College Physics
10th Edition
ISBN: 9781285737027
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Chapter 27, Problem 4P
(a)
To determine
The surface temperature of the sun.
(b)
To determine
The peak wavelength for the Sun.
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Review Conceptual Example 3 and the drawing as an aid in solving this problem. A
conducting rod slides down between two frictionless vertical copper tracks at a
constant speed of 3.9 m/s perpendicular to a 0.49-T magnetic field. The resistance of th
rod and tracks is negligible. The rod maintains electrical contact with the tracks at all
times and has a length of 1.4 m. A 1.1-Q resistor is attached between the tops of the
tracks. (a) What is the mass of the rod? (b) Find the change in the gravitational potentia
energy that occurs in a time of 0.26 s. (c) Find the electrical energy dissipated in the
resistor in 0.26 s.
A camera lens used for taking close-up photographs has a focal length of 21.5 mm. The farthest it can be placed from the film is 34.0 mm.
(a) What is the closest object (in mm) that can be photographed?
58.5
mm
(b) What is the magnification of this closest object?
0.581
× ×
Given two particles with Q = 4.40-µC charges as shown in the figure below and a particle with charge q = 1.40 ✕ 10−18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = ∞.)
Three positively charged particles lie along the x-axis of the x y coordinate plane.Charge q is at the origin.Charge Q is at (0.800 m, 0).Another charge Q is at (−0.800 m, 0).(a)What is the net force (in N) exerted by the two 4.40-µC charges on the charge q? (Enter the magnitude.) N(b)What is the electric field (in N/C) at the origin due to the two 4.40-µC particles? (Enter the magnitude.) N/C(c)What is the electrical potential (in kV) at the origin due to the two 4.40-µC particles? kV(d)What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 4.40-µC particles?
Chapter 27 Solutions
College Physics
Ch. 27.5 - Prob. 27.1QQCh. 27.5 - Prob. 27.2QQCh. 27.5 - Prob. 27.3QQCh. 27.6 - Prob. 27.4QQCh. 27.6 - Prob. 27.5QQCh. 27 - Prob. 1CQCh. 27 - Prob. 2CQCh. 27 - Prob. 3CQCh. 27 - Prob. 4CQCh. 27 - Prob. 5CQ
Ch. 27 - Prob. 6CQCh. 27 - Prob. 7CQCh. 27 - Prob. 8CQCh. 27 - Prob. 9CQCh. 27 - Prob. 10CQCh. 27 - Prob. 11CQCh. 27 - Prob. 12CQCh. 27 - Prob. 13CQCh. 27 - Prob. 14CQCh. 27 - Prob. 15CQCh. 27 - Prob. 16CQCh. 27 - Prob. 1PCh. 27 - Prob. 2PCh. 27 - Prob. 3PCh. 27 - Prob. 4PCh. 27 - Prob. 5PCh. 27 - Prob. 6PCh. 27 - Prob. 7PCh. 27 - Prob. 8PCh. 27 - Prob. 9PCh. 27 - Prob. 10PCh. 27 - Prob. 11PCh. 27 - Prob. 12PCh. 27 - Prob. 13PCh. 27 - Prob. 14PCh. 27 - Prob. 15PCh. 27 - Prob. 16PCh. 27 - Prob. 17PCh. 27 - Prob. 18PCh. 27 - Prob. 19PCh. 27 - Prob. 20PCh. 27 - Prob. 21PCh. 27 - Prob. 22PCh. 27 - Prob. 23PCh. 27 - Prob. 24PCh. 27 - Prob. 25PCh. 27 - Prob. 26PCh. 27 - Prob. 27PCh. 27 - Prob. 28PCh. 27 - Prob. 29PCh. 27 - Prob. 30PCh. 27 - Prob. 31PCh. 27 - Prob. 32PCh. 27 - Prob. 33PCh. 27 - Prob. 34PCh. 27 - Prob. 35PCh. 27 - Prob. 36PCh. 27 - Prob. 37PCh. 27 - Prob. 38PCh. 27 - Prob. 39PCh. 27 - Prob. 40PCh. 27 - Prob. 41APCh. 27 - Prob. 42APCh. 27 - Prob. 43APCh. 27 - Prob. 44APCh. 27 - Prob. 45APCh. 27 - Prob. 46APCh. 27 - Prob. 47APCh. 27 - Prob. 48APCh. 27 - Prob. 49APCh. 27 - Prob. 50APCh. 27 - Prob. 51APCh. 27 - Prob. 52AP
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