(a)
Interpretation:
Draw mechanism of formation of poly(ethylene oxide) from ethylene oxide
Concept introduction:
To draw : To draw a mechanism for formation of poly(ethylene oxide)
(b)
Interpretation:
Draw mechanism of formation of poly(ethylene oxide) from ethylene oxide
Concept introduction:
Polymerization is a reaction when monomer molecules are reacted to form a polymer chain. In acidic conditions the epoxide gets protonated and then nucleophilic attack occurs in the epoxide ring opens to form an alcohol. This acts as weak nucleophile and attacks another protonated epoxide ring to extend the carbon chain forming a polymeric chain.
To draw: To draw a mechanism for formation of poly(ethylene oxide) under acidic conditions
(c)
Interpretation:
Draw mechanism of formation of poly(ethylene oxide) from ethylene oxide
Concept introduction:
Polymerization is a reaction when monomer molecules are reacted to form a polymer chain. If the formed polymer is having an ether linkage in it then the monomer must have been a epoxide.
To draw : To draw the structure of monomer required for the synthesis of given polymer.
(d)
Interpretation:
Draw mechanism of formation of poly(ethylene oxide) from ethylene oxide
To determine: To determine whether acidic or basic conditions is used to synthesize the given polymer.
Concept introduction:
Polymerization is a reaction when monomer molecules are reacted to form a polymer chain. If the formed polymer is having an ether linkage in it then the monomer must have been a epoxide.
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Chapter 27 Solutions
ORG.CHEM EBOOK W/BBWILEY PLUS>CUSTOM<
- 2H2S(g)+3O2(g)→2SO2(g)+2H2O(g) A 1.2mol sample of H2S(g) is combined with excess O2(g), and the reaction goes to completion. Question Which of the following predicts the theoretical yield of SO2(g) from the reaction? Responses 1.2 g Answer A: 1.2 grams A 41 g Answer B: 41 grams B 77 g Answer C: 77 grams C 154 g Answer D: 154 grams Darrow_forwardPart VII. Below are the 'HNMR, 13 C-NMR, COSY 2D- NMR, and HSQC 2D-NMR (similar with HETCOR but axes are reversed) spectra of an organic compound with molecular formula C6H1003 - Assign chemical shift values to the H and c atoms of the compound. Find the structure. Show complete solutions. Predicted 1H NMR Spectrum 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 f1 (ppm) Predicted 13C NMR Spectrum 100 f1 (ppm) 30 220 210 200 190 180 170 160 150 140 130 120 110 90 80 70 -26 60 50 40 46 30 20 115 10 1.0 0.9 0.8 0 -10arrow_forwardQ: Arrange BCC and Fec metals, in sequence from the Fable (Dr. R's slides) and Calculate Volume and Density. Aa BCC V 52 5 SFCCarrow_forward
- 4. Draw and label all possible isomers for [M(py)3(DMSO)2(CI)] (py = pyridine, DMSO dimethylsulfoxide).arrow_forwardThe emission data in cps displayed in Table 1 is reported to two decimal places by the chemist. However, the instrument output is shown in Table 2. Table 2. Iron emission from ICP-AES Sample Blank Standard Emission, cps 579.503252562 9308340.13122 Unknown Sample 343.232365741 Did the chemist make the correct choice in how they choose to display the data up in Table 1? Choose the best explanation from the choices below. No. Since the instrument calculates 12 digits for all values, they should all be kept and not truncated. Doing so would eliminate significant information. No. Since the instrument calculates 5 decimal places for the standard, all of the values should be limited to the same number. The other decimal places are not significant for the blank and unknown sample. Yes. The way Saman made the standards was limited by the 250-mL volumetric flask. This glassware can report values to 2 decimal places, and this establishes our number of significant figures. Yes. Instrumental data…arrow_forwardSteps and explanation pleasearrow_forward
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