEY
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Question
Chapter 2.8, Problem 22ATS
Interpretation Introduction
Interpretation:
The curved arrow has to be draw to avoid the violation of curved arrow rules.
Concept Introduction:
Curved arrows:
The necessary tools to draw perfect resonance structure are curved arrows. Curved arrows don’t represent the flow of electrons. A tail and a head can be seen in curved arrow.
A head and tail of every arrow are to be drawn in the exact location. The tail represents where the electrons are originated, and the head represents the place where the electrons are going.
Rules for the curved arrow:
- 1) The breaking of single bond should be avoided.
- 2) The octet should never be exceeding for second row elements.
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(Part A) Provide structures of the FGI products and missing reagents (dashed box)
1 eq Na* H*
H
-H
B1
B4
R1
H2 (gas)
Lindlar's
catalyst
A1
Br2
MeOH
H2 (gas)
Lindlar's
catalyst
MeO.
OMe
C6H1402
B2
B3
A1
Product carbons' origins
Draw a box around product
C's that came from A1.
Draw a dashed box around
product C's that came from B1.
Classify each of the amino acids below.
Note for advanced students: none of these amino acids are found in normal proteins.
X
CH2
H3N-CH-COOH3N-CH-COO-
H3N-CH-COO
CH2
CH3-C-CH3
CH2
NH3
N
NH
(Choose one) ▼
(Choose one)
S
CH2
OH
(Choose one) ▼
+
H3N-CH-COO¯
CH2
H3N CH COO H3N-CH-COO
CH2
오오
CH
CH3
CH2
+
O
C
CH3
O=
O_
(Choose one)
(Choose one) ▼
(Choose one)
G
Another standard reference electrode is the standard calomel electrode:
Hg2Cl2(s) (calomel) + 2e2 Hg() +2 Cl(aq)
This electrode is usually constructed with saturated KCI to keep the Cl- concentration
constant (similar to what we discussed with the Ag-AgCl electrode). Under these
conditions the potential of this half-cell is 0.241 V.
A measurement was taken by dipping a Cu wire and a saturated calomel electrode into a
CuSO4 solution:
saturated
calomel
electrode
potentiometer
copper wire
CuSO4
a) Write the half reaction for the Cu electrode.
b) Write the Nernst equation for the Cu electrode, which will include [Cu2+]
c) If the voltage on the potentiometer reads 0.068 V, solve for [Cu²+].
Chapter 2 Solutions
Student Study Guide and Solutions Manual T/A Organic Chemistry
Ch. 2.1 - Prob. 1LTSCh. 2.1 - Prob. 1PTSCh. 2.1 - Prob. 2ATSCh. 2.1 - Prob. 3ATSCh. 2.1 - Prob. 4ATSCh. 2.2 - Prob. 2LTSCh. 2.2 - Prob. 5PTSCh. 2.2 - Prob. 6ATSCh. 2.2 - Prob. 7ATSCh. 2.2 - Prob. 3LTS
Ch. 2.2 - Prob. 8PTSCh. 2.2 - Prob. 9ATSCh. 2.2 - Prob. 10ATSCh. 2.3 - Prob. 11CCCh. 2.4 - Prob. 12CCCh. 2.4 - Prob. 13CCCh. 2.5 - Prob. 4LTSCh. 2.5 - Prob. 14PTSCh. 2.5 - Prob. 15ATSCh. 2.5 - Prob. 5LTSCh. 2.5 - Prob. 16PTSCh. 2.5 - Prob. 17ATSCh. 2.5 - Prob. 18ATSCh. 2.5 - Prob. 19ATSCh. 2.6 - Prob. 20CCCh. 2.8 - Prob. 6LTSCh. 2.8 - Prob. 21PTSCh. 2.8 - Prob. 22ATSCh. 2.9 - Prob. 7LTSCh. 2.9 - Prob. 23PTSCh. 2.9 - Prob. 24ATSCh. 2.10 - Prob. 25CCCh. 2.10 - Prob. 26CCCh. 2.10 - Prob. 27CCCh. 2.10 - Prob. 28CCCh. 2.10 - Prob. 29CCCh. 2.10 - Prob. 30CCCh. 2.10 - Prob. 31CCCh. 2.10 - Prob. 32CCCh. 2.11 - Prob. 8LTSCh. 2.11 - Prob. 33PTSCh. 2.11 - Prob. 34ATSCh. 2.11 - Prob. 35ATSCh. 2.12 - Prob. 9LTSCh. 2.12 - Prob. 36PTSCh. 2.12 - Prob. 37ATSCh. 2.12 - Prob. 38ATSCh. 2 - Prob. 39PPCh. 2 - Prob. 40PPCh. 2 - Prob. 41PPCh. 2 - Prob. 42PPCh. 2 - Prob. 43PPCh. 2 - Prob. 44PPCh. 2 - Prob. 45PPCh. 2 - Prob. 46PPCh. 2 - Prob. 47PPCh. 2 - Prob. 48PPCh. 2 - Prob. 49PPCh. 2 - Prob. 50PPCh. 2 - Prob. 51PPCh. 2 - Prob. 52PPCh. 2 - Prob. 53PPCh. 2 - Prob. 54PPCh. 2 - Prob. 55PPCh. 2 - Prob. 56PPCh. 2 - Prob. 57PPCh. 2 - Prob. 58PPCh. 2 - Prob. 59PPCh. 2 - Prob. 60PPCh. 2 - Prob. 61PPCh. 2 - Prob. 62PPCh. 2 - Prob. 65IPCh. 2 - Prob. 66IPCh. 2 - Prob. 67IP
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- 2. (Part B). Identify a sequence of FGI that prepares the Synthesis Target 2,4-dimethoxy- pentane. All carbons in the Synthesis Target must start as carbons in either ethyne, propyne or methanol. Hint: use your analysis of Product carbons' origins (Part A) to identify possible structure(s) of a precursor that can be converted to the Synthesis Target using one FGI. All carbons in the Synthesis Target must start as carbons in one of the three compounds below. H = -H H = -Me ethyne propyne Synthesis Target 2,4-dimethoxypentane MeOH methanol OMe OMe MeO. OMe C₂H₁₂O₂ Product carbons' origins Draw a box around product C's that came from A1. Draw a dashed box around product C's that came from B1.arrow_forwardDraw the skeletal ("line") structure of the smallest organic molecule that produces potassium 3-hydroxypropanoate when reacted with KOH. Click and drag to start drawing a structure. Sarrow_forwardDraw the skeleatal strucarrow_forward
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