Electrical Wiring Residential
18th Edition
ISBN: 9781285170954
Author: Ray C. Mullin, Phil Simmons
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 28, Problem 1R
What is the minimum size service for a one-family dwelling? ____________________
Expert Solution & Answer
To determine
Find the minimum rating of service size for a one-family dwelling.
Answer to Problem 1R
The minimum rating of service size for a one-family dwelling is
Explanation of Solution
Discussion:
The National Electrical Code committee develops NEC – the standard electrical code, and the main objective for the origin of the code is to protect and safeguard people and elements from electrical hazards. The codes that explain the rating of service disconnecting means are defined in an article NEC 230.79.
According to an article NEC 230.79 (C), for a one-family dwelling, the rating of the service disconnecting means should not be less than
Conclusion:
Thus, the minimum rating of service size for a one-family dwelling is
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
A3 m long cantilever ABC is built-in at A, partially supported at B, 2 m from A,
with a force of 10 kN and carries a vertical load of 20 kN at C. A uniformly distributed
bad of 5 kN/m is also applied between A and B. Determine
(a) the values of the vertical reaction and built-in moment at A and
(b) the deflection of the free end C of the cantilever,
Develop an expression for the slope of the beam at any position and hence plot a slope diagram.
E = 208GN / (m ^ 2) and 1 = 24 * 10 ^ - 6 * m ^ 4
7. Consider the following feedback system with a proportional controller.
K
G(s)
The plant transfer function is given by
G(s) =
10
(s + 2)(s + 10)
You want the system to have a damping ratio of 0.3 for unit step response. What is the
value of K you need to choose to achieve the desired damping ratio? For that value of
K, find the steady-state error for ramp input and settling time for step input.
Hint: Sketch the root locus and find the point in the root locus that intersects with z =
0.3 line.
Create the PLC ladder logic diagram
for the logic gate circuit displayed in
Figure 7-35. The pilot light red (PLTR)
output section has three inputs: PBR,
PBG, and SW. Pushbutton red (PBR)
and pushbutton green (PBG) are inputs
to an XOR logic gate. The output of the
XOR logic gate and the inverted switch
SW) are inputs to a two-input AND
logic gate. These inputs generate the
pilot light red (PLTR) output.
The two-input AND logic gate output
is also fed into a two-input NAND logic
PBR
PBG
SW
TSW
PLTR
Figure 7-35. Logic gate circuit for Example 7-3.
PLTW
Goodheart-Willcox Publisher
gate. The temperature switch (TSW) is the other input to the NAND logic gate. The output generated from
the NAND logic gate is labeled pilot light white (PLTW).
Chapter 28 Solutions
Electrical Wiring Residential
Ch. 28 - What is the minimum size service for a one-family...Ch. 28 - Prob. 2RCh. 28 - Prob. 3RCh. 28 - Prob. 4RCh. 28 - Prob. 5RCh. 28 - Prob. 6RCh. 28 - Prob. 7RCh. 28 - List the standard sizes of fuses and circuit...Ch. 28 - Prob. 9RCh. 28 - Using the method shown in this unit, what is the...
Ch. 28 - State four possible combinations of service...Ch. 28 - Which Code section states that all overcurrent...Ch. 28 - All electrical components have some sort of...Ch. 28 - Arc-fault damage is closely related to the value...Ch. 28 - The utility company has provided a letter to the...Ch. 28 - While working on the main panelboard that is...Ch. 28 - Repeat problem 16 for a main service panel that...Ch. 28 - NEC ______________________________ generally...Ch. 28 - Prob. 19RCh. 28 - Prob. 20RCh. 28 - Overcurrent devices must be accessible. (True)...
Additional Engineering Textbook Solutions
Find more solutions based on key concepts
What is an uninitialized variable?
Starting Out with Programming Logic and Design (5th Edition) (What's New in Computer Science)
How is the hydrodynamic entry length defined for flow in a pipe? Is the entry length longer in laminar or turbu...
Fluid Mechanics: Fundamentals and Applications
CONCEPT QUESTIONS
15.CQ3 The ball rolls without slipping on the fixed surface as shown. What is the direction ...
Vector Mechanics for Engineers: Statics and Dynamics
This optional Google account security feature sends you a message with a code that you must enter, in addition ...
