COLLEGE PHYSICS,VOLUME 1
2nd Edition
ISBN: 9781319115104
Author: Freedman
Publisher: MAC HIGHER
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Chapter 27, Problem 54QAP
To determine
How many kilograms of U-235 must completely fission to produce 1000 MW of power continuously for one year?
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rections: For problem
rough 3, read
each question carefully and be sure to
show all work.
1. Determine if
9(4a²-4ab+b²) = (6a-3b)² is a
polynomial identity.
2. Is (2x-y) (8x3+ y³) equivalent to
16x4-y4?
3. Find an expression that is equivalent to
(a - b)³.
Directions: For problems 4 and 5,
algebraically prove that the following
equations are polynomial identities. Show
all of your work and explain each step.
4. (2x+5)² = 4x(x+5)+25
5. (4x+6y)(x-2y)=2(2x²-xy-6y²)
Name:
Mussels & bem
A section of a river currently has a population of 20 zebra mussels. The
population of zebra mussels increases 60 % each month. What will be the
population of zebra mussels after 2 years?
9
10
# of
months
# of
mussels
1
2
3
4
5
6
7
8
o
Graph your data. Remember to title your graph.
What scale should be used on the y-axis?
What scale should be used on the x-axis?
Exponential Growth Equation
y = a(1+r)*
Chapter 27 Solutions
COLLEGE PHYSICS,VOLUME 1
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- Nicole organized a new corporation. The corporation began business on April 1 of year 1. She made the following expenditures associated with getting the corporation started: Expense Date Amount Attorney fees for articles of incorporation February 10 $ 40,500 March 1-March 30 wages March 30 6,550 March 1-March 30 rent Stock issuance costs March 30 2,850 April 1-May 30 wages Note: Leave no answer blank. Enter zero if applicable. April 1 May 30 24,000 16,375 c. What amount can the corporation deduct as amortization expense for the organizational expenditures and for the start-up costs for year 1 [not including the amount determined in part (b)]? Note: Round intermediate calculations to 2 decimal places and final answer to the nearest whole dollar amount. Start-up costs amortized Organizational expenditures amortizedarrow_forwardLast Chance Mine (LCM) purchased a coal deposit for $2,918,300. It estimated it would extract 18,950 tons of coal from the deposit. LCM mined the coal and sold it, reporting gross receipts of $1.24 million, $13 million, and $11 million for years 1 through 3, respectively. During years 1-3, LCM reported net income (loss) from the coal deposit activity in the amount of ($11,400), $550,000, and $502,500, respectively. In years 1-3, LCM extracted 19,950 tons of coal as follows: (1) Tons of Coal 18,950 Depletion (2) Basis (2)(1) Rate $2,918,300 $154.00 Tons Extracted per Year Year 1 4,500 Year 2 8,850 Year 3 6,600 Note: Leave no answer blank. Enter zero if applicable. Enter your answers in dollars and not in millions of dollars. a. What is LCM's cost depletion for years 1, 2, and 3? Cost Depletion Year 1 Year 2 Year 3arrow_forwardConsider the following equation. log1/9' =6 Find the value of x. Round your answer to the nearest thousandth. x = ✓arrow_forward
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- Expanding a logarithmic expression: Problem type 2 Use the properties of logarithms to expand the following expression. 3 yz log 5 x 0/3 An Each logarithm should involve only one variable and should not have any radicals or exponents. You may assume that all variables are positive. log yz 3 厚 5 Explanation Check log ☑ 2025 MG ¿W MIII LLC. All Rights Reserved. Terms of Use | Privacy Centerarrow_forwardWhat is the domain and range, thank you !!arrow_forwardAssume a bivariate patch p(u, v) over the unit square [0, 1]² that is given as a tensor product patch where u-sections (u fixed to some constant û; v varying across [0, 1]) are quadratic polynomials Pu:û(v) = p(û, v) while v-sections are lines pv:ô (u) = p(u, v). The boundary lines pv:o(u) and pv:1 (u) are specified by their end points p(0,0) 0.8 and p(1,0) 0.2 as well as p(0, 1) 0.3 and p(1, 1) = 0.8. The boundary quadratics pu:o(v) and pu:1 (v) interpolate p(0,0.5) = 0.1 and p(1, 0.5) = 0.9 in addition to the above given four corner-values. = = = Use Pu:û(v) = (1, v, v² ) Mq (Pu:û(0), Pu:û (0.5), Pu:û(1)) with Ma = 1 0 0 -3 4-1 2 4 2 (Pv:ô as well as pu: (u) = (1, u) M₁ (pv:v (0), P: (1)) with M₁ = = (19) 0 to formulate p(u, v) using the "geometric input" G with G = = (P(0,0%) p(0,0) p(0,0.5) p(0,1) ) = ( 0.39 0.8 0.1 0.3 0.2 0.9 0.8 p(1,0) p(1, 0.5) p(1, 1) See the figure below for (left) a selection of iso-lines of p(u, v) and (right) a 3D rendering of p(u, v) as a height surface…arrow_forward
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