Chapter 2.7, Problem 2.7.4SR

Interpretation Introduction

Interpretation:

The mass of $\text{Hg}$ should be calculated, when it has same number of atoms as $\text{90}\text{.15}\text{g}\text{He}$.

Concept introduction:

$\begin{array}{l}\text{Avogadro’s number is 6}{\text{.022 × 10}}^{\text{23}}\\ \text{1 mole = }\text{6}{\text{.022 × 10}}^{\text{23}}\text{Avogadro’s number }\end{array}$

$\text{Number of}\text{moles }\text{=}\frac{\text{Mass}}{\text{Molar mass }}$

$\text{mol × }\frac{\text{6}{\text{.022 × 10}}^{\text{23}}\text{ atoms}}{\text{1 mol }}\text{=}\text{ atoms}$