Physics for Scientists and Engineers
Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
Question
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Chapter 28, Problem 21P

(a)

To determine

The magnetic flux through the coil when the axis of the coil is vertical.

(a)

Expert Solution
Check Mark

Answer to Problem 21P

The magnetic flux through the coil when the axis of the coil is vertical is 0 .

Explanation of Solution

Given:

The turns of the coilis n=25 .

The radius of the coil is r=5.0cm .

The axis of coil is vertical.

Formula used:

The expression for the magnetic flux through the coil is given by,

  ϕm=NBAcosθ

Calculation:

The expression for the magnetic flux through the coil is given by,

  ϕm=NBAcosθ=NBπr2cosθ=25(0.70G× 1T 10 4 G)π(5.0× 10 2m)2cosθ=(13.7μWb)cosθ

If the plane of the coil is vertical, θ=90° ,

  ϕm=(13.7μWb)cos90°=0

Conclusion:

Therefore, the magnetic flux through the coil when the axis of the coil is vertical is 0 .

(b)

To determine

The magnetic flux through the coil when the axis of the coil is horizontal.

(b)

Expert Solution
Check Mark

Answer to Problem 21P

The magnetic flux through the coil when the axis of the coil is vertical is 14μWb .

Explanation of Solution

Given:

The axis of coil is vertical.

Formula used:

The expression for the magnetic flux through the coil is given by,

  ϕm=NBAcosθ

Calculation:

The expression for the magnetic flux through the coil is given by,

  ϕm=NBAcosθ=NBπr2cosθ=25(0.70G× 1T 10 4 G)π(5.0× 10 2m)2cosθ=(13.7μWb)cosθ

If the plane of the coil is horizontal, θ=0° ,

  ϕm=(13.7μWb)cos0°14μWb

Conclusion:

Therefore, the magnetic flux through the coil when the axis of the coil is vertical is 14μWb .

(c)

To determine

The magnetic flux through the coil when the axis of the coil is horizontal with the axis pointing to east.

(c)

Expert Solution
Check Mark

Answer to Problem 21P

The magnetic flux through the coil when the axis of the coil is horizontal with its axis pointing east, is 0 .

Explanation of Solution

Given:

The axis of coil is vertical.

Formula used:

The expression for the magnetic flux through the coil is given by,

  ϕm=NBAcosθ

Calculation:

The expression for the magnetic flux through the coil is given by,

  ϕm=NBAcosθ=NBπr2cosθ=25(0.70G× 1T 10 4 G)π(5.0× 10 2m)2cosθ=(13.7μWb)cosθ

If the plane of the coil is horizontal with its axis pointing east, θ=90° ,

  ϕm=(13.7μWb)cos90°=0

Conclusion:

Therefore, the magnetic flux through the coil when the axis of the coil is horizontal with its axis pointing east, is 0 .

(d)

To determine

The magnetic flux through the coil when the axis of the coil is horizontal with the axis marking an angle of 30 with north.

(d)

Expert Solution
Check Mark

Answer to Problem 21P

The magnetic flux through the coil when the axis of the coil is horizontal with the axis marking an angle of 30 with northis 12μWb .

Explanation of Solution

Given:

The axis of coil is horizontal with the axis marking an angle of 30 with north.

Formula used:

The expression for the magnetic flux through the coil is given by,

  ϕm=NBAcosθ

Calculation:

The expression for the magnetic flux through the coil is given by,

  ϕm=NBAcosθ=NBπr2cosθ=25(0.70G× 1T 10 4 G)π(5.0× 10 2m)2cosθ=(13.7μWb)cosθ

If the plane of the coil is horizontal with its axis making an angle of 30° with north, θ=90° ,

  ϕm=(1.37μWb)cos30°=( 3 2)(1.37μWb)=12μWb

Conclusion:

Therefore, the magnetic flux through the coil when the axis of the coil is is horizontal with the axis marking an angle of 30° with north is 12μWb .

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Chapter 28 Solutions

Physics for Scientists and Engineers

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