SURVEY OF OPERATING SYSTEMS
The solid steel shaft AC has a diameter of 25 mm and is supported by smooth bearings at D and E. It is coupled ...
Mechanics of Materials (10th Edition)
Convert each of the following binary representations to its equivalent base ten form: a. 101010 b. 100001 c. 10...
Computer Science: An Overview (13th Edition) (What's New in Computer Science)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Imaginary Axis (seconds) 1 6. Root locus for a closed-loop system with L(s) = is shown below. s(s+4)(s+6) 15 10- 0.89 0.95 0.988 0.988 -10 0.95 -15 -25 0.89 20 Root Locus 0.81 0.7 0.56 0.38 0.2 5 10 15 System: sys Gain: 239 Pole: -0.00417 +4.89 Damping: 0.000854 Overshoot (%): 99.7 Frequency (rad/s): 4.89 System: sys Gain: 16.9 Pole: -1.57 Damping: 1 Overshoot (%): 0 Frequency (rad/s): 1.57 0.81 0.7 0.56 0.38 0.2 -20 -15 -10 -5 5 10 Real Axis (seconds) From the values shown in the figure, compute the following. a) Range of K for which the closed-loop system is stable. b) Range of K for which the closed-loop step response will not have any overshoot. Note that when all poles are real, the step response has no overshoot. c) Smallest possible peak time of the system. Note that peak time is the smallest when wa is the largest for the dominant pole. d) Smallest possible settling time of the system. Note that peak time is the smallest when σ is the largest for the dominant pole.arrow_forwardFor a band-rejection filter, the response drops below this half power point at two locations as visualised in Figure 7, we need to find these frequencies. Let's call the lower frequency-3dB point as fr and the higher frequency -3dB point fH. We can then find out the bandwidth as f=fHfL, as illustrated in Figure 7. 0dB Af -3 dB Figure 7. Band reject filter response diagram Considering your AC simulation frequency response and referring to Figure 7, measure the following from your AC simulation. 1% accuracy: (a) Upper-3db Frequency (fH) = Hz (b) Lower-3db Frequency (fL) = Hz (c) Bandwidth (Aƒ) = Hz (d) Quality Factor (Q) =arrow_forwardP 4.4-21 Determine the values of the node voltages V1, V2, and v3 for the circuit shown in Figure P 4.4-21. 29 ww 12 V +51 Aia ww 22. +21 ΖΩ www ΖΩ w +371 ①1 1 Aarrow_forward
- 1. What is the theoretical attenuation of the output voltage at the resonant frequency? Answer to within 1%, or enter 0, or infinity (as “inf”) Attenuation =arrow_forwardWhat is the settling time for your output signal (BRF_OUT)? For this question, We define the settling time as the period of time it has taken for the output to settle into a steady state - ie when your oscillation first decays (aka reduces) to less than approximately 1/20 (5%) of the initial value. (a) Settling time = 22 μs Your last answer was interpreted as follows: Incorrect answer. Check 22 222 What is the peak to peak output voltage (BRF_OUT pp) at the steady state condition? You may need to use the zoom function to perform this calculation. Select a time point that is two times the settling time you answered in the question above. Answer to within 10% accuracy. (a) BRF_OUT pp= mVpp As you may have noticed, the output voltage amplitude is a tiny fraction of the input voltage, i.e. it has been significantly attenuated. Calculate the attenuation (decibels = dB) in the output signal as compared to the input based on the formula given below. Answer to within 1% accuracy.…arrow_forwardmy previous answers for a,b,d were wrong a = 1050 b = 950 d=9.99 c was the only correct value i got previously c = 100hz is correctarrow_forward
- V₁(t) ww ZRI ZLI ZL2 ZTH Zci VTH Zc21 Figure 8. Circuit diagram showing calculation approach for VTH and Z TH we want to create a blackbox for the red region, we want to use the same input signal conditions as previously the design of your interference ector circuit: Sine wave with a 1 Vpp, with a frequency of 100 kHz (interference) Square wave with 2.4Vpp, with a frequency of 10 kHz (signal) member an AC Thevenin equivalent is only valid at one frequency. We have chosen to calculate the Thevenin equivalent circuit (and therefore the ackbox) at the interference frequency (i.e. 100 kHz), and the signal frequency (i.e. 10 kHz) as these are the key frequencies to analyse. Your boss is assured you