COLLEGE PHYSICS,VOLUME 1
COLLEGE PHYSICS,VOLUME 1
2nd Edition
ISBN: 9781319115104
Author: Freedman
Publisher: MAC HIGHER
Question
Book Icon
Chapter 27, Problem 50QAP
To determine

(A)

Complete the fission reaction

Expert Solution
Check Mark

Answer to Problem 50QAP

  A95235m+8n01S3890r+L57149a+4n01

Explanation of Solution

Given information:

  A95235m+x0xS3890r+L57149a+4n01

Calculation:

To calculate the no of neutrons release from the above equation. The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
  235+x=90+149+4x=8

So, 8 neutrons will be released from the above equation
Hence, the complete reaction would be
  A95235m+8n01S3890r+L57149a+4n01

To determine

(B)

Complete the fission reaction

Expert Solution
Check Mark

Answer to Problem 50QAP

  P91244a+n01Z40102r+S51131b+12n01

Explanation of Solution

Given information:

  P91244a+n01xyx+S51131b+12n01

Calculation:

The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
  244+1=x+131+12×1x=102

And, Atomic Number
  91=y+51y=40

So, Check the periodic table and find the element whose atomic number is 40
Hence, the complete reaction would be
  P91244a+n01Z40102r+S51131b+12n01

To determine

(C)

Complete the fission reaction

Expert Solution
Check Mark

Answer to Problem 50QAP

  C96250m+n01S3492e+S62153m+6n01

Explanation of Solution

Given information:

  xyx+n01S3492e+S62153m+6n01

Calculation:

The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
  x+1=92+153+6×1x=250

And, Atomic Number
  y=34+62y=96

So, Check the periodic table and find the element whose atomic number is 96.

Hence, the complete reaction would be
  C96250m+n01S3492e+S62153m+6n01

To determine

(D)

Complete the fission reaction

Expert Solution
Check Mark

Answer to Problem 50QAP

  F100262m+n01R45112h+C55142s+9n01

Explanation of Solution

Given information:

  F100262m+n01R45112h+xyx+9n01

Calculation:

The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
  262+1=112+x+9×1x=142

And, Atomic Number
  100=45+yy=55

So, Check the periodic table and find the element whose atomic number is 55.

Hence, the complete reaction would be
  F100262m+n01R45112h+C55142s+9n01

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Current Attempt in Progress In the figure what is the net electric potential at point P due to the four particles if V = 0 at infinity, q = 2.12 fC, and d = 1.75 cm? d Number MI Units +q
Current Attempt in Progress In the figure what is the net electric potential at point P due to the four particles if V = 0 at infinity, q = 2.12 fC, and d = 1.75 cm? d Number MI Units +q
A 0.500 kg sphere moving with a velocity given by (2.00î – 2.60ĵ + 1.00k) m/s strikes another sphere of mass 1.50 kg moving with an initial velocity of (−1.00î + 2.00ĵ – 3.20k) m/s. (a) The velocity of the 0.500 kg sphere after the collision is (-0.90î + 3.00ĵ − 8.00k) m/s. Find the final velocity of the 1.50 kg sphere. R = m/s Identify the kind of collision (elastic, inelastic, or perfectly inelastic). ○ elastic O inelastic O perfectly inelastic (b) Now assume the velocity of the 0.500 kg sphere after the collision is (-0.250 + 0.850ĵ - 2.15k) m/s. Find the final velocity of the 1.50 kg sphere. ✓ = m/s Identify the kind of collision. O elastic O inelastic O perfectly inelastic (c) Take the velocity of the 0.500 kg sphere after the collision as (−1.00ỉ + 3.40] + ak) m/s. Find the value of a and the velocity of the 1.50 kg sphere after an elastic collision. (Two values of a are possible, a positive value and a negative value. Report each with their corresponding final velocities.) a…

