Chapter 27, Problem 50QAP

To determine

(A)

Complete the fission reaction

Answer to Problem 50QAP

  $Am+8n\to Sr+La+4n$

Explanation of Solution

Given information:

  $Am+x\to Sr+La+4n$

Calculation:

To calculate the no of neutrons release from the above equation. The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
  $\begin{array}{l}235+x=90+149+4\\ x=8\end{array}$

So, 8 neutrons will be released from the above equation
Hence, the complete reaction would be
  $Am+8n\to Sr+La+4n$

To determine

(B)

Complete the fission reaction

Answer to Problem 50QAP

  $Pa+n\to Zr+Sb+12n$

Explanation of Solution

Given information:

  $Pa+n\to x+Sb+12n$

Calculation:

The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
  $\begin{array}{l}244+1=x+131+12\times 1\\ x=102\end{array}$

And, Atomic Number
  $\begin{array}{l}91=y+51\\ y=40\end{array}$

So, Check the periodic table and find the element whose atomic number is 40
Hence, the complete reaction would be
  $Pa+n\to Zr+Sb+12n$

To determine

(C)

Complete the fission reaction

Answer to Problem 50QAP

  $Cm+n\to Se+Sm+6n$

Explanation of Solution

Given information:

  $x+n\to Se+Sm+6n$

Calculation:

The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
  $\begin{array}{l}x+1=92+153+6\times 1\\ x=250\end{array}$

And, Atomic Number
  $\begin{array}{l}y=34+62\\ y=96\end{array}$

So, Check the periodic table and find the element whose atomic number is 96.

Hence, the complete reaction would be
  $Cm+n\to Se+Sm+6n$

To determine

(D)

Complete the fission reaction

Answer to Problem 50QAP

  $Fm+n\to Rh+Cs+9n$

Explanation of Solution

Given information:

  $Fm+n\to Rh+x+9n$

Calculation:

The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
  $\begin{array}{l}262+1=112+x+9\times 1\\ x=142\end{array}$

And, Atomic Number
  $\begin{array}{l}100=45+y\\ y=55\end{array}$

So, Check the periodic table and find the element whose atomic number is 55.

Hence, the complete reaction would be
  $Fm+n\to Rh+Cs+9n$