FlipIt for College Physics (Algebra Version - Six Months Access)
FlipIt for College Physics (Algebra Version - Six Months Access)
17th Edition
ISBN: 9781319032432
Author: Todd Ruskell
Publisher: W.H. Freeman & Co
Question
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Chapter 27, Problem 50QAP
To determine

(A)

Complete the fission reaction

Expert Solution
Check Mark

Answer to Problem 50QAP

  A95235m+8n01S3890r+L57149a+4n01

Explanation of Solution

Given information:

  A95235m+x0xS3890r+L57149a+4n01

Calculation:

To calculate the no of neutrons release from the above equation. The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
  235+x=90+149+4x=8

So, 8 neutrons will be released from the above equation
Hence, the complete reaction would be
  A95235m+8n01S3890r+L57149a+4n01

To determine

(B)

Complete the fission reaction

Expert Solution
Check Mark

Answer to Problem 50QAP

  P91244a+n01Z40102r+S51131b+12n01

Explanation of Solution

Given information:

  P91244a+n01xyx+S51131b+12n01

Calculation:

The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
  244+1=x+131+12×1x=102

And, Atomic Number
  91=y+51y=40

So, Check the periodic table and find the element whose atomic number is 40
Hence, the complete reaction would be
  P91244a+n01Z40102r+S51131b+12n01

To determine

(C)

Complete the fission reaction

Expert Solution
Check Mark

Answer to Problem 50QAP

  C96250m+n01S3492e+S62153m+6n01

Explanation of Solution

Given information:

  xyx+n01S3492e+S62153m+6n01

Calculation:

The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
  x+1=92+153+6×1x=250

And, Atomic Number
  y=34+62y=96

So, Check the periodic table and find the element whose atomic number is 96.

Hence, the complete reaction would be
  C96250m+n01S3492e+S62153m+6n01

To determine

(D)

Complete the fission reaction

Expert Solution
Check Mark

Answer to Problem 50QAP

  F100262m+n01R45112h+C55142s+9n01

Explanation of Solution

Given information:

  F100262m+n01R45112h+xyx+9n01

Calculation:

The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
  262+1=112+x+9×1x=142

And, Atomic Number
  100=45+yy=55

So, Check the periodic table and find the element whose atomic number is 55.

Hence, the complete reaction would be
  F100262m+n01R45112h+C55142s+9n01

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Chapter 27 Solutions

FlipIt for College Physics (Algebra Version - Six Months Access)

Ch. 27 - Prob. 11QAPCh. 27 - Prob. 12QAPCh. 27 - Prob. 13QAPCh. 27 - Prob. 14QAPCh. 27 - Prob. 15QAPCh. 27 - Prob. 16QAPCh. 27 - Prob. 17QAPCh. 27 - Prob. 18QAPCh. 27 - Prob. 19QAPCh. 27 - Prob. 20QAPCh. 27 - Prob. 21QAPCh. 27 - Prob. 22QAPCh. 27 - Prob. 23QAPCh. 27 - Prob. 24QAPCh. 27 - Prob. 25QAPCh. 27 - Prob. 26QAPCh. 27 - Prob. 27QAPCh. 27 - Prob. 28QAPCh. 27 - Prob. 29QAPCh. 27 - Prob. 30QAPCh. 27 - Prob. 31QAPCh. 27 - Prob. 32QAPCh. 27 - Prob. 33QAPCh. 27 - Prob. 34QAPCh. 27 - Prob. 35QAPCh. 27 - Prob. 36QAPCh. 27 - Prob. 37QAPCh. 27 - Prob. 38QAPCh. 27 - Prob. 39QAPCh. 27 - Prob. 40QAPCh. 27 - Prob. 41QAPCh. 27 - Prob. 42QAPCh. 27 - Prob. 43QAPCh. 27 - Prob. 44QAPCh. 27 - Prob. 45QAPCh. 27 - Prob. 46QAPCh. 27 - Prob. 47QAPCh. 27 - Prob. 48QAPCh. 27 - Prob. 49QAPCh. 27 - Prob. 50QAPCh. 27 - Prob. 51QAPCh. 27 - Prob. 52QAPCh. 27 - Prob. 53QAPCh. 27 - Prob. 54QAPCh. 27 - Prob. 55QAPCh. 27 - Prob. 56QAPCh. 27 - Prob. 57QAPCh. 27 - Prob. 58QAPCh. 27 - Prob. 59QAPCh. 27 - Prob. 60QAPCh. 27 - Prob. 61QAPCh. 27 - Prob. 62QAPCh. 27 - Prob. 63QAPCh. 27 - Prob. 64QAPCh. 27 - Prob. 65QAPCh. 27 - Prob. 66QAPCh. 27 - Prob. 67QAPCh. 27 - Prob. 68QAPCh. 27 - Prob. 69QAPCh. 27 - Prob. 70QAPCh. 27 - Prob. 71QAPCh. 27 - Prob. 72QAPCh. 27 - Prob. 73QAPCh. 27 - Prob. 74QAPCh. 27 - Prob. 75QAPCh. 27 - Prob. 76QAPCh. 27 - Prob. 77QAPCh. 27 - Prob. 78QAPCh. 27 - Prob. 79QAPCh. 27 - Prob. 80QAPCh. 27 - Prob. 81QAPCh. 27 - Prob. 82QAPCh. 27 - Prob. 83QAPCh. 27 - Prob. 84QAPCh. 27 - Prob. 85QAPCh. 27 - Prob. 86QAPCh. 27 - Prob. 87QAPCh. 27 - Prob. 88QAPCh. 27 - Prob. 89QAPCh. 27 - Prob. 90QAPCh. 27 - Prob. 91QAPCh. 27 - Prob. 92QAPCh. 27 - Prob. 93QAPCh. 27 - Prob. 94QAPCh. 27 - Prob. 95QAPCh. 27 - Prob. 96QAPCh. 27 - Prob. 97QAP
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