Crossed E → and B → Fields . A particle with initial velocity v 0 → = (5.85 × 10 3 m/s) ĵ enters a region of uniform electric and magnetic fields. The magnetic field in the region is B → = − (1.35T) k ^ . Calculate the magnitude and direction of the electric field in the region if the particle is to pass through undetected, for a particle of charge (a) +0.640 nC and (b) −0.320 nC. You can ignore the weight of the particle.
Crossed E → and B → Fields . A particle with initial velocity v 0 → = (5.85 × 10 3 m/s) ĵ enters a region of uniform electric and magnetic fields. The magnetic field in the region is B → = − (1.35T) k ^ . Calculate the magnitude and direction of the electric field in the region if the particle is to pass through undetected, for a particle of charge (a) +0.640 nC and (b) −0.320 nC. You can ignore the weight of the particle.
Crossed
E
→
and
B
→
Fields. A particle with initial velocity
v
0
→
= (5.85 × 103 m/s)ĵ enters a region of uniform electric and magnetic fields. The magnetic field in the region is
B
→
= − (1.35T)
k
^
. Calculate the magnitude and direction of the electric field in the region if the particle is to pass through undetected, for a particle of charge (a) +0.640 nC and (b) −0.320 nC. You can ignore the weight of the particle.
Figure 8.14 shows a cube at rest and a small object heading toward it. (a) Describe the directions (angle 1) at which the small object can emerge after colliding elastically with the cube. How does 1 depend on b, the so-called impact parameter? Ignore any effects that might be due to rotation after the collision, and assume that the cube is much more massive than the small object. (b) Answer the same questions if the small object instead collides with a massive sphere.
2. A projectile is shot from a launcher at an angle 0,, with an initial velocity
magnitude vo, from a point even with a tabletop. The projectile hits an apple atop a
child's noggin (see Figure 1). The apple is a height y above the tabletop, and a
horizontal distance x from the launcher. Set this up as a formal problem, and solve
for x. That is, determine an expression for x in terms of only v₁, 0, y and g.
Actually, this is quite a long expression. So, if you want, you can determine an
expression for x in terms of v., 0., and time t, and determine another expression for
timet (in terms of v., 0.,y and g) that you will solve and then substitute the value of
t into the expression for x. Your final equation(s) will be called Equation 3 (and
Equation 4).
Draw a phase portrait for an oscillating, damped spring.
Chapter 27 Solutions
University Physics with Modern Physics, Volume 1 (Chs. 1-20) and Mastering Physics with Pearson eText & ValuePack Access Card (14th Edition)
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