that the waveform converter module has been pre-optimised to the DAB Receiver if you use the recommended circuit topology.arrow_forwardVs(t) + v(t) + vi(t) ZR ZL Figure 1: Second order RLC circuit Zc + ve(t) You are requested to design the circuit shown in Figure 1. The circuit is assumed to be operating at its resonant frequency when it is fed by a sinusoidal voltage source Vs (t) = 2sin(le6t). To help design your circuit you have been given the value of inductive reactance ZL = j1000. Assume that the amplitude of the current at resonance is Is (t) = 2 mA. Based on this information, answer the following to help design your circuit. Use cartesian notation for your answers, where required.arrow_forwardWhat is the attenuation at the resonant frequency? You should use the LTSpice cursors for your measurement. Answer to within 1% accuracy, or enter 0, or infinity (as "inf") (a) Attenuation (dB) = dB Check You may have noticed that it was significantly easier to use frequency-domain "AC" simulation to measure the attenuation, compared to the steps we performed in the last few questions. (i.e. via a time-domain "transient" simulation). AC analysis allows us to observe and quantify large scale positive or negative changes in a signal of interest across a wide range of different frequencies. From the response you will notice that only frequencies that are relatively close to 100 kHz have been attenuated. This is the result of the Band-reject filter you have designed, and shows the 'rejection' (aka attenuation) of any frequencies that lie in a given band. The obvious follow-up question is how do we define this band? We use a quantity known as the bandwidth. A commonly used measurement for…arrow_forward
- V₁(t) ww ZRI ZLI ZL2 ZTH Zci VTH Zc21 Figure 8. Circuit diagram showing calculation approach for VTH and Z TH we want to create a blackbox for the red region, we want to use the same input signal conditions as previously the design of your interference ector circuit: Sine wave with a 1 Vpp, with a frequency of 100 kHz (interference) Square wave with 2.4Vpp, with a frequency of 10 kHz (signal) member an AC Thevenin equivalent is only valid at one frequency. We have chosen to calculate the Thevenin equivalent circuit (and therefore the ackbox) at the interference frequency (i.e. 100 kHz), and the signal frequency (i.e. 10 kHz) as these are the key frequencies to analyse. Your boss is assured you that the waveform converter module has been pre-optimised to the DAB Receiver if you use the recommended circuit topology.arrow_forwardVs(t) + v(t) + vi(t) ZR ZL Figure 1: Second order RLC circuit Zc + ve(t) You are requested to design the circuit shown in Figure 1. The circuit is assumed to be operating at its resonant frequency when it is fed by a sinusoidal voltage source Vs (t) = 2sin(le6t). To help design your circuit you have been given the value of inductive reactance ZL = j1000. Assume that the amplitude of the current at resonance is Is (t) = 2 mA. Based on this information, answer the following to help design your circuit. Use cartesian notation for your answers, where required.arrow_forwardFor a band-rejection filter, the response drops below this half power point at two locations as visualised in Figure 7, we need to find these frequencies. Let's call the lower frequency-3dB point as fr and the higher frequency -3dB point fH. We can then find out the bandwidth as f=fHfL, as illustrated in Figure 7. 0dB Af -3 dB Figure 7. Band reject filter response diagram Considering your AC simulation frequency response and referring to Figure 7, measure the following from your AC simulation. 1% accuracy: (a) Upper-3db Frequency (fH) = Hz (b) Lower-3db Frequency (fL) = Hz (c) Bandwidth (Aƒ) = Hz (d) Quality Factor (Q) =arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
EBK ELECTRICAL WIRING RESIDENTIALElectrical EngineeringISBN:9781337516549Author:SimmonsPublisher:CENGAGE LEARNING - CONSIGNMENT
EBK ELECTRICAL WIRING RESIDENTIAL
Electrical Engineering
ISBN:9781337516549
Author:Simmons
Publisher:CENGAGE LEARNING - CONSIGNMENT
What is an electric furnace and how does it work?; Author: Fire & Ice Heating and Air Conditioning Inc;https://www.youtube.com/watch?v=wjAWecPGi0M;License: Standard Youtube License