Chapter 27, Problem 41QAP

To determine

(A)

Calculate the atomic mass of $H$

Answer to Problem 41QAP

The atomic mass of $H$ is $1.67\times {10}^{-24}g$

Explanation of Solution

Atomic mass:
$1.0078or1.008u$

In one gram
$\frac{1.008g}{6.023\times {10}^{23}}=1.67\times {10}^{-24}g$

To determine

(B)

Calculate the atomic mass of $He$

Answer to Problem 41QAP

The atomic mass of $He$ is $6.646\times {10}^{-24}g$

Explanation of Solution

Atomic Mass:
$4.003u$

In one gram
$\frac{4.003g}{6.023\times {10}^{23}}=6.646\times {10}^{-24}g$

To determine

(C)

Calculate the atomic mass of $Be$

Answer to Problem 41QAP

The atomic mass of $Be$ is $1.496\times {10}^{-23}g$

Explanation of Solution

Atomic Mass:
$9.012u$

In one gram
$\frac{9.012g}{6.023\times {10}^{23}}=1.496\times {10}^{-23}g$

To determine

(D)

Calculate the atomic mass of $C$

Answer to Problem 41QAP

The atomic mass of $C$ is $1.994\times {10}^{-23}g$

Explanation of Solution

Carbon − 12 99% = $12\times \frac{99}{100}$

Carbon − 13 01% = $13\times \frac{1}{100}$

Atomic Mass
$12\times 0.99+13\times 0.01=12.01u$

In one gram
$\frac{12.01g}{6.023\times {10}^{23}}=1.994\times {10}^{-23}g$

To determine

(E)

Calculate the atomic mass of $Fe$

Answer to Problem 41QAP

The atomic mass of $Fe$ is $9.27\times {10}^{-23}g$

Explanation of Solution

Atomic mass:
$55.84u$

In one gram
$\frac{55.84g}{6.023\times {10}^{23}}=9.27\times {10}^{-23}g$

To determine

(F)

Calculate the atomic mass of $Sr$

Answer to Problem 41QAP

The atomic mass of $Sr$ is $1.4547\times {10}^{-22}g$

Explanation of Solution

Atomic mass:
$87.62u$

In one gram
$\frac{87.62g}{6.023\times {10}^{23}}=1.4547\times {10}^{-22}g$

To determine

(G)

Calculate the atomic mass of $I$

Answer to Problem 41QAP

The atomic mass of $I$ is $2.10692\times {10}^{-22}g$

Explanation of Solution

Atomic mass:
$126.9u$

In one gram
$\frac{126.9g}{6.023\times {10}^{23}}=2.10692\times {10}^{-22}g$

To determine

(H)

Calculate the atomic mass of $U$

Answer to Problem 41QAP

The atomic mass of $U$ is $3.95235\times {10}^{-22}g$

Explanation of Solution

Atomic mass:
$238.050u$

In one gram
$\frac{238.050u}{6.023\times {10}^{23}}=3.95235\times {10}^{-22}g$