The ideal battery in Fig. 27-39 a has emf ℰ = 6.0 V. Plot 1 in Fig. 27-39 b gives the electric potential difference V that can appear across resistor 1 versus the current i in that resistor when the resistor is individually tested by putting a variable potential across it. The scale of the V axis is set by V s = 18.0 V. and the scale of the i axis is set by i s = 3.00 mA. Plots 2 and 3 are similar plots for resistors 2 and 3, respectively, when they are individually tested by putting a variable potential across them. What is the current in resistor 2 in the circuit of Fig. 27-39 a ? Figure 27-39 Problem 28.
The ideal battery in Fig. 27-39 a has emf ℰ = 6.0 V. Plot 1 in Fig. 27-39 b gives the electric potential difference V that can appear across resistor 1 versus the current i in that resistor when the resistor is individually tested by putting a variable potential across it. The scale of the V axis is set by V s = 18.0 V. and the scale of the i axis is set by i s = 3.00 mA. Plots 2 and 3 are similar plots for resistors 2 and 3, respectively, when they are individually tested by putting a variable potential across them. What is the current in resistor 2 in the circuit of Fig. 27-39 a ? Figure 27-39 Problem 28.
The ideal battery in Fig. 27-39a has emf ℰ = 6.0 V. Plot 1 in Fig. 27-39b gives the electric potential difference V that can appear across resistor 1 versus the current i in that resistor when the resistor is individually tested by putting a variable potential across it. The scale of the V axis is set by Vs = 18.0 V. and the scale of the i axis is set by is = 3.00 mA. Plots 2 and 3 are similar plots for resistors 2 and 3, respectively, when they are individually tested by putting a variable potential across them. What is the current in resistor 2 in the circuit of Fig. 27-39a?
Three point-like charges in the attached image are placed at the corners of an equilateral triangle as shown in the figure. Each side of the triangle has a length of 38.0 cm, and the point (C) is located half way between q1 and q3 along the side. Find the magnitude of the electric field at point (C). Let q1 = −2.80 µC, q2 = −3.40 µC, and q3 = −4.50 µC. Thank you.
Three point-like charges are placed as shown in the attach image, where r1 = r2 = 44.0 cm. Find the magnitude of the electric force exerted on the charge q3. Let q1 = -1.90 uC, q2 = -2.60 uC, and q3 = +3.60 uC. Thank you.
The drawing attached shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Surface (1) has an area of 1.90 m², while Surface (2) has an area of 3.90 m². The electric field in magnitude of 215 N/C. Find the magnitude of the electric flux through surface (1 and 2 combined) if the angle theta made between the electric field with surface (2) is 30.0 degrees. Thank you.
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DC Series circuits explained - The basics working principle; Author: The Engineering Mindset;https://www.youtube.com/watch?v=VV6tZ3Aqfuc;License: Standard YouTube License, CC-BY