Chapter 27 Solutions

COLLEGE PHYSICS,VOLUME 1

Ch. 27 - Prob. 11QAPCh. 27 - Prob. 12QAPCh. 27 - Prob. 13QAPCh. 27 - Prob. 14QAPCh. 27 - Prob. 15QAPCh. 27 - Prob. 16QAPCh. 27 - Prob. 17QAPCh. 27 - Prob. 18QAPCh. 27 - Prob. 19QAPCh. 27 - Prob. 20QAPCh. 27 - Prob. 21QAPCh. 27 - Prob. 22QAPCh. 27 - Prob. 23QAPCh. 27 - Prob. 24QAPCh. 27 - Prob. 25QAPCh. 27 - Prob. 26QAPCh. 27 - Prob. 27QAPCh. 27 - Prob. 28QAPCh. 27 - Prob. 29QAPCh. 27 - Prob. 30QAPCh. 27 - Prob. 31QAPCh. 27 - Prob. 32QAPCh. 27 - Prob. 33QAPCh. 27 - Prob. 34QAPCh. 27 - Prob. 35QAPCh. 27 - Prob. 36QAPCh. 27 - Prob. 37QAPCh. 27 - Prob. 38QAPCh. 27 - Prob. 39QAPCh. 27 - Prob. 40QAPCh. 27 - Prob. 41QAPCh. 27 - Prob. 42QAPCh. 27 - Prob. 43QAPCh. 27 - Prob. 44QAPCh. 27 - Prob. 45QAPCh. 27 - Prob. 46QAPCh. 27 - Prob. 47QAPCh. 27 - Prob. 48QAPCh. 27 - Prob. 49QAPCh. 27 - Prob. 50QAPCh. 27 - Prob. 51QAPCh. 27 - Prob. 52QAPCh. 27 - Prob. 53QAPCh. 27 - Prob. 54QAPCh. 27 - Prob. 55QAPCh. 27 - Prob. 56QAPCh. 27 - Prob. 57QAPCh. 27 - Prob. 58QAPCh. 27 - Prob. 59QAPCh. 27 - Prob. 60QAPCh. 27 - Prob. 61QAPCh. 27 - Prob. 62QAPCh. 27 - Prob. 63QAPCh. 27 - Prob. 64QAPCh. 27 - Prob. 65QAPCh. 27 - Prob. 66QAPCh. 27 - Prob. 67QAPCh. 27 - Prob. 68QAPCh. 27 - Prob. 69QAPCh. 27 - Prob. 70QAPCh. 27 - Prob. 71QAPCh. 27 - Prob. 72QAPCh. 27 - Prob. 73QAPCh. 27 - Prob. 74QAPCh. 27 - Prob. 75QAPCh. 27 - Prob. 76QAPCh. 27 - Prob. 77QAPCh. 27 - Prob. 78QAPCh. 27 - Prob. 79QAPCh. 27 - Prob. 80QAPCh. 27 - Prob. 81QAPCh. 27 - Prob. 82QAPCh. 27 - Prob. 83QAPCh. 27 - Prob. 84QAPCh. 27 - Prob. 85QAPCh. 27 - Prob. 86QAPCh. 27 - Prob. 87QAPCh. 27 - Prob. 88QAPCh. 27 - Prob. 89QAPCh. 27 - Prob. 90QAPCh. 27 - Prob. 91QAPCh. 27 - Prob. 92QAPCh. 27 - Prob. 93QAPCh. 27 - Prob. 94QAPCh. 27 - Prob. 95QAPCh. 27 - Prob. 96QAPCh. 27 - Prob. 97QAP
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
  • Text book image
    College Physics
    Physics
    ISBN:9781938168000
    Author:Paul Peter Urone, Roger Hinrichs
    Publisher:OpenStax College
    Text book image
    College Physics
    Physics
    ISBN:9781285737027
    Author:Raymond A. Serway, Chris Vuille
    Publisher:Cengage Learning
    Text book image
    Inquiry into Physics
    Physics
    ISBN:9781337515863
    Author:Ostdiek
    Publisher:Cengage
  • Text book image
    University Physics Volume 3
    Physics
    ISBN:9781938168185
    Author:William Moebs, Jeff Sanny
    Publisher:OpenStax
    Text book image
    College Physics
    Physics
    ISBN:9781305952300
    Author:Raymond A. Serway, Chris Vuille
    Publisher:Cengage Learning
    Text book image
    Modern Physics
    Physics
    ISBN:9781111794378
    Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
    Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Text book image
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
Inquiry into Physics
Physics
ISBN:9781337515863
Author:Ostdiek
Publisher:Cengage
Text book image